1976 United States Senate election in North Dakota explained

Election Name:1976 United States Senate election in North Dakota
Country:North Dakota
Type:presidential
Ongoing:no
Previous Election:1970 United States Senate election in North Dakota
Previous Year:1970
Next Election:1982 United States Senate election in North Dakota
Next Year:1982
Election Date:November 2, 1976
Image1:File:BurdickQN_(D-ND) (cropped 2).jpg
Nominee1:Quentin Burdick
Party1:North Dakota Democratic-NPL Party
Popular Vote1:175,772
Percentage1:62.10%
Nominee2:Robert Stroup
Party2:Republican Party (United States)
Popular Vote2:103,466
Percentage2:36.55%
Map Size:250px
U.S. Senator
Before Election:Quentin Burdick
Posttitle:Elected U.S. Senator
Before Party:Democratic Party (US)
After Election:Quentin Burdick
After Party:Democratic Party (US)

The 1976 U.S. Senate election for the state of North Dakota was held November 2, 1976. The incumbent, North Dakota Democratic NPL Party (Dem-NPL) Senator Quentin Burdick, sought and received re-election to his fourth term to the United States Senate, defeating Republican candidate Robert Stroup.[1]

Only Burdick filed as a Dem-NPLer, and the endorsed Republican candidate was Robert Stroup, as state senator from Hazen, North Dakota. Burdick and Stroup won the primary elections for their respective parties.

One independent candidate, Clarence Haggard, also filed before the deadline under the American Party.

See also

External links

Notes and References

  1. Web site: Statistics of the Presidential and Congressional Election of November 2, 1976 . Clerk of the House of Representatives . 36.