Ptak space explained
A locally convex topological vector space (TVS)
is
B-complete or a
Ptak space if every subspace
is closed in the weak-* topology on
(i.e.
or
\sigma\left(X\prime,X\right)
) whenever
is closed in
(when
is given the subspace topology from
) for each equicontinuous subset
.
B-completeness is related to
-completeness, where a
locally convex TVS
is
-complete if every subspace
is closed in
whenever
is closed in
(when
is given the subspace topology from
) for each equicontinuous subset
.
Characterizations
Throughout this section,
will be a
locally convex topological vector space (TVS).
The following are equivalent:
is a Ptak space.
- Every continuous nearly open linear map of
into any locally convex space
is a topological homomorphism.
is called
nearly open if for each neighborhood
of the origin in
,
is dense in some neighborhood of the origin in
The following are equivalent:
is
-complete.
- Every continuous biunivocal, nearly open linear map of
into any locally convex space
is a TVS-isomorphism.
Properties
Every Ptak space is complete. However, there exist complete Hausdorff locally convex space that are not Ptak spaces.
Let
be a nearly open linear map whose domain is dense in a
-complete space
and whose range is a locally convex space
. Suppose that the graph of
is closed in
. If
is injective or if
is a Ptak space then
is an open map.
Examples and sufficient conditions
There exist Br-complete spaces that are not B-complete.
Every Fréchet space is a Ptak space. The strong dual of a reflexive Fréchet space is a Ptak space.
Every closed vector subspace of a Ptak space (resp. a Br-complete space) is a Ptak space (resp. a
-complete space). and every
Hausdorff quotient of a Ptak space is a Ptak space. If every Hausdorff quotient of a TVS
is a B
r-complete space then
is a
B-complete space.
If
is a locally convex space such that there exists a continuous nearly open surjection
from a Ptak space, then
is a Ptak space.
If a TVS
has a closed
hyperplane that is B-complete (resp. B
r-complete) then
is B-complete (resp. B
r-complete).
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