Moore plane explained

In mathematics, the Moore plane, also sometimes called Niemytzki plane (or Nemytskii plane, Nemytskii's tangent disk topology), is a topological space. It is a completely regular Hausdorff space (that is, a Tychonoff space) that is not normal. It is an example of a Moore space that is not metrizable. It is named after Robert Lee Moore and Viktor Vladimirovich Nemytskii.

Definition

If

\Gamma

is the (closed) upper half-plane

\Gamma=\{(x,y)\in\R2|y\geq0\}

, then a topology may be defined on

\Gamma

by taking a local basis

l{B}(p,q)

as follows:

(x,y)

with

y>0

are the open discs in the plane which are small enough to lie within

\Gamma

.

p=(x,0)

are sets

\{p\}\cupA

where A is an open disc in the upper half-plane which is tangent to the x axis at p.

That is, the local basis is given by

l{B}(p,q)=\begin{cases}\{U\epsilon(p,q):=\{(x,y):(x-p)2+(y-q)2<\epsilon2\}\mid\epsilon>0\},&ifq>0;\\{V\epsilon(p):=\{(p,0)\}\cup\{(x,y):(x-p)2+(y-\epsilon)2<\epsilon2\}\mid\epsilon>0\},&ifq=0.\end{cases}

Thus the subspace topology inherited by

\Gamma\backslash\{(x,0)|x\in\R\}

is the same as the subspace topology inherited from the standard topology of the Euclidean plane.

Properties

\Gamma

is separable, that is, it has a countable dense subset.

\{(x,0)\in\Gamma|x\inR\}

of

\Gamma

has, as its subspace topology, the discrete topology. Thus, the Moore plane shows that a subspace of a separable space need not be separable.

Proof that the Moore plane is not normal

The fact that this space

\Gamma

is not normal can be established by the following counting argument (which is very similar to the argument that the Sorgenfrey plane is not normal):
  1. On the one hand, the countable set

S:=\{(p,q)\inQ x Q:q>0\}

of points with rational coordinates is dense in

\Gamma

; hence every continuous function

f:\Gamma\toR

is determined by its restriction to

S

, so there can be at most

|R||S|=

\aleph0
2
many continuous real-valued functions on

\Gamma

.
  1. On the other hand, the real line

L:=\{(p,0):p\inR\}

is a closed discrete subspace of

\Gamma

with
\aleph0
2
many points. So there are
\aleph0
2
2

>

\aleph0
2
many continuous functions from L to

R

. Not all these functions can be extended to continuous functions on

\Gamma

.
  1. Hence

\Gamma

is not normal, because by the Tietze extension theorem all continuous functions defined on a closed subspace of a normal space can be extended to a continuous function on the whole space.

In fact, if X is a separable topological space having an uncountable closed discrete subspace, X cannot be normal.

See also

References