Positive operator (Hilbert space) explained

A

acting on an inner product space is called positive-semidefinite (or non-negative) if, for every

x\inDom(A)

,

\langleAx,x\rangle\inR

and

\langleAx,x\rangle\geq0

, where

Dom(A)

is the domain of

A

. Positive-semidefinite operators are denoted as

A\ge0

. The operator is said to be positive-definite, and written

A>0

, if

\langleAx,x\rangle>0,

for all

x\inDom(A)\setminus\{0\}

.

Many authors define a positive operator

A

to be a self-adjoint (or at least symmetric) non-negative operator. We show below that for a complex Hilbert space the self adjointness follows automatically from non-negativity. For a real Hilbert space non-negativity does not imply self adjointness.

In physics (specifically quantum mechanics), such operators represent quantum states, via the density matrix formalism.

Cauchy–Schwarz inequality

See main article: Cauchy–Schwarz inequality. Take the inner product

\langle,\rangle

to be anti-linear on the first argument and linear on the second and suppose that

A

is positive and symmetric, the latter meaning that

\langleAx,y\rangle=\langlex,Ay\rangle

.Then the non negativity of

\begin{align} \langleA(λx+\muy),λx+\muy\rangle =|λ|2\langleAx,x\rangle+λ*\mu\langleAx,y\rangle+λ\mu*\langleAy,x\rangle+|\mu|2\langleAy,y\rangle\\[1mm] =|λ|2\langleAx,x\rangle+λ*\mu\langleAx,y\rangle+λ\mu*(\langleAx,y\rangle)*+|\mu|2\langleAy,y\rangle \end{align}

for all complex

λ

and

\mu

shows that

\left|\langleAx,y\rangle\right|2\leq\langleAx,x\rangle\langleAy,y\rangle.

It follows that

ImA\perpKerA.

If

A

is defined everywhere, and

\langleAx,x\rangle=0,

then

Ax=0.

On a complex Hilbert space, if an operator is non-negative then it is symmetric

For

x,y\inDomA,

the polarization identity

\begin{align} \langleAx,y\rangle=

1
4

({}&\langleA(x+y),x+y\rangle-\langleA(x-y),x-y\rangle\\[1mm] &{}-i\langleA(x+iy),x+iy\rangle+i\langleA(x-iy),x-iy\rangle) \end{align}

and the fact that

\langleAx,x\rangle=\langlex,Ax\rangle,

for positive operators, show that

\langleAx,y\rangle=\langlex,Ay\rangle,

so

A

is symmetric.

In contrast with the complex case, a positive-semidefinite operator on a real Hilbert space

HR

may not be symmetric. As a counterexample, define

A:R2\toR2

to be an operator of rotation by an acute angle

\varphi\in(-\pi/2,\pi/2).

Then

\langleAx,x\rangle=\|Ax\|\|x\|\cos\varphi>0,

but

A*=A-1A,

so

A

is not symmetric.

The symmetry of

A

implies that

DomA\subseteqDomA*

and

A=

*|
A
Dom(A)

.

For

A

to be self-adjoint, it is necessary that

DomA=DomA*.

In our case, the equality of domains holds because

HC=DomA\subseteqDomA*,

so

A

is indeed self-adjoint. The fact that

A

is bounded now follows from the Hellinger–Toeplitz theorem.

This property does not hold on

HR.

Partial order of self-adjoint operators

A natural partial ordering of self-adjoint operators arises from the definition of positive operators. Define

B\geqA

if the following hold:

A

and

B

are self-adjoint

B-A\geq0

It can be seen that a similar result as the Monotone convergence theorem holds for monotone increasing, bounded, self-adjoint operators on Hilbert spaces.[1]

Application to physics: quantum states

HC

and a set

\calS

of positive trace-class operators

\rho

on

HC

for which

Trace\rho=1.

The set

\calS

is the set of states. Every

\rho\in{\calS}

is called a state or a density operator. For

\psi\inHC,

where

\|\psi\|=1,

the operator

P\psi

of projection onto the span of

\psi

is called a pure state. (Since each pure state is identifiable with a unit vector

\psi\inHC,

some sources define pure states to be unit elements from

HC).

States that are not pure are called mixed.

Notes and References

  1. Eidelman, Yuli, Vitali D. Milman, and Antonis Tsolomitis. 2004. Functional analysis: an introduction. Providence (R.I.): American mathematical Society.