Roseville, Iowa Explained

Roseville, Iowa
Settlement Type:Census-designated place
Pushpin Map:Iowa
Pushpin Label:Roseville
Pushpin Map Caption:Location in Iowa
Subdivision Type:Country
Subdivision Name:United States
Subdivision Type1:State
Subdivision Name1:Iowa
Subdivision Type2:County
Subdivision Name2:Floyd
Subdivision Type3:Township
Subdivision Name3:Ulster and Union
Unit Pref:Imperial
Area Footnotes:[1]
Area Total Km2:9.56
Area Land Km2:9.56
Area Water Km2:0.00
Population As Of:2020
Population Total:39
Population Density Km2:4.08
Timezone:Central (CST)
Coordinates:43.01°N -92.8119°W
Postal Code Type:ZIP code
Blank Name:FIPS code
Blank Info:19-68800
Area Total Sq Mi:3.69
Area Land Sq Mi:3.69
Area Water Sq Mi:0.00
Population Density Sq Mi:10.56

Roseville is a census-designated place[2] mainly located in Ulster Township and a small portion in the northern part of Union Township in Floyd County in the state of Iowa. As of the 2010 census the population was 49.[3]

Its location is approximately 6miles northeast of the city of Marble Rock or 11miles southwest of the city of Charles City, along Iowa Highway 14.

References

  1. Web site: 2020 U.S. Gazetteer Files. United States Census Bureau. March 16, 2022.
  2. https://www.census.gov/2010census/popmap/ipmtext.php?fl=1968800
  3. Web site: Decennial Census of Population and Housing by Decades .