Serre's inequality on height explained

In algebra, specifically in the theory of commutative rings, Serre's inequality on height states: given a (Noetherian) regular ring A and a pair of prime ideals

ak{p},ak{q}

in it, for each prime ideal

akr

that is a minimal prime ideal over the sum

akp+akq

, the following inequality on heights holds:

\operatorname{ht}(akr)\le\operatorname{ht}(akp)+\operatorname{ht}(akq).

Without the assumption on regularity, the inequality can fail; see scheme-theoretic intersection#Proper intersection.

Sketch of Proof

Serre gives the following proof of the inequality, based on the validity of Serre's multiplicity conjectures for formal power series ring over a complete discrete valuation ring.

By replacing

A

by the localization at

akr

, we assume

(A,akr)

is a local ring. Then the inequality is equivalent to the following inequality: for finite

A

-modules

M,N

such that

MAN

has finite length,

\dimAM+\dimAN\le\dimA

where

\dimAM=\dim(A/\operatorname{Ann}A(M))

= the dimension of the support of

M

and similar for

\dimAN

. To show the above inequality, we can assume

A

is complete. Then by Cohen's structure theorem, we can write

A=A1/a1A1

where

A1

is a formal power series ring over a complete discrete valuation ring and

a1

is a nonzero element in

A1

. Now, an argument with the Tor spectral sequence shows that
A1
\chi

(M,N)=0

. Then one of Serre's conjectures says
\dim
A1

M+

\dim
A1

N<\dimA1

, which in turn gives the asserted inequality.

\square

References