Ping-pong lemma explained

In mathematics, the ping-pong lemma, or table-tennis lemma, is any of several mathematical statements that ensure that several elements in a group acting on a set freely generates a free subgroup of that group.

History

The ping-pong argument goes back to the late 19th century and is commonly attributed to Felix Klein who used it to study subgroups of Kleinian groups, that is, of discrete groups of isometries of the hyperbolic 3-space or, equivalently Möbius transformations of the Riemann sphere. The ping-pong lemma was a key tool used by Jacques Tits in his 1972 paper[1] containing the proof of a famous result now known as the Tits alternative. The result states that a finitely generated linear group is either virtually solvable or contains a free subgroup of rank two. The ping-pong lemma and its variations are widely used in geometric topology and geometric group theory.

Modern versions of the ping-pong lemma can be found in many books such as Lyndon & Schupp,[2] de la Harpe,[3] Bridson & Haefliger[4] and others.

Formal statements

Ping-pong lemma for several subgroups

This version of the ping-pong lemma ensures that several subgroups of a group acting on a set generate a free product. The following statement appears in Olijnyk and Suchchansky (2004),[5] and the proof is from de la Harpe (2000).[3]

Let G be a group acting on a set X and let H1, H2, ..., Hk be subgroups of G where k ≥ 2, such that at least one of these subgroups has order greater than 2.Suppose there exist pairwise disjoint nonempty subsets of such that the following holds:

Then \langle H_1,\dots, H_k\rangle=H_1\ast\dots \ast H_k.

Proof

By the definition of free product, it suffices to check that a given (nonempty) reduced word represents a nontrivial element of

G

. Let

w

be such a word of length

m\geq2

, and let w = \prod_^m w_i, where w_i \in H_ for some \alpha_i \in \. Since w is reduced, we have

\alphai\alphai+1

for any

i=1,...,m-1

and each

wi

is distinct from the identity element of
H
\alphai
. We then let

w

act on an element of one of the sets X_i. As we assume that at least one subgroup

Hi

has order at least 3, without loss of generality we may assume that

H1

has order at least 3. We first make the assumption that

\alpha1

and

\alpham

are both 1 (which implies

m\geq3

). From here we consider

w

acting on

X2

. We get the following chain of containments:w(X_2) \subseteq \prod_^ w_i(X_1) \subseteq \prod_^ w_i(X_) \subseteq \dots \subseteq w_1(X_) \subseteq X_1.

By the assumption that different

Xi

's are disjoint, we conclude that

w

acts nontrivially on some element of

X2

, thus

w

represents a nontrivial element of

G

.

To finish the proof we must consider the three cases:

\alpha1=1,\alpham1

, then let

h\inH1\setminus

-1
\{w
1

,1\}

(such an

h

exists since by assumption

H1

has order at least 3);

\alpha11,\alpham=1

, then let

h\inH1\setminus\{wm,1\}

;

\alpha1 ≠ 1,\alpham1

, then let

h\inH1\setminus\{1\}

.

In each case,

hwh-1

after reduction becomes a reduced word with its first and last letter in

H1

. Finally,

hwh-1

represents a nontrivial element of

G

, and so does

w

. This proves the claim.

The Ping-pong lemma for cyclic subgroups

Let G be a group acting on a set X. Let a1, ...,ak be elements of G of infinite order, where k ≥ 2. Suppose there exist disjoint nonempty subsets

of with the following properties:

Then the subgroup generated by a1, ..., ak is free with free basis .

Proof

This statement follows as a corollary of the version for general subgroups if we let and let .

Examples

Special linear group example

One can use the ping-pong lemma to prove[3] that the subgroup, generated by the matricesA = \begin1 & 2\\ 0 &1 \end and B = \begin1 & 0\\ 2 &1 \endis free of rank two.

Proof

Indeed, let and be cyclic subgroups of generated by and accordingly. It is not hard to check that and are elements of infinite order in and thatH_1 = \ = \left\andH_2 = \ = \left\.

Consider the standard action of on by linear transformations. PutX_1 = \left\andX_2 = \left\.

It is not hard to check, using the above explicit descriptions of H1 and H2, that for every nontrivial we have and that for every nontrivial we have . Using the alternative form of the ping-pong lemma, for two subgroups, given above, we conclude that . Since the groups and are infinite cyclic, it follows that H is a free group of rank two.

Word-hyperbolic group example

Let be a word-hyperbolic group which is torsion-free, that is, with no nonidentity elements of finite order. Let be two non-commuting elements, that is such that . Then there exists M ≥ 1 such that for any integers, the subgroup is free of rank two.

Sketch of the proof[6]

The group G acts on its hyperbolic boundaryG by homeomorphisms. It is known that if a in G is a nonidentity element then a has exactly two distinct fixed points, and in and that is an attracting fixed point while is a repelling fixed point.

Since and do not commute, basic facts about word-hyperbolic groups imply that,, and are four distinct points in . Take disjoint neighborhoods,,, and of,, and in respectively.Then the attracting/repelling properties of the fixed points of g and h imply that there exists such that for any integers, we have:

The ping-pong lemma now implies that is free of rank two.

Applications of the ping-pong lemma

See also

Notes and References

  1. J. Tits. Free subgroups in linear groups. Journal of Algebra, vol. 20 (1972), pp. 250–270
  2. [Roger Lyndon|Roger C. Lyndon]
  3. Pierre de la Harpe. Topics in geometric group theory. Chicago Lectures in Mathematics. University of Chicago Press, Chicago. ; Ch. II.B "The table-Tennis Lemma (Klein's criterion) and examples of free products"; pp. 25 - 41.
  4. Martin R. Bridson, and André Haefliger. Metric spaces of non-positive curvature. Grundlehren der Mathematischen Wissenschaften [Fundamental Principles of Mathematical Sciences], 319. Springer-Verlag, Berlin, 1999. ; Ch.III.Γ, pp. 467 - 468
  5. Andrij Olijnyk and Vitaly Suchchansky. Representations of free products by infinite unitriangular matrices over finite fields. International Journal of Algebra and Computation. Vol. 14 (2004), no. 5 - 6, pp. 741 - 749; Lemma 2.1
  6. M. Gromov. Hyperbolic groups. Essays in group theory, pp. 75 - 263, Mathematical Sciences Research Institute Publications, 8, Springer, New York, 1987; ; Ch. 8.2, pp. 211 - 219.
  7. [Alexander Lubotzky]
  8. Richard P. Kent, and Christopher J. Leininger. Subgroups of mapping class groups from the geometrical viewpoint. In the tradition of Ahlfors-Bers. IV, pp. 119 - 141,Contemporary Mathematics series, 432, American Mathematical Society, Providence, RI, 2007; ; 0-8218-4227-7
  9. [Mladen Bestvina|M. Bestvina]
  10. Pierre de la Harpe. Free groups in linear groups. L'Enseignement Mathématique (2), vol. 29 (1983), no. 1-2, pp. 129 - 144
  11. [Bernard Maskit]
  12. Pierre de la Harpe. Topics in geometric group theory. Chicago Lectures in Mathematics. University of Chicago Press, Chicago. ; Ch. II.B "The table-Tennis Lemma (Klein's criterion) and examples of free products"; pp. 187 - 188.
  13. Alex Eskin, Shahar Mozes and Hee Oh. On uniform exponential growth for linear groups. Inventiones Mathematicae. vol. 60 (2005), no. 1, pp.1432 - 1297; Lemma 2.2
  14. Roger C. Alperin and Guennadi A. Noskov. Uniform growth, actions on trees and GL2. Computational and Statistical Group Theory:AMS Special Session Geometric Group Theory, April 21–22, 2001, Las Vegas, Nevada, AMS Special Session Computational Group Theory, April 28–29, 2001, Hoboken, New Jersey. (Robert H. Gilman, Vladimir Shpilrain, Alexei G. Myasnikov, editors). American Mathematical Society, 2002. ; page 2, Lemma 3.1
  15. Yves de Cornulier and Romain Tessera. Quasi-isometrically embedded free sub-semigroups. Geometry & Topology, vol. 12 (2008), pp. 461 - 473; Lemma 2.1