The Shvab–Zeldovich formulation is an approach to remove the chemical-source terms from the conservation equations for energy and chemical species by linear combinations of independent variables, when the conservation equations are expressed in a common form. Expressing conservation equations in common form often limits the range of applicability of the formulation. The method was first introduced by V. A. Shvab in 1948[1] and by Yakov Zeldovich in 1949.[2]
For simplicity, assume combustion takes place in a single global irreversible reaction
N | |
\sum | |
i=1 |
\nui'\reali →
N | |
\sum | |
i=1 |
\nui''\reali
where
\reali
N
\nui'
\nui''
\omega
\omega=
wi | |
Wi(\nui''-\nui') |
where
wi
Wi
The main approximation involved in Shvab–Zeldovich formulation is that all binary diffusion coefficients
D
\alphai=Yi/[Wi(\nui''-\nui')] and \alphaT=
| ||||||||||
|
where
Yi
cp=
N | |
\sum | |
i=1 |
Yicp,i
T
0 | |
h | |
i |
\begin{align} \nabla ⋅ [\rho\boldsymbol{v}\alphai-\rhoD\nabla\alphai]=\omega,\\ \nabla ⋅ [\rho\boldsymbol{v}\alphaT-\rhoD\nabla\alphaT]=\omega \end{align}
where
\rho
\boldsymbol{v}
N+1
N
\alpha1
\nabla ⋅ [\rho\boldsymbol{v}\alpha1-\rhoD\nabla\alpha1]=\omega
then by defining the linear combinations
\betaT=\alphaT-\alpha1
\betai=\alphai-\alpha1
i ≠ 1
N
\begin{align} \nabla ⋅ [\rho\boldsymbol{v}\betai-\rhoD\nabla\betai]=0,\\ \nabla ⋅ [\rho\boldsymbol{v}\betaT-\rhoD\nabla\betaT]=0. \end{align}
The linear combinations automatically removes the nonlinear reaction term in the above
N
Shvab–Zeldovich–Liñán formulation was introduced by Amable Liñán in 1991[4] [5] for diffusion-flame problems where the chemical time scale is infinitely small (Burke–Schumann limit) so that the flame appears as a thin reaction sheet. The reactants can have Lewis number that is not necessarily equal to one.
Suppose the non-dimensional scalar equations for fuel mass fraction
YF
YO
T
\begin{align} \rho
\partialYF | |
\partialt |
+\rhov ⋅ \nablaYF&=
1 | |
LeF |
\nabla ⋅ (\rhoDT\nablaYF)-\omega,\\ \rho
\partialYO | |
\partialt |
+\rhov ⋅ \nablaYO&=
1 | |
LeO |
\nabla ⋅ (\rhoDT\nablaYO)-S\omega,\\ \rho
\partialT | |
\partialt |
+\rhov ⋅ \nablaT&=\nabla ⋅ (\rhoDT\nablaT)+q\omega \end{align}
where
\omega=DaYFYOe-E/RT
Da
S
q
e-E/RT
LeF
LeO
DT
Da → infty
YFYO=0
In this case, the reaction terms on the right-hand side become Dirac delta functions. To solve this problem, Liñán introduced the following functions
\begin{align} Z=
SYF-YO+1 | |
S+1 |
,& \tildeZ=
\tildeSYF-YO+1 | |
\tildeS+1 |
,\\ H=
T-T0 | |
Ts-T0 |
+YF+YO-1,& \tildeH=
T-T0 | |
Ts-T0 |
+
YO | |
LeO |
+
YF-1 | |
LeF |
\end{align}
where
\tildeS=SLeO/LeF
T0
Ts
\begin{align} \rho
\partialZ | |
\partialt |
+\rhov ⋅ \nablaZ&=
1 | |
Lem |
\nabla ⋅ (\rhoDT\nabla\tildeZ),\\ \rho
\partialH | |
\partialt |
+\rhov ⋅ \nablaH&=\nabla ⋅ (\rhoDT\nabla\tildeH), \end{align}
where
Lem=LeO(S+1)/(\tildeS+1)
Z
\tildeZ
H
\tildeH
At the stoichiometric surface (the flame surface), both
YF
YO
Z=Zs=1/(S+1)
\tildeZ=\tildeZs=1/(\tildeS+1)
H=Hs=(Tf-T0)/(Ts-T0)-1
\tildeH=\tildeHs=(Tf-T0)/(Ts-T0)-1/LeF
Tf
Ts
LeF=LeO=1
YF-1=YO=T-T0=0
Z-1=\tildeZ-1=H=\tildeH=0
YF=YO-1=T-1=0
Z=\tildeZ=H-(1-T0)/(Ts-T0)=\tildeH-(1-T0)/(Ts-T0)-1/LeO+1/LeF=0
The equilibrium condition defines[7]
\begin{align} \tildeZ<\tildeZs:& YF=0,YO=1-
\tildeZ | =1- | |
\tildeZs |
Z | |
Zs |
,\ \tildeZ>\tildeZs:& YO=0,YF=
\tildeZ-\tildeZs | = | |
1-\tildeZs |
Z-Zs | |
1-Zs |
. \end{align}
Z(\tildeZ)
Z=\begin{cases} \tildeZ/Lem, if\tildeZ<\tildeZs\\ Zs+Le(\tildeZ-\tildeZs)/Lem, if\tildeZ>\tildeZs \end{cases}
Lem=\tildeZs/Zs=(S+1)/(S/LeF+1)
\tildeZ
H-\tildeH
YF
YO
H(\tildeZ,\tildeH)
H=\tildeH+\begin{cases} (1/LeF-1)-(1/LeO-1)(1-\tildeZ/\tildeZs), if\tildeZ<\tildeZs\\ (1/LeF-1)(1-\tildeZ)/(1-\tildeZs), if\tildeZ>\tildeZs \end{cases}
\tildeH
It can be shown that
\tildeZ
\tildeH
Z
H