Pell number explained

Pell number should not be confused with Bell number.

In mathematics, the Pell numbers are an infinite sequence of integers, known since ancient times, that comprise the denominators of the closest rational approximations to the square root of 2. This sequence of approximations begins,,,, and, so the sequence of Pell numbers begins with 1, 2, 5, 12, and 29. The numerators of the same sequence of approximations are half the companion Pell numbers or Pell–Lucas numbers; these numbers form a second infinite sequence that begins with 2, 6, 14, 34, and 82.

Both the Pell numbers and the companion Pell numbers may be calculated by means of a recurrence relation similar to that for the Fibonacci numbers, and both sequences of numbers grow exponentially, proportionally to powers of the silver ratio 1 + . As well as being used to approximate the square root of two, Pell numbers can be used to find square triangular numbers, to construct integer approximations to the right isosceles triangle, and to solve certain combinatorial enumeration problems.[1]

As with Pell's equation, the name of the Pell numbers stems from Leonhard Euler's mistaken attribution of the equation and the numbers derived from it to John Pell. The Pell–Lucas numbers are also named after Édouard Lucas, who studied sequences defined by recurrences of this type; the Pell and companion Pell numbers are Lucas sequences.

Pell numbers

The Pell numbers are defined by the recurrence relation:

Pn=\begin{cases}0&ifn=0;\\1&ifn=1;\\2Pn-1+Pn-2&otherwise.\end{cases}

In words, the sequence of Pell numbers starts with 0 and 1, and then each Pell number is the sum of twice the previous Pell number, plus the Pell number before that. The first few terms of the sequence are

0, 1, 2, 5, 12, 29, 70, 169, 408, 985, 2378, 5741, 13860, … .

Analogously to the Binet formula, the Pell numbers can also be expressed by the closed form formula

P
n=\left(1+\sqrt2\right)n-\left(1-\sqrt2\right)n
2\sqrt2

.

For large values of n, the term dominates this expression, so the Pell numbers are approximately proportional to powers of the silver ratio, analogous to the growth rate of Fibonacci numbers as powers of the golden ratio.

A third definition is possible, from the matrix formula

\begin{pmatrix}Pn+1&Pn\Pn&Pn-1\end{pmatrix}=\begin{pmatrix}2&1\ 1&0\end{pmatrix}n.

Many identities can be derived or proven from these definitions; for instance an identity analogous to Cassini's identity for Fibonacci numbers,

Pn+1Pn-1

2
-P
n

=(-1)n,

is an immediate consequence of the matrix formula (found by considering the determinants of the matrices on the left and right sides of the matrix formula).[2]

Approximation to the square root of two

Pell numbers arise historically and most notably in the rational approximation to . If two large integers x and y form a solution to the Pell equation

x2-2y2=\pm1,

then their ratio provides a close approximation to . The sequence of approximations of this form is
11,
32,
75,
17
12

,

41
29

,

99
70

,...

where the denominator of each fraction is a Pell number and the numerator is the sum of a Pell number and its predecessor in the sequence. That is, the solutions have the form
Pn-1+Pn
Pn

.

The approximation

\sqrt2 ≈

577
408
of this type was known to Indian mathematicians in the third or fourth century BCE.[3] The Greek mathematicians of the fifth century BCE also knew of this sequence of approximations:[4] Plato refers to the numerators as rational diameters.[5] In the second century CE Theon of Smyrna used the term the side and diameter numbers to describe the denominators and numerators of this sequence.[6]

These approximations can be derived from the continued fraction expansion of

\sqrt2

:

\sqrt2=1+\cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{2+\ddots}}}}}.

Truncating this expansion to any number of terms produces one of the Pell-number-based approximations in this sequence; for instance,
577
408

=1+\cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{2+\cfrac{1}{2}}}}}}}.

As Knuth (1994) describes, the fact that Pell numbers approximate allows them to be used for accurate rational approximations to a regular octagon with vertex coordinates and . All vertices are equally distant from the origin, and form nearly uniform angles around the origin. Alternatively, the points

(\pm(Pi+Pi-1),0)

,

(0,\pm(Pi+Pi-1))

, and

(\pmPi,\pmPi)

form approximate octagons in which the vertices are nearly equally distant from the origin and form uniform angles.

Primes and squares

A Pell prime is a Pell number that is prime. The first few Pell primes are

2, 5, 29, 5741, 33461, 44560482149, 1746860020068409, 68480406462161287469, ... .The indices of these primes within the sequence of all Pell numbers are

2, 3, 5, 11, 13, 29, 41, 53, 59, 89, 97, 101, 167, 181, 191, 523, 929, 1217, 1301, 1361, 2087, 2273, 2393, 8093, ... These indices are all themselves prime. As with the Fibonacci numbers, a Pell number Pn can only be prime if n itself is prime, because if d is a divisor of n then Pd is a divisor of Pn.

The only Pell numbers that are squares, cubes, or any higher power of an integer are 0, 1, and 169 = 132.[7]

However, despite having so few squares or other powers, Pell numbers have a close connection to square triangular numbers.[8] Specifically, these numbers arise from the following identity of Pell numbers:

l(\left(Pk-1+Pk\right)

2
P
kr)

=

\left(P
2 ⋅ \left(\left(P
+P
k-1
2-(-1)
+P
k\right)
k\right)
k-1
2

.

The left side of this identity describes a square number, while the right side describes a triangular number, so the result is a square triangular number.

Falcón and Díaz-Barrero (2006) proved another identity relating Pell numbers to squares and showing that the sum of the Pell numbers up to P4n +1 is always a square:

4n+1
\sum
i=0

Pi=

n
\left(\sum
r=0

2r{2n+1\choose2r}\right)2=\left(P2n+P2n+1\right)2.

For instance, the sum of the Pell numbers up to P5,, is the square of . The numbers forming the square roots of these sums,

1, 7, 41, 239, 1393, 8119, 47321, …,are known as the Newman–Shanks–Williams (NSW) numbers.

Pythagorean triples

If a right triangle has integer side lengths a, b, c (necessarily satisfying the Pythagorean theorem), then (a,b,c) is known as a Pythagorean triple. As Martin (1875) describes, the Pell numbers can be used to form Pythagorean triples in which a and b are one unit apart, corresponding to right triangles that are nearly isosceles. Each such triple has the form

\left(2PnPn+1,

2
P
n+1

-

2,
P
n
2
P
n+1

+

2=P
P
2n+1

\right).

The sequence of Pythagorean triples formed in this way is

(4,3,5), (20,21,29), (120,119,169), (696,697,985), …

Pell–Lucas numbers

The companion Pell numbers or Pell–Lucas numbers are defined by the recurrence relation

Qn=\begin{cases}2&ifn=0;\\2&ifn=1;\\2Qn-1+Qn-2&otherwise.\end{cases}

In words: the first two numbers in the sequence are both 2, and each successive number is formed by adding twice the previous Pell–Lucas number to the Pell–Lucas number before that, or equivalently, by adding the next Pell number to the previous Pell number: thus, 82 is the companion to 29, and The first few terms of the sequence are : 2, 2, 6, 14, 34, 82, 198, 478, …

Like the relationship between Fibonacci numbers and Lucas numbers,

Q
n=P2n
Pn
for all natural numbers n.

The companion Pell numbers can be expressed by the closed form formula

Qn=\left(1+\sqrt2\right)n+\left(1-\sqrt2\right)n.

These numbers are all even; each such number is twice the numerator in one of the rational approximations to

\sqrt2

discussed above.

Like the Lucas sequence, if a Pell–Lucas number Qn is prime, it is necessary that n be either prime or a power of 2. The Pell–Lucas primes are

3, 7, 17, 41, 239, 577, … .

For these n are

2, 3, 4, 5, 7, 8, 16, 19, 29, 47, 59, 163, 257, 421, … .

Computations and connections

The following table gives the first few powers of the silver ratio δ = δ S = 1 +  and its conjugate = 1 − .

n(1 +)n(1 −)n
01 + 0 = 11 − 0 = 1
11 + 1 = 2.41421…1 − 1 = −0.41421…
23 + 2 = 5.82842…3 − 2 = 0.17157…
37 + 5 = 14.07106…7 − 5 = −0.07106…
417 + 12 = 33.97056…17 − 12 = 0.02943…
541 + 29 = 82.01219…41 − 29 = −0.01219…
699 + 70 = 197.9949…99 − 70 = 0.0050…
7239 + 169 = 478.00209…239 − 169 = −0.00209…
8577 + 408 = 1153.99913…577 − 408 = 0.00086…
91393 + 985 = 2786.00035…1393 − 985 = −0.00035…
103363 + 2378 = 6725.99985…3363 − 2378 = 0.00014…
118119 + 5741 = 16238.00006…8119 − 5741 = −0.00006…
1219601 + 13860 = 39201.99997…19601 − 13860 = 0.00002…

The coefficients are the half-companion Pell numbers Hn and the Pell numbers Pn which are the (non-negative) solutions to .A square triangular number is a number

N=

t(t+1)
2

=s2,

which is both the t-th triangular number and the s-th square number. A near-isosceles Pythagorean triple is an integer solution to where .

The next table shows that splitting the odd number Hn into nearly equal halves gives a square triangular number when n is even and a near isosceles Pythagorean triple when n is odd. All solutions arise in this manner.

nHnPntt + 1sabc
010010   
111   011
232121   
375   345
41712896   
54129   202129
69970495035   
7239169   119120169
8577408288289204   
91393985   696697985
1033632378168116821189   
1181195741   405940605741
121960113860980098016930   

Definitions

The half-companion Pell numbers Hn and the Pell numbers Pn can be derived in a number of easily equivalent ways.

Raising to powers

\left(1+\sqrt2\right)n=Hn+Pn\sqrt{2}

\left(1-\sqrt2\right)n=Hn-Pn\sqrt{2}.

From this it follows that there are closed forms:

Hn=

\left(1+\sqrt2\right)n+\left(1-\sqrt2\right)n
2

.

and

Pn\sqrt2=

\left(1+\sqrt2\right)n-\left(1-\sqrt2\right)n
2

.

Paired recurrences

Hn=\begin{cases}1&ifn=0;\\Hn-1+2Pn-1&otherwise.\end{cases}

Pn=\begin{cases}0&ifn=0;\\Hn-1+Pn-1&otherwise.\end{cases}

Reciprocal recurrence formulas

Let n be at least 2.

Hn=(3Pn-Pn-2)/2=3Pn-1+Pn-2;

Pn=(3Hn-Hn-2)/4=(3Hn-1+Hn-2)/2.

Matrix formulations

\begin{pmatrix}Hn\Pn\end{pmatrix}=\begin{pmatrix}1&2\ 1&1\end{pmatrix}\begin{pmatrix}Hn-1\Pn-1\end{pmatrix}=\begin{pmatrix}1&2\ 1&1\end{pmatrix}n\begin{pmatrix}1\ 0\end{pmatrix}.

So

\begin{pmatrix}Hn&2Pn\Pn&Hn\end{pmatrix}=\begin{pmatrix}1&2\ 1&1\end{pmatrix}n.

Approximations

The difference between Hn and Pn is

\left(1-\sqrt2\right)n(-0.41421)n,

which goes rapidly to zero. So

\left(1+\sqrt2\right)n=Hn+Pn\sqrt2

is extremely close to 2Hn.

From this last observation it follows that the integer ratios rapidly approach ; and and rapidly approach 1 + .

H  2 − 2P  2 = ±1

Since is irrational, we cannot have  = , i.e.,

H2
P2

=

2P2
P2

.

The best we can achieve is either

H2
P2

=

2P2-1
P2

or

H2
P2

=

2P2+1
P2

.

The (non-negative) solutions to are exactly the pairs with n even, and the solutions to are exactly the pairs with n odd. To see this, note first that

2
H
n+1

=\left(Hn+2P

2-2\left(H
n+P
2
n\right)

=

2\right),
-\left(H
n

so that these differences, starting with, are alternately 1 and −1. Then note that every positive solution comes in this way from a solution with smaller integers since

(2P-H)2-2(H-P)2=-\left(H2-2P2\right).

The smaller solution also has positive integers, with the one exception: which comes from H0 = 1 and P0 = 0.

Square triangular numbers

See main article: Square triangular number. The required equation

t(t+1)
2

=s2

is equivalent to

4t2+4t+1=8s2+1,

which becomes with the substitutions H = 2t + 1 and P = 2s. Hence the n-th solution is

tn=

H2n-1
2

andsn=

P2n
2

.

Observe that t and t + 1 are relatively prime, so that  = s 2 happens exactly when they are adjacent integers, one a square H  2 and the other twice a square 2P  2. Since we know all solutions of that equation, we also have

tn=\begin{cases}2P

2&ifnisodd.\end{cases}
n
and

sn=HnPn.

This alternate expression is seen in the next table.

nHnPntt + 1sabc
010      
111121345
232896202129
375495035119120169
41712288289204696697985
54129168116821189405940605741
69970980098016930236602366133461

Pythagorean triples

The equality occurs exactly when which becomes with the substitutions and . Hence the n-th solution is and .

The table above shows that, in one order or the other, an and are and while .

References

External links

Notes and References

  1. For instance, Sellers (2002) proves that the number of perfect matchings in the Cartesian product of a path graph and the graph K4 − e can be calculated as the product of a Pell number with the corresponding Fibonacci number.
  2. For the matrix formula and its consequences see Ercolano (1979) and Kilic and Tasci (2005). Additional identities for the Pell numbers are listed by Horadam (1971) and Bicknell (1975).
  3. As recorded in the Shulba Sutras; see e.g. Dutka (1986), who cites Thibaut (1875) for this information.
  4. See Knorr (1976) for the fifth century date, which matches Proclus' claim that the side and diameter numbers were discovered by the Pythagoreans. For more detailed exploration of later Greek knowledge of these numbers see Thompson (1929), Vedova (1951), Ridenhour (1986), Knorr (1998), and Filep (1999).
  5. For instance, as several of the references from the previous note observe, in Plato's Republic there is a reference to the "rational diameter of 5", by which Plato means 7, the numerator of the approximation of which 5 is the denominator.
  6. .
  7. Pethő (1992); Cohn (1996). Although the Fibonacci numbers are defined by a very similar recurrence to the Pell numbers, Cohn writes that an analogous result for the Fibonacci numbers seems much more difficult to prove. (However, this was proven in 2006 by Bugeaud et al.)
  8. Sesskin (1962). See the square triangular number article for a more detailed derivation.