Set function explained
which consists of the
real numbers
and
A set function generally aims to subsets in some way. Measures are typical examples of "measuring" set functions. Therefore, the term "set function" is often used for avoiding confusion between the mathematical meaning of "measure" and its common language meaning.
Definitions
If
is a
family of sets over
(meaning that
where
denotes the powerset) then a is a function
with
domain
and
codomain
or, sometimes, the codomain is instead some
vector space, as with
vector measures,
complex measures, and
projection-valued measures. The domain of a set function may have any number properties; the commonly encountered properties and categories of families are listed in the table below.
In general, it is typically assumed that
is always well-defined for all
or equivalently, that
does not take on both
and
as values. This article will henceforth assume this; although alternatively, all definitions below could instead be qualified by statements such as "whenever the sum/series is defined". This is sometimes done with subtraction, such as with the following result, which holds whenever
is finitely additive:
\mu(F)-\mu(E)=\mu(F\setminusE)whenever\mu(F)-\mu(E)
is defined with
satisfying
and
Null sets
A set
is called a (with respect to
) or simply if
Whenever
is not identically equal to either
or
then it is typically also assumed that:
Variation and mass
is
where
denotes the
absolute value (or more generally, it denotes the
norm or
seminorm if
is vector-valued in a (semi)normed space). Assuming that
\cupl{F}~\stackrel{\scriptscriptstyledef
}~ \textstyle\bigcup\limits_ F \in \mathcal, then
|\mu|\left(\cupl{F}\right)
is called the of
and
is called the of
A set function is called if for every
the value
is (which by definition means that
and
; an is one that is equal to
or
). Every finite set function must have a finite mass.
Common properties of set functions
A set function
on
is said to be
- if it is valued in
- if
\mu\left(Fi\right)=
| n |
\mu\left(stylecup\limits | |
| i=1 |
Fi\right)
for all pairwise disjoint finite sequences
such that
is closed under binary unions then
is finitely additive if and only if \mu(E\cupF)=\mu(E)+\mu(F)
for all disjoint pairs
is finitely additive and if
then taking
shows that \mu(\varnothing)=\mu(\varnothing)+\mu(\varnothing)
which is only possible if
or \mu(\varnothing)=\pminfty,
where in the latter case, \mu(E)=\mu(E\cup\varnothing)=\mu(E)+\mu(\varnothing)=\mu(E)+(\pminfty)=\pminfty
for every
(so only the case
is useful). - or if in addition to being finitely additive, for all pairwise disjoint sequences
in
such that
all of the following hold:
\mu\left(Fi\right)=
| infty |
\mu\left(stylecup\limits | |
| i=1 |
Fi\right)
- The series on the left hand side is defined in the usual way as the limit
\mu\left(Fi\right)~\stackrel{\scriptscriptstyledef
}~ \mu\left(F_1\right) + \cdots + \mu\left(F_n\right).
is any permutation/bijection then
\mu\left(Fi\right)=
\mu\left(F\rho(i)\right);
this is because
and applying this condition (a) twice guarantees that both
\mu\left(Fi\right)=
| infty |
\mu\left(stylecup\limits | |
| i=1 |
Fi\right)
and | infty |
\mu\left(stylecup\limits | |
| i=1 |
F\rho(i)\right)=
\mu\left(F\rho(i)\right)
hold. By definition, a convergent series with this property is said to be unconditionally convergent. Stated in plain English, this means that rearranging/relabeling the sets
to the new order
does not affect the sum of their measures. This is desirable since just as the union F~\stackrel{\scriptscriptstyledef
}~ \textstyle\bigcup\limits_ F_i does not depend on the order of these sets, the same should be true of the sums \mu(F)=\mu\left(F1\right)+\mu\left(F2\right)+ …
and \mu(F)=\mu\left(F\rho(1)\right)+\mu\left(F\rho(2)\right)+ … .
- if
| infty |
\mu\left(stylecup\limits | |
| i=1 |
Fi\right)
is not infinite then this series
must also converge absolutely, which by definition means that
\left|\mu\left(Fi\right)\right|
must be finite. This is automatically true if
is non-negative (or even just valued in the extended real numbers).
\mu\left(Fi\right)={\displaystyle\limN
} \mu\left(F_1\right) + \mu\left(F_2\right) + \cdots + \mu\left(F_N\right) converges absolutely if and only if its sum does not depend on the order of its terms (a property known as unconditional convergence). Since unconditional convergence is guaranteed by (a) above, this condition is automatically true if
is valued in
- if
| infty |
\mu\left(stylecup\limits | |
| i=1 |
Fi\right)=
\mu\left(Fi\right)
is infinite then it is also required that the value of at least one of the series style\sum\limits\stackrel{i{\mu\left(Fi\right)>0}}\mu\left(Fi\right) and style\sum\limits\stackrel{i{\mu\left(Fi\right)<0}}\mu\left(Fi\right)
be finite (so that the sum of their values is well-defined). This is automatically true if
is non-negative.
- a if it is non-negative, countably additive (including finitely additive), and has a null empty set.
- a if it is a pre-measure whose domain is a σ-algebra. That is to say, a measure is a non-negative countably additive set function on a σ-algebra that has a null empty set.
- a if it is a measure that has a mass of
- an if it is non-negative, countably subadditive, has a null empty set, and has the power set
as its domain.
a if it is countably additive, has a null empty set, and
does not take on both
and
as values. if every subset of every null set is null; explicitly, this means: whenever F\inl{F}satisfies\mu(F)=0
and
is any subset of
then
and
- Unlike many other properties, completeness places requirements on the set
\operatorname{domain}\mu=l{F}
(and not just on
's values). if there exists a sequence
in
such that
is finite for every index
and also
} F. if there exists a subfamily
of pairwise disjoint sets such that
is finite for every
and also
} \, P = \textstyle\bigcup\limits_ F (where l{F}=\operatorname{domain}\mu
).- Every -finite set function is decomposable although not conversely. For example, the counting measure on
(whose domain is
) is decomposable but not -finite.a if it is a countably additive set function
valued in a topological vector space
(such as a normed space) whose domain is a σ-algebra.
is valued in a normed space
then it is countably additive if and only if for any pairwise disjoint sequence
in
\limn\left\|\mu\left(F1\right)+ … +\mu\left(Fn\right)-
| infty |
\mu\left(stylecup\limits | |
| i=1 |
Fi\right)\right\|=0.
If
is finitely additive and valued in a Banach space then it is countably additive if and only if for any pairwise disjoint sequence
in
\limn\left\|\mu\left(Fn\cupFn+1\cupFn+2\cup … \right)\right\|=0.
a if it is a countably additive complex-valued set function
whose domain is a σ-algebra.- By definition, a complex measure never takes
as a value and so has a null empty set.a if it is a measure-valued random element.Arbitrary sums
As described in this article's section on generalized series, for any family
of
real numbers indexed by an arbitrary indexing set
it is possible to define their sum
as the limit of the
net of finite partial sums
F\in\operatorname{FiniteSubsets}(I)\mapstostyle\sum\limitsiri
where the domain
\operatorname{FiniteSubsets}(I)
is
directed by
Whenever this net converges then its limit is denoted by the symbols
while if this net instead diverges to
then this may be indicated by writing
style\sum\limitsiri=\pminfty.
Any sum over the empty set is defined to be zero; that is, if
then
by definition.
For example, if
for every
then
And it can be shown that
style\sum\limitsiri=style\sum\limits\stackrel{i{ri=0}}ri+style\sum\limits\stackrel{i{ri ≠ 0}}ri=0+style\sum\limits\stackrel{i{ri ≠ 0}}ri=style\sum\limits\stackrel{i{ri ≠ 0}}ri.
If
then the generalized series
converges in
if and only if
converges unconditionally (or equivalently,
converges absolutely) in the usual sense. If a generalized series
converges in
then both
style\sum\limits\stackrel{i{ri>0}}ri
and
style\sum\limits\stackrel{i{ri<0}}ri
also converge to elements of
and the set
\left\{i\inI:ri ≠ 0\right\}
is necessarily
countable (that is, either finite or countably infinite); this remains true if
is replaced with any normed space. It follows that in order for a generalized series
to converge in
or
it is necessary that all but at most countably many
will be equal to
which means that
style\sum\limitsiri~=~style\sum\limits\stackrel{i{ri ≠ 0}}ri
is a sum of at most countably many non-zero terms. Said differently, if
\left\{i\inI:ri ≠ 0\right\}
is uncountable then the generalized series
does not converge.
In summary, due to the nature of the real numbers and its topology, every generalized series of real numbers (indexed by an arbitrary set) that converges can be reduced to an ordinary absolutely convergent series of countably many real numbers. So in the context of measure theory, there is little benefit gained by considering uncountably many sets and generalized series. In particular, this is why the definition of "countably additive" is rarely extended from countably many sets
in
(and the usual countable series
) to arbitrarily many sets
(and the generalized series
style\sum\limitsi\mu\left(Fi\right)
).
Inner measures, outer measures, and other properties
A set function
is said to be/satisfies
- if
whenever
satisfy
- if it satisfies the following condition, known as :
\mu(E\cupF)+\mu(E\capF)=\mu(E)+\mu(F)
for all
such that
if
\mu(E\cupF)+\mu(E\capF)\leq\mu(E)+\mu(F)
for all
such that
if |\mu(F)|\leq
\left|\mu\left(Fi\right)\right|
for all finite sequences
that satisfy
or if |\mu(F)|\leq
\left|\mu\left(Fi\right)\right|
for all sequences
in
that satisfy
is closed under finite unions then this condition holds if and only if |\mu(F\cupG)|\leq|\mu(F)|+|\mu(G)|
for all
If
is non-negative then the absolute values may be removed.
is a measure then this condition holds if and only if | infty |
\mu\left(stylecup\limits | |
| i=1 |
Fi\right)\leq
\mu\left(Fi\right)
for all
in
If
is a probability measure then this inequality is Boole's inequality.
is countably subadditive and
with
then
is finitely subadditive. if \mu(E)+\mu(F)\leq\mu(E\cupF)
whenever
are disjoint with
if \limn\mu\left(Fi\right)=
| infty |
\mu\left(stylecap\limits | |
| i=1 |
Fi\right)
for all of sets F1\supseteqF2\supseteqF3 …
in
such that
with | infty |
\mu\left(stylecap\limits | |
| i=1 |
Fi\right)
and all
finite.
is continuous from above but it would not be if the assumption that all
are eventually finite was omitted from the definition, as this example shows: For every integer
let
be the open interval
so that \limnλ\left(Fi\right)=\limninfty=infty ≠ 0=λ(\varnothing)=
| infty |
λ\left(stylecap\limits | |
| i=1 |
Fi\right)
where
if \limn\mu\left(Fi\right)=
| infty |
\mu\left(stylecup\limits | |
| i=1 |
Fi\right)
for all of sets F1\subseteqF2\subseteqF3 …
in
such that
if whenever
satisfies
then for every real
there exists some
such that
and r\leq\mu\left(Fr\right)<infty.
an if
is non-negative, countably subadditive, has a null empty set, and has the power set
as its domain.an if
is non-negative, superadditive, continuous from above, has a null empty set, has the power set
as its domain, and
is approached from below.if every measurable set of positive measure contains an atom.
is defined, then a set function
is said to be
Topology related definitions
If
is a topology on
then a set function
is said to be:
- a if it is a measure defined on the σ-algebra of all Borel sets, which is the smallest σ-algebra containing all open subsets (that is, containing
).
- a if it is a measure defined on the σ-algebra of all Baire sets.
- if for every point
there exists some neighborhood
of this point such that
is finite.
is a finitely additive, monotone, and locally finite then
is necessarily finite for every compact measurable subset
- if
\mu\left({stylecup}l{D}\right)=\supD
} \mu(D) whenever l{D}\subseteq\tau\capl{F}
is directed with respect to
and satisfies {stylecup}l{D}~\stackrel{\scriptscriptstyledef
}~ \textstyle\bigcup\limits_ D \in \mathcal.
is directed with respect to
if and only if it is not empty and for all
there exists some
such that
and
- or if for every
\mu(F)=\sup\{\mu(K):F\supseteqKwithK\inl{F}acompactsubsetof(\Omega,\tau)\}.
- if for every
\mu(F)=inf\{\mu(U):F\subseteqUandU\inl{F}\cap\tau\}.
- if it is both inner regular and outer regular.
- a if it is a Borel measure that is also .
- a if it is a regular and locally finite measure.
- if every non-empty open subset has (strictly) positive measure.
- a if it is non-negative, monotone, modular, has a null empty set, and has domain
Relationships between set functions
See also: Radon–Nikodym theorem and Lebesgue's decomposition theorem.
If
and
are two set functions over
then:
-
is said to be or, written
if for every set
that belongs to the domain of both
and
if
then
and
are
-finite measures on the same measurable space and if
then the Radon–Nikodym derivative
exists and for every measurable
and
are called if each one is absolutely continuous with respect to the other.
is called a of a measure
if
is
-finite and they are equivalent.[1] -
and
are , written
if there exist disjoint sets
and
in the domains of
and
such that
for all
in the domain of
and
for all
in the domain of
Examples
Examples of set functions include:
- The function
, assigning
densities to sufficiently well-behaved subsets
A\subseteq\{1,2,3,\ldots\},
is a set function.
with other sets given probabilities between
and
The Jordan measure on
is a set function defined on the set of all Jordan measurable subsets of
it sends a Jordan measurable set to its Jordan measure.
Lebesgue measure
The Lebesgue measure on
is a set function that assigns a non-negative real number to every set of real numbers that belongs to the Lebesgue
-algebra.
[2] Its definition begins with the set
\operatorname{Intervals}(\Reals)
of all intervals of real numbers, which is a semialgebra on
The function that assigns to every interval
its
is a finitely additive set function (explicitly, if
has endpoints
then
\operatorname{length}(I)=b-a
). This set function can be extended to the Lebesgue outer measure on
which is the translation-invariant set function
λ*:\wp(\Reals)\to[0,infty]
that sends a subset
to the infimum
Lebesgue outer measure is not countably additive (and so is not a measure) although its restriction to the -algebra of all subsets
that satisfy the
Carathéodory criterion:
is a measure that called
Lebesgue measure.
Vitali sets are examples of
non-measurable sets of real numbers.
Infinite-dimensional space
See also: Abstract Wiener space, Feldman–Hájek theorem and Radonifying function.
As detailed in the article on infinite-dimensional Lebesgue measure, the only locally finite and translation-invariant Borel measure on an infinite-dimensional separable normed space is the trivial measure. However, it is possible to define Gaussian measures on infinite-dimensional topological vector spaces. The structure theorem for Gaussian measures shows that the abstract Wiener space construction is essentially the only way to obtain a strictly positive Gaussian measure on a separable Banach space.
Finitely additive translation-invariant set functions
The only translation-invariant measure on
with domain
that is finite on every compact subset of
is the trivial set function
that is identically equal to
(that is, it sends every
to
)However, if countable additivity is weakened to finite additivity then a non-trivial set function with these properties does exist and moreover, some are even valued in
In fact, such non-trivial set functions will exist even if
is replaced by any other
abelian group
Extending set functions
See also: Carathéodory's extension theorem.
Extending from semialgebras to algebras
Suppose that
is a set function on a semialgebra
over
and let
which is the
algebra on
generated by
The archetypal example of a semialgebra that is not also an
algebra is the family
on
where
(a,b]:=\{x\in\R:a<x\leqb\}
for all
Importantly, the two non-strict inequalities
in
cannot be replaced with strict inequalities
since semialgebras must contain the whole underlying set
that is,
is a requirement of semialgebras (as is
).
If
is finitely additive then it has a unique extension to a set function
on
\operatorname{algebra}(l{F})
defined by sending
F1\sqcup … \sqcupFn\in\operatorname{algebra}(l{F})
(where
indicates that these
are pairwise disjoint) to:
This extension
will also be finitely additive: for any pairwise disjoint
A1,\ldots,An\in\operatorname{algebra}(l{F}),
If in addition
is extended real-valued and monotone (which, in particular, will be the case if
is non-negative) then
will be monotone and finitely subadditive: for any
A,A1,\ldots,An\in\operatorname{algebra}(l{F})
such that
A\subseteqA1\cup … \cupAn,
Extending from rings to σ-algebras
See also: Pre-measure.
If
is a pre-measure on a
ring of sets (such as an
algebra of sets)
over
then
has an extension to a measure
\overline{\mu}:\sigma(l{F})\to[0,infty]
on the
σ-algebra
generated by
If
is σ-finite then this extension is unique.
To define this extension, first extend
to an
outer measure
on
by
and then restrict it to the set
of
-measurable sets (that is, Carathéodory-measurable sets), which is the set of all
such that
It is a
-algebra and
is sigma-additive on it, by Caratheodory lemma.
Restricting outer measures
If
\mu*:\wp(\Omega)\to[0,infty]
is an outer measure on a set
where (by definition) the domain is necessarily the
power set
of
then a subset
is called
or
if it satisfies the following :
where
is the
complement of
The family of all
–measurable subsets is a
σ-algebra and the
restriction of the outer measure
to this family is a
measure.
Notes
Proofs
References
- A. N. Kolmogorov and S. V. Fomin (1975), Introductory Real Analysis, Dover.
Further reading
Notes and References
- Book: Kallenberg . Olav . Olav Kallenberg . 2017 . Random Measures, Theory and Applications. Probability Theory and Stochastic Modelling . 77 . Switzerland . Springer . 10.1007/978-3-319-41598-7. 978-3-319-41596-3. 21.
- Kolmogorov and Fomin 1975