| Official Name: | Seward Township |
| Settlement Type: | Township |
| Subdivision Type: | Country |
| Subdivision Name: | United States |
| Subdivision Type1: | State |
| Subdivision Name1: | Indiana |
| Subdivision Type2: | County |
| Subdivision Name2: | Kosciusko |
| Government Type: | Indiana township |
| Area Total Sq Mi: | 36.27 |
| Area Land Sq Mi: | 34.98 |
| Area Water Sq Mi: | 1.3 |
| Population As Of: | 2020 |
| Population Footnotes: | [1] |
| Population Total: | 2280 |
| Population Density Sq Mi: | 73.4 |
| Timezone: | Eastern (EST) |
| Utc Offset: | -5 |
| Timezone Dst: | EDT |
| Utc Offset Dst: | -4 |
| Elevation Footnotes: | [2] |
| Elevation M: | 267 |
| Elevation Ft: | 876 |
| Coordinates: | 41.1081°N -85.9461°W |
| Blank Name: | FIPS code |
| Blank Info: | 18-68796[3] |
| Blank1 Name: | GNIS feature ID |
| Blank1 Info: | 453840 |
Seward Township is one of seventeen townships in Kosciusko County, Indiana, United States. As of the 2020 census, its population was 2,280 (down from 2,567 at 2010[4]) and it contained 1,357 housing units.
Seward Township was organized in 1859.[5]
According to the 2010 census, the township has a total area of, of which (or 96.44%) is land and (or 3.58%) is water.[4]