The Mott–Schottky equation relates the capacitance to the applied voltage across a semiconductor-electrolyte junction.[1]
1 | |
C2 |
=
2 | |
\epsilon\epsilon0A2eNd |
(V-Vfb-
kBT | |
e |
)
where
C
\partial{Q | |
\epsilon
\epsilon0
A
wA
e
Nd
V
Vfb
kB
This theory predicts that a Mott–Schottky plot will be linear. The doping density
Nd
V
Under an applied potential
V
w=(
2\epsilon\epsilon0 | |
eNd |
(V-Vfb)
| ||||
) |
Using the abrupt approximation,[2] all charge carriers except the ionized dopants have left the depletion region, so the charge density in the depletion region is
eNd
Q=eNdAw=eNdA(
2\epsilon\epsilon0 | |
eNd |
(V-Vfb)
| ||||
) |
Thus, the differential capacitance is
C=
\partial{Q | |
which is equivalent to the Mott-Schottky equation, save for the temperature term. In fact the temperature term arises from a more careful analysis, which takes statistical mechanics into account by abandoning the abrupt approximation and solving the Poisson–Boltzmann equation for the charge density in the depletion region.[2]