See also: signal reflection. A signal travelling along an electrical transmission line will be partly, or wholly, reflected back in the opposite direction when the travelling signal encounters a discontinuity in the characteristic impedance of the line, or if the far end of the line is not terminated in its characteristic impedance. This can happen, for instance, if two lengths of dissimilar transmission lines are joined.
This article is about signal reflections on electrically conducting lines. Such lines are loosely referred to as copper lines, and indeed, in telecommunications are generally made from copper, but other metals are used, notably aluminium in power lines. Although this article is limited to describing reflections on conducting lines, this is essentially the same phenomenon as optical reflections in fibre-optic lines and microwave reflections in waveguides.
Reflections cause several undesirable effects, including modifying frequency responses, causing overload power in transmitters and overvoltages on power lines. However, the reflection phenomenon can be useful in such devices as stubs and impedance transformers. The special cases of open circuit and short circuit lines are of particular relevance to stubs.
Reflections cause standing waves to be set up on the line. Conversely, standing waves are an indication that reflections are present. There is a relationship between the measures of reflection coefficient and standing wave ratio.
There are several approaches to understanding reflections, but the relationship of reflections to the conservation laws is particularly enlightening. A simple example is a step voltage, (where is the height of the step and is the unit step function with time ), applied to one end of a lossless line, and consider what happens when the line is terminated in various ways. The step will be propagated down the line according to the telegrapher's equation at some velocity
\kappa
vi
x
vi=Vu(\kappat-x)
The incident current,
ii
Z0
ii=
vi | |
Z0 |
=Iu(\kappat-x)
The incident wave travelling down the line is not affected in any way by the open circuit at the end of the line. It cannot have any effect until the step actually reaches that point. The signal cannot have any foreknowledge of what is at the end of the line and is only affected by the local characteristics of the line. However, if the line is of length
\ell
t=\ell/\kappa
ir
ir=
vr | |
Z0 |
there must also be a reflected voltage,
vr
viii
vr=vi
These two voltages will add to each other so that after the step has been reflected, twice the incident voltage appears across the output terminals of the line. As the reflection proceeds back up the line the reflected voltage continues to add to the incident voltage and the reflected current continues to subtract from the incident current. After a further interval of
t=\ell/\kappa
Z0
Z0
V
Z0
However, if the generator is left open circuit, a voltage of
2V
Z0
V
2V
The reflection from a short-circuited line can be described in similar terms to that from an open-circuited line. Just as in the open circuit case where the current must be zero at the end of the line, in the short circuit case the voltage must be zero since there can be no volts across a short circuit. Again, all of the energy must be reflected back up the line and the reflected voltage must be equal and opposite to the incident voltage by Kirchhoff's voltage law:
vr=-vi
ir=-ii
As the reflection travels back up the line, the two voltages subtract and cancel, while the currents will add (the reflection is double negative - a negative current traveling in the reverse direction), the dual situation to the open circuit case.[2]
For the general case of a line terminated in some arbitrary impedance it is usual to describe the signal as a wave traveling down the line and analyse it in the frequency domain. The impedance is consequently represented as a frequency dependant complex function.
For a line terminated in its own characteristic impedance there is no reflection. By definition, terminating in the characteristic impedance has the same effect as an infinitely long line. Any other impedance will result in a reflection. The magnitude of the reflection will be smaller than the magnitude of the incident wave if the terminating impedance is wholly or partly resistive since some of the energy of the incident wave will be absorbed in the resistance. The voltage (
Vo
ZL
Vo=2Vi
ZL | |
Z0+ZL |
The reflection,
Vr
Vi+Vr=Vo
Vr=Vo-Vi=2Vi
ZL | |
Z0+ZL |
-Vi=Vi
ZL-Z0 | |
ZL+Z0 |
The reflection coefficient,
\Gamma
\Gamma=
Vr | |
Vi |
and substituting in the expression for
Vr
\Gamma=
Vr | |
Vi |
=
Ir | |
Ii |
=
ZL-Z0 | |
ZL+Z0 |
In general
\Gamma
\left|\Gamma\right|\le1
\operatorname{Re}(ZL),\operatorname{Re}(Z0)>0
The physical interpretation of this is that the reflection cannot be greater than the incident wave when only passive elements are involved (but see negative resistance amplifier for an example where this condition does not hold).[4] For the special cases described above,
Termination | \Gamma | ||
---|---|---|---|
Open circuit | \Gamma=+1 | ||
Short circuit | \Gamma=-1 | ||
ZL=RL Z0=R0\ | \operatorname{Re}(\Gamma)<1 \operatorname{Im}(\Gamma)=0 |
When both
Z0
ZL
\Gamma
\Gamma
See also: Reflection phase change.
Another special case occurs when
Z0
R0
ZL
jXL
\Gamma=
jXL-R0 | |
jXL+R0 |
Since
|jXL-R0|=|jXL+R0|
then
|\Gamma|=1
showing that all the incident wave is reflected, and none of it is absorbed in the termination, as is to be expected from a pure reactance. There is, however, a change of phase,
\theta
\theta= \begin{cases} \pi-2\arctan
XL | |
R0 |
&if{XL}>0\\ -\pi-2\arctan
XL | |
R0 |
&if{XL}<0\\ \end{cases}
A discontinuity, or mismatch, somewhere along the length of the line results in part of the incident wave being reflected and part being transmitted onward in the second section of line as shown in figure 5. The reflection coefficient in this case is given by
\Gamma=
Z02-Z01 | |
Z02+Z01 |
In a similar manner, a transmission coefficient,
T
Vt
T=
Vt | |
Vi |
=
2Z02 | |
Z02+Z01 |
ZL
\Gamma=
-Z0 | |
Z0+2ZL |
T=
2ZL | |
Z0+2ZL |
Similar expressions can be developed for a series element, or any electrical network for that matter.[6]
Reflections in more complex scenarios, such as found on a network of cables, can result in very complicated and long lasting waveforms on the cable. Even a simple overvoltage pulse entering a cable system as uncomplicated as the power wiring found in a typical private home can result in an oscillatory disturbance as the pulse is reflected to and from multiple circuit ends. These ring waves as they are known[7] persist for far longer than the original pulse and their waveforms bears little obvious resemblance to the original disturbance, containing high frequency components in the tens of MHz range.[8]
For a transmission line carrying sinusoidal waves, the phase of the reflected wave is continually changing with distance, with respect to the incident wave, as it proceeds back down the line. Because of this continuous change there are certain points on the line that the reflection will be in phase with the incident wave and the amplitude of the two waves will add. There will be other points where the two waves are in anti-phase and will consequently subtract. At these latter points the amplitude is at a minimum and they are known as nodes. If the incident wave has been totally reflected and the line is lossless, there will be complete cancellation at the nodes with zero signal present there despite the ongoing transmission of waves in both directions. The points where the waves are in phase are anti-nodes and represent a peak in amplitude. Nodes and anti-nodes alternate along the line and the combined wave amplitude varies continuously between them. The combined (incident plus reflected) wave appears to be standing still on the line and is called a standing wave.[9]
\gamma
V
Vi=Ve-\gammax'
However, it is often more convenient to work in terms of distance from the load () and the incident voltage that has arrived there (
ViL
Vi=
\gammax | |
V | |
iLe |
The negative sign is absent because
x
Vr=
-\gammax | |
\GammaV | |
iLe |
~.
The total voltage on the line is given by
VT=Vi+Vr=ViL\left(e\gammax+\Gammae-\gammax\right)~.
It is often convenient to express this in terms of hyperbolic functions
VT=ViL\left[\left(1+\Gamma\right)\cosh(\gammax)+\left(1-\Gamma\right)\sinh(\gammax)\right]~.
Similarly, the total current on the line is
IT=IiL\left[(1-\Gamma)\cosh(\gammax)+(1+\Gamma)\sinh(\gammax)\right]~.
The voltage nodes (current nodes are not at the same locations) and anti-nodes occur when
\partial\left|VT\right| | |
\partialx |
=0~.
Because of the absolute value bars, the general case analytical solution is tiresomely complicated, but in the case of lossless lines (or lines that are short enough that the losses can be neglected)
\gamma
j\beta
\beta
VT=ViL\left[(1+\Gamma)\cos(\betax)+j\left(1-\Gamma\right)\sin(\betax)\right]~,
and the partial differential of the magnitude of this yields the condition,
-2\operatornamel{Im}\{\Gamma\}=\tan(2\betax)~.
Expressing
\beta
λ
x
λ
-2\operatornamel{Im}\{\Gamma\}=\tan\left(
4\pi | |
λ |
x\right)~.
\Gamma
Z0
ZL
\tan\left(
4\pi | |
λ |
x\right)=0~,
which solves for
x
x=0,~~\tfrac{1}{4}λ,~~\tfrac{1}{2}λ,~~\tfrac{3}{4}λ,~...~.
For
RL<R0
RL>R0
\Gamma
The ratio of
|VT|
VSWR=
1+\left|\Gamma\right| | |
1-\left|\Gamma\right| |
for a lossless line; the expression for the current standing wave ratio (ISWR) is identical in this case. For a lossy line the expression is only valid adjacent to the termination; VSWR asymptotically approaches unity with distance from the termination or discontinuity.
VSWR and the positions of the nodes are parameters that can be directly measured with an instrument called a slotted line. This instrument makes use of the reflection phenomenon to make many different measurements at microwave frequencies. One use is that VSWR and node position can be used to calculate the impedance of a test component terminating the slotted line. This is a useful method because measuring impedances by directly measuring voltages and currents is difficult at these frequencies.[11] [12]
VSWR is the conventional means of expressing the match of a radio transmitter to its antenna. It is an important parameter because power reflected back into a high power transmitter can damage its output circuitry.[13]
The input impedance looking into a transmission line which is not terminated with its characteristic impedance at the far end will be something other than
Z0
Zin=
VT | |
IT |
=Z0
(1+\Gamma)\cosh(\gammax)+(1-\Gamma)\sinh(\gammax) | |
(1-\Gamma)\cosh(\gammax)+(1+\Gamma)\sinh(\gammax) |
Substituting
x=\ell
(1+\Gamma)\cosh(\gammax)
Zin=Z0
ZL+Z0\tanh(\gamma\ell) | |
Z0+ZL\tanh(\gamma\ell) |
As before, when considering just short pieces of transmission line,
\gamma
j\beta
Zin=Z0
ZL+jZ0\tan(\beta\ell) | |
Z0+jZL\tan(\beta\ell) |
There are two structures that are of particular importance which use reflected waves to modify impedance. One is the stub which is a short length of line terminated in a short circuit (or it can be an open circuit). This produces a purely imaginary impedance at its input, that is, a reactance
Xin=Z0\tan(\beta\ell)
By suitable choice of length, the stub can be used in place of a capacitor, an inductor or a resonant circuit.[15]
The other structure is the quarter wave impedance transformer. As its name suggests, this is a line exactly
λ/4
\beta\ell=\pi/2
Zin=
{Z0 | |
2}{Z |
L}
Both of these structures are widely used in distributed element filters and impedance matching networks.