Roseville, Iowa | |
Settlement Type: | Census-designated place |
Pushpin Map: | Iowa |
Pushpin Label: | Roseville |
Pushpin Map Caption: | Location in Iowa |
Subdivision Type: | Country |
Subdivision Name: | United States |
Subdivision Type1: | State |
Subdivision Name1: | Iowa |
Subdivision Type2: | County |
Subdivision Name2: | Floyd |
Subdivision Type3: | Township |
Subdivision Name3: | Ulster and Union |
Unit Pref: | Imperial |
Area Footnotes: | [1] |
Area Total Km2: | 9.56 |
Area Land Km2: | 9.56 |
Area Water Km2: | 0.00 |
Population As Of: | 2020 |
Population Total: | 39 |
Population Density Km2: | 4.08 |
Timezone: | Central (CST) |
Coordinates: | 43.01°N -92.8119°W |
Postal Code Type: | ZIP code |
Blank Name: | FIPS code |
Blank Info: | 19-68800 |
Area Total Sq Mi: | 3.69 |
Area Land Sq Mi: | 3.69 |
Area Water Sq Mi: | 0.00 |
Population Density Sq Mi: | 10.56 |
Roseville is a census-designated place[2] mainly located in Ulster Township and a small portion in the northern part of Union Township in Floyd County in the state of Iowa. As of the 2010 census the population was 49.[3]
Its location is approximately 6miles northeast of the city of Marble Rock or 11miles southwest of the city of Charles City, along Iowa Highway 14.