Samarium(III) bromide explained

Samarium(III) bromide is a crystalline compound of one samarium and three bromine atoms with the chemical formula of SmBr3. Samarium(III) bromide is a dark brown powder at room temperature.[1] The compound has a crystal structure isotypic to that of plutonium(III) bromide.[2] [3]

Preparation

SmBr3·6H2O can be crystallized by dissolving samarium oxide in 40% hydrobromic acid. The hydrate and ammonium bromide are heated in a vacuum to obtain the anhydrous form of samarium(III) bromide.[4]

Other compounds

Samarium(III) bromide forms some compounds with hydrazine, such as SmBr3·3N2H4·H2O which is a pale yellow needle-shaped crystal that is soluble in water and ethanol but insoluble in benzene, with d20 °C = 3.147 g/cm3.[5]

Notes and References

  1. Web site: Elements. American. Samarium(III) Bromide Hexahydrate. American Elements. 21 December 2016.
  2. Book: Christoph Janiak, Hans-Jürgen Meyer, Dietrich Gudat, Ralf Alsfasser . Riedel Moderne Anorganische Chemie . Walter de Gruyter . 978-3-11-024901-9 . 2012 .
  3. Book: A. F. . Wells . Structural Inorganic Chemistry . 5th . 1984 . Oxford University Press . 978-0-19-965763-6 . 421 .
  4. 林平娣, 吴国庆. 无水三溴化钐和三溴化镱的制备 [J]. 化学试剂, 1991(1):13-14.
  5. https://books.google.com/books?id=GJ04AAAAIAAJ Uchenye zapiski: Serii︠a︡ khimicheskikh nauk