A right triangle or right-angled triangle, sometimes called an orthogonal triangle or rectangular triangle, is a triangle in which two sides are perpendicular, forming a right angle (turn or 90 degrees).
The side opposite to the right angle is called the hypotenuse (side
c
a
B
A,
b
A
B.
Every right triangle is half of a rectangle which has been divided along its diagonal. When the rectangle is a square, its right-triangular half is isosceles, with two congruent sides and two congruent angles. When the rectangle is not a square, its right-triangular half is scalene.
Every triangle whose base is the diameter of a circle and whose apex lies on the circle is a right triangle, with the right angle at the apex and the hypotenuse as the base; conversely, the circumcircle of any right triangle has the hypotenuse as its diameter. This is Thales' theorem.
The legs and hypotenuse of a right triangle satisfy the Pythagorean theorem: the sum of the areas of the squares on two legs is the area of the square on the hypotenuse,
a2+b2=c2.
The relations between the sides and angles of a right triangle provides one way of defining and understanding trigonometry, the study of the metrical relationships between lengths and angles.
See main article: Pythagorean theorem.
The three sides of a right triangle are related by the Pythagorean theorem, which in modern algebraic notation can be written
a2+b2=c2,
where
c
a
b
a,b,c
As with any triangle, the area is equal to one half the base multiplied by the corresponding height. In a right triangle, if one leg is taken as the base then the other is height, so the area of a right triangle is one half the product of the two legs. As a formula the area
T
T=\tfrac{1}{2}ab
where
a
b
If the incircle is tangent to the hypotenuse
AB
P,
s=\tfrac12(a+b+c),
|PA|=s-a
|PB|=s-b,
T=|PA| ⋅ |PB|=(s-a)(s-b).
This formula only applies to right triangles.[1]
If an altitude is drawn from the vertex with the right angle to the hypotenuse then the triangle is divided into two smaller triangles which are both similar to the original and therefore similar to each other. From this:
In equations,
f2=de,
b2=ce,
a2=cd
where
a,b,c,d,e,f
f= | ab |
c |
.
Moreover, the altitude to the hypotenuse is related to the legs of the right triangle by[3] [4]
1 | |
a2 |
+
1 | |
b2 |
=
1 | |
f2 |
.
For solutions of this equation in integer values of
a,b,c,f,
The altitude from either leg coincides with the other leg. Since these intersect at the right-angled vertex, the right triangle's orthocenter—the intersection of its three altitudes—coincides with the right-angled vertex.
The radius of the incircle of a right triangle with legs
a
b
c
r=
a+b-c | |
2 |
=
ab | |
a+b+c |
.
The radius of the circumcircle is half the length of the hypotenuse,
R=
c | |
2 |
.
Thus the sum of the circumradius and the inradius is half the sum of the legs:[5]
R+r=
a+b | |
2 |
.
One of the legs can be expressed in terms of the inradius and the other leg as
a= | 2r(b-r) |
b-2r |
.
A triangle
\triangleABC
a\leb<c
T,
hc
R,
r,
ra,rb,rc
a,b,c
ma,mb,mc
a2+b2=c2 (Pythagoreantheorem)
(s-a)(s-b)=s(s-c)
s=2R+r.
a2+b2+c2=8R2.
A
B
\cos{A}\cos{B}\cos{C}=0.
\sin2{A}+\sin2{B}+\sin2{C}=2.
\cos2{A}+\cos2{B}+\cos2{C}=1.
\sin{2A}=\sin{2B}=2\sin{A}\sin{B}.
T= | ab |
2 |
T=rarb=rrc
T=r(2R+r)
T= | (2s-c)2-c2 |
4 |
=s(s-c)
T=|PA| ⋅ |PB|,
P
AB.
r=s-c=(a+b-c)/2
ra=s-b=(a-b+c)/2
rb=s-a=(-a+b+c)/2
rc=s=(a+b+c)/2
ra+rb+rc+r=a+b+c
2+r | |
r | |
c |
2=a2+b2+c2
r= | rarb |
rc |
.
h | ||||
|
2=6R | |
m | |
c |
2.
(c=2R).
\sqrt{2}r
The trigonometric functions for acute angles can be defined as ratios of the sides of a right triangle. For a given angle, a right triangle may be constructed with this angle, and the sides labeled opposite, adjacent and hypotenuse with reference to this angle according to the definitions above. These ratios of the sides do not depend on the particular right triangle chosen, but only on the given angle, since all triangles constructed this way are similar. If, for a given angle α, the opposite side, adjacent side and hypotenuse are labeled
O,
A,
H,
\sin\alpha=
O | |
H |
,\cos\alpha=
A | |
H |
,\tan\alpha=
O | |
A |
,\sec\alpha=
H | |
A |
,\cot\alpha=
A | |
O |
,\csc\alpha=
H | |
O |
.
For the expression of hyperbolic functions as ratio of the sides of a right triangle, see the hyperbolic triangle of a hyperbolic sector.
See main article: Special right triangles.
The values of the trigonometric functions can be evaluated exactly for certain angles using right triangles with special angles. These include the 30-60-90 triangle which can be used to evaluate the trigonometric functions for any multiple of
\tfrac16\pi,
\tfrac14\pi.
Let
H,
G,
A
a
b
a>b.
H
G
A,
A | |
H |
=
A2 | |
G2 |
=
G2 | |
H2 |
=\phi,
a | |
b |
=\phi3,
where
\phi=\tfrac12l(1+\sqrt{5}r)
See main article: Thales' theorem. Thales' theorem states that if
BC
A
\triangleABC
A.
The following formulas hold for the medians of a right triangle:
2 | |
m | |
a |
+
2 | |
m | |
b |
=
2 | |
5m | |
c |
=
5 | |
4 |
c2.
The median on the hypotenuse of a right triangle divides the triangle into two isosceles triangles, because the median equals one-half the hypotenuse.
The medians
ma
mb
4c4+9a2b
2. | |
b |
In a right triangle, the Euler line contains the median on the hypotenuse—that is, it goes through both the right-angled vertex and the midpoint of the side opposite that vertex. This is because the right triangle's orthocenter, the intersection of its altitudes, falls on the right-angled vertex while its circumcenter, the intersection of its perpendicular bisectors of sides, falls on the midpoint of the hypotenuse.
In any right triangle the diameter of the incircle is less than half the hypotenuse, and more strongly it is less than or equal to the hypotenuse times
(\sqrt{2}-1).
In a right triangle with legs
a,b
c,
c\geq
\sqrt{2 | |
with equality only in the isosceles case.[12]
If the altitude from the hypotenuse is denoted
hc,
hc\leq
\sqrt{2 | |
with equality only in the isosceles case.[12]
If segments of lengths
p
q
C
\tfrac13c,
p2+q2=5\left(
c | |
3 |
\right)2.
The right triangle is the only triangle having two, rather than one or three, distinct inscribed squares.[14]
Given any two positive numbers
h
k
h>k.
h
k
c.
1 | |
c2 |
+
1 | |
h2 |
=
1 | |
k2 |
.
These sides and the incircle radius
r
1 | =-{ | |
r |
1 | |
c |
The perimeter of a right triangle equals the sum of the radii of the incircle and the three excircles:
a+b+c=r+ra+rb+rc.
a-2+b-2=d-2