Moore plane explained
In mathematics, the Moore plane, also sometimes called Niemytzki plane (or Nemytskii plane, Nemytskii's tangent disk topology), is a topological space. It is a completely regular Hausdorff space (that is, a Tychonoff space) that is not normal. It is an example of a Moore space that is not metrizable. It is named after Robert Lee Moore and Viktor Vladimirovich Nemytskii.
Definition
If
is the (closed) upper half-plane
\Gamma=\{(x,y)\in\R2|y\geq0\}
, then a
topology may be defined on
by taking a local basis
as follows:
- Elements of the local basis at points
with
are the open discs in the plane which are small enough to lie within
.
- Elements of the local basis at points
are sets
where
A is an open disc in the upper half-plane which is tangent to the
x axis at
p.
That is, the local basis is given by
l{B}(p,q)=\begin{cases}\{U\epsilon(p,q):=\{(x,y):(x-p)2+(y-q)2<\epsilon2\}\mid\epsilon>0\},&ifq>0;\ \{V\epsilon(p):=\{(p,0)\}\cup\{(x,y):(x-p)2+(y-\epsilon)2<\epsilon2\}\mid\epsilon>0\},&ifq=0.\end{cases}
Thus the subspace topology inherited by
\Gamma\backslash\{(x,0)|x\in\R\}
is the same as the subspace topology inherited from the standard topology of the Euclidean plane.
Properties
is
separable, that is, it has a countable dense subset.
of
has, as its
subspace topology, the
discrete topology. Thus, the Moore plane shows that a subspace of a separable space need not be separable.
Proof that the Moore plane is not normal
The fact that this space
is not
normal can be established by the following counting argument (which is very similar to the argument that the
Sorgenfrey plane is not normal):
- On the one hand, the countable set
of points with rational coordinates is dense in
; hence every continuous function
is determined by its restriction to
, so there can be at most
many continuous real-valued functions on
.
- On the other hand, the real line
is a closed discrete subspace of
with
many points. So there are
many continuous functions from
L to
. Not all these functions can be extended to continuous functions on
.
- Hence
is not normal, because by the
Tietze extension theorem all continuous functions defined on a closed subspace of a normal space can be extended to a continuous function on the whole space.
In fact, if X is a separable topological space having an uncountable closed discrete subspace, X cannot be normal.
See also
References
- Stephen Willard. General Topology, (1970) Addison-Wesley .
- (Example 82)