Riesz potential explained

In mathematics, the Riesz potential is a potential named after its discoverer, the Hungarian mathematician Marcel Riesz. In a sense, the Riesz potential defines an inverse for a power of the Laplace operator on Euclidean space. They generalize to several variables the Riemann–Liouville integrals of one variable.

Definition

If 0 < α < n, then the Riesz potential Iαf of a locally integrable function f on Rn is the function defined by

where the constant is given by

c\alpha=\pin/2

\alpha\Gamma(\alpha/2)
\Gamma((n-\alpha)/2)
2

.

This singular integral is well-defined provided f decays sufficiently rapidly at infinity, specifically if f ∈ Lp(Rn) with 1 ≤ p < n/α. In fact, for any 1 ≤ p (p>1 is classical, due to Sobolev, while for p=1 see, the rate of decay of f and that of Iαf are related in the form of an inequality (the Hardy–Littlewood–Sobolev inequality)

\|I\alpha

f\|
p*

\leCp\|Rf\|p,

*=np
n-\alphap
p

,

where

Rf=DI1f

is the vector-valued Riesz transform. More generally, the operators Iα are well-defined for complex α such that .

The Riesz potential can be defined more generally in a weak sense as the convolution

I\alphaf=f*K\alpha

where Kα is the locally integrable function:

K\alpha(x)=

1
c\alpha
1
|x|n-\alpha

.

The Riesz potential can therefore be defined whenever f is a compactly supported distribution. In this connection, the Riesz potential of a positive Borel measure μ with compact support is chiefly of interest in potential theory because Iαμ is then a (continuous) subharmonic function off the support of μ, and is lower semicontinuous on all of Rn.

Consideration of the Fourier transform reveals that the Riesz potential is a Fourier multiplier.[1] In fact, one has

\widehat{K\alpha}(\xi)=

\int
\Rn

K\alpha(x)e-2\pidx=|2\pi\xi|-\alpha

and so, by the convolution theorem,

\widehat{I\alphaf}(\xi)=|2\pi\xi|-\alpha\hat{f}(\xi).

The Riesz potentials satisfy the following semigroup property on, for instance, rapidly decreasing continuous functions

I\alphaI\beta=I\alpha+\beta

provided

0<\operatorname{Re}\alpha,\operatorname{Re}\beta<n,0<\operatorname{Re}(\alpha+\beta)<n.

Furthermore, if, then

\DeltaI\alpha+2=I\alpha+2\Delta=-I\alpha.

One also has, for this class of functions,
\lim
\alpha\to0+

(I\alphaf)(x)=f(x).

See also

References

Notes and References

  1. .