Normal cone (functional analysis) explained
In mathematics, specifically in order theory and functional analysis, if
is a
cone at the origin in a
topological vector space
such that
and if
is the
neighborhood filter at the origin, then
is called
normal if
where
\left[l{U}\right]C:=\left\{[U]C:U\inl{U}\right\}
and where for any subset
is the
-saturatation of
Normal cones play an important role in the theory of ordered topological vector spaces and topological vector lattices.
Characterizations
If
is a cone in a TVS
then for any subset
let
[S]C:=\left(S+C\right)\cap\left(S-C\right)
be the
-saturated hull of
and for any collection
of subsets of
let
\left[l{S}\right]C:=\left\{\left[S\right]C:S\inl{S}\right\}.
If
is a cone in a TVS
then
is
normal if
where
is the neighborhood filter at the origin.
If
is a collection of subsets of
and if
is a subset of
then
is a
fundamental subfamily of
if every
is contained as a subset of some element of
If
is a family of subsets of a TVS
then a cone
in
is called a
-cone if
\left\{\overline{\left[G\right]C}:G\inl{G}\right\}
is a fundamental subfamily of
and
is a
strict
-cone if
\left\{\left[G\right]C:G\inl{G}\right\}
is a fundamental subfamily of
Let
denote the family of all bounded subsets of
If
is a cone in a TVS
(over the real or complex numbers), then the following are equivalent:
-
is a normal cone.
- For every filter
in
if
then
\lim\left[l{F}\right]C=0.
- There exists a neighborhood base
in
such that
implies
\left[B\capC\right]C\subseteqB.
and if
is a vector space over the reals then we may add to this list:
- There exists a neighborhood base at the origin consisting of convex, balanced,
-saturated sets.
- There exists a generating family
of semi-norms on
such that
for all
and
and if
is a locally convex space and if the dual cone of
is denoted by
then we may add to this list:
- For any equicontinuous subset
there exists an equicontiuous
such that
- The topology of
is the topology of uniform convergence on the equicontinuous subsets of
and if
is an
infrabarreled locally convex space and if
is the family of all strongly bounded subsets of
then we may add to this list:
- The topology of
is the topology of uniform convergence on strongly bounded subsets of
-
is a
-cone in
- this means that the family
\left\{\overline{\left[B\prime\right]C}:B\prime\inl{B}\prime\right\}
is a fundamental subfamily of
-
is a strict
-cone in
- this means that the family
\left\{\left[B\prime\right]C:B\prime\inl{B}\prime\right\}
is a fundamental subfamily of
and if
is an ordered locally convex TVS over the reals whose positive cone is
then we may add to this list:
- there exists a Hausdorff locally compact topological space
such that
is isomorphic (as an ordered TVS) with a subspace of
where
is the space of all real-valued continuous functions on
under the topology of compact convergence.
If
is a
locally convex TVS,
is a cone in
with
dual cone
and
is a
saturated family of weakly bounded subsets of
then
- if
is a
-cone then
is a normal cone for the
-topology on
;
- if
is a normal cone for a
-topology on
consistent with
\left\langleX,X\prime\right\rangle
then
is a strict
-cone in
If
is a Banach space,
is a closed cone in
, and
is the family of all bounded subsets of
then the
dual cone
is normal in
if and only if
is a strict
-cone.
If
is a Banach space and
is a cone in
then the following are equivalent:
is a
-cone in
;
X=\overline{C}-\overline{C}
;
is a strict
-cone in
Ordered topological vector spaces
Suppose
is an
ordered topological vector space. That is,
is a
topological vector space, and we define
whenever
lies in the cone
. The following statements are equivalent:
[1] - The cone
is normal;
- The normed space
admits an equivalent monotone
norm;
- There exists a constant
such that
implies
\lVertx\rVert\leqcmax\{\lVerta\rVert,\lVertb\rVert\}
;
- The full hull
of the closed unit ball
of
is norm bounded;
- There is a constant
such that
implies
\lVertx\rVert\leqc\lVerty\rVert
.
Properties
is a Hausdorff TVS then every normal cone in
is a proper cone.
is a normable space and if
is a normal cone in
then
- Suppose that the positive cone of an ordered locally convex TVS
is weakly normal in
and that
is an ordered locally convex TVS with positive cone
If
then
is dense in
where
is the canonical positive cone of
and
is the space
with the topology of simple convergence.
is a family of bounded subsets of
then there are apparently no simple conditions guaranteeing that
is a
-cone in
}(X; Y), even for the most common types of families
of bounded subsets of
}(X; Y) (except for very special cases).
Sufficient conditions
If the topology on
is locally convex then the closure of a normal cone is a normal cone.
Suppose that
\left\{X\alpha:\alpha\inA\right\}
is a family of locally convex TVSs and that
is a cone in
If
is the locally convex direct sum then the cone
is a normal cone in
if and only if each
is normal in
If
is a locally convex space then the closure of a normal cone is a normal cone.
If
is a cone in a locally convex TVS
and if
is the dual cone of
then
if and only if
is weakly normal. Every normal cone in a locally convex TVS is weakly normal. In a normed space, a cone is normal if and only if it is weakly normal.
If
and
are ordered locally convex TVSs and if
is a family of bounded subsets of
then if the positive cone of
is a
-cone in
and if the positive cone of
is a normal cone in
then the positive cone of
}(X; Y) is a normal cone for the
-topology on
Notes and References
- Book: Aliprantis, Charalambos D. . Cones and duality . 2007 . American Mathematical Society . Rabee Tourky . 978-0-8218-4146-4 . Providence, R.I. . 87808043.