In mathematics, the ping-pong lemma, or table-tennis lemma, is any of several mathematical statements that ensure that several elements in a group acting on a set freely generates a free subgroup of that group.
The ping-pong argument goes back to the late 19th century and is commonly attributed to Felix Klein who used it to study subgroups of Kleinian groups, that is, of discrete groups of isometries of the hyperbolic 3-space or, equivalently Möbius transformations of the Riemann sphere. The ping-pong lemma was a key tool used by Jacques Tits in his 1972 paper[1] containing the proof of a famous result now known as the Tits alternative. The result states that a finitely generated linear group is either virtually solvable or contains a free subgroup of rank two. The ping-pong lemma and its variations are widely used in geometric topology and geometric group theory.
Modern versions of the ping-pong lemma can be found in many books such as Lyndon & Schupp,[2] de la Harpe,[3] Bridson & Haefliger[4] and others.
This version of the ping-pong lemma ensures that several subgroups of a group acting on a set generate a free product. The following statement appears in Olijnyk and Suchchansky (2004),[5] and the proof is from de la Harpe (2000).[3]
Let G be a group acting on a set X and let H1, H2, ..., Hk be subgroups of G where k ≥ 2, such that at least one of these subgroups has order greater than 2.Suppose there exist pairwise disjoint nonempty subsets of such that the following holds:
Then
By the definition of free product, it suffices to check that a given (nonempty) reduced word represents a nontrivial element of
G
w
m\geq2
\alphai ≠ \alphai+1
i=1,...,m-1
wi
H | |
\alphai |
w
Hi
H1
\alpha1
\alpham
m\geq3
w
X2
By the assumption that different
Xi
w
X2
w
G
To finish the proof we must consider the three cases:
\alpha1=1,\alpham ≠ 1
h\inH1\setminus
-1 | |
\{w | |
1 |
,1\}
h
H1
\alpha1 ≠ 1,\alpham=1
h\inH1\setminus\{wm,1\}
\alpha1 ≠ 1,\alpham ≠ 1
h\inH1\setminus\{1\}
In each case,
hwh-1
H1
hwh-1
G
w
Let G be a group acting on a set X. Let a1, ...,ak be elements of G of infinite order, where k ≥ 2. Suppose there exist disjoint nonempty subsets
of with the following properties:
Then the subgroup generated by a1, ..., ak is free with free basis .
This statement follows as a corollary of the version for general subgroups if we let and let .
One can use the ping-pong lemma to prove[3] that the subgroup, generated by the matrices and is free of rank two.
Indeed, let and be cyclic subgroups of generated by and accordingly. It is not hard to check that and are elements of infinite order in and thatand
Consider the standard action of on by linear transformations. Putand
It is not hard to check, using the above explicit descriptions of H1 and H2, that for every nontrivial we have and that for every nontrivial we have . Using the alternative form of the ping-pong lemma, for two subgroups, given above, we conclude that . Since the groups and are infinite cyclic, it follows that H is a free group of rank two.
Let be a word-hyperbolic group which is torsion-free, that is, with no nonidentity elements of finite order. Let be two non-commuting elements, that is such that . Then there exists M ≥ 1 such that for any integers, the subgroup is free of rank two.
The group G acts on its hyperbolic boundary ∂G by homeomorphisms. It is known that if a in G is a nonidentity element then a has exactly two distinct fixed points, and in and that is an attracting fixed point while is a repelling fixed point.
Since and do not commute, basic facts about word-hyperbolic groups imply that,, and are four distinct points in . Take disjoint neighborhoods,,, and of,, and in respectively.Then the attracting/repelling properties of the fixed points of g and h imply that there exists such that for any integers, we have:
The ping-pong lemma now implies that is free of rank two.