In mathematics, Schur's inequality, named after Issai Schur,establishes that for all non-negative real numbersx, y, z, and t>0,
xt(x-y)(x-z)+yt(y-z)(y-x)+zt(z-x)(z-y)\ge0
with equality if and only if x = y = z or two of them are equal and the other is zero. When t is an even positive integer, the inequality holds for all real numbers x, y and z.
When
t=1
x3+y3+z3+3xyz\geqxy(x+y)+xz(x+z)+yz(y+z)
Since the inequality is symmetric in
x,y,z
x\geqy\geqz
(x-y)[xt(x-z)-yt(y-z)]+zt(x-z)(y-z)\geq0
clearly holds, since every term on the left-hand side of the inequality is non-negative. This rearranges to Schur's inequality.
A generalization of Schur's inequality is the following:Suppose a,b,c are positive real numbers. If the triples (a,b,c) and (x,y,z) are similarly sorted, then the following inequality holds:
a(x-y)(x-z)+b(y-z)(y-x)+c(z-x)(z-y)\ge0.
In 2007, Romanian mathematician Valentin Vornicu showed that a yet further generalized form of Schur's inequality holds:
Consider
a,b,c,x,y,z\inR
a\geqb\geqc
x\geqy\geqz
z\geqy\geqx
k\inZ+
f:R →
+ | |
R | |
0 |
{f(x)(a-b)k(a-c)k+f(y)(b-a)k(b-c)k+f(z)(c-a)k(c-b)k\geq0}.
Another possible extension states that if the non-negative real numbers
x\geqy\geqz\geqv
xt(x-y)(x-z)(x-v)+yt(y-x)(y-z)(y-v)+zt(z-x)(z-y)(z-v)+vt(v-x)(v-y)(v-z)\ge0.