Molybdenum(V) fluoride explained

Molybdenum(V) fluoride is an inorganic compound with the formula MoF5. It is a hygroscopic yellow solid. Like most pentafluorides, it exists as a tetramer.[1]

Production

Molybdenum(V) fluoride is produced by the reaction of molybdenum and molybdenum hexafluoride:[2]

Mo + 5 MoF6 → 6 MoF5It can also be prepared by the reduction of molybdenum hexafluoride with phosphorus trifluoride or tungsten hexacarbonyl, or by the oxidation of elemental molybdenum with fluorine at 900 °C.

About 165 °C, it disproportionates to the tetra- and hexafluoride:[3]

2 MoF5 → MoF4 + MoF6

References

  1. 10.1039/J19690000909. Crystal Structure of tungsten pentafluoride. J. Chem. Soc. A. 909. 1969. Edwards. A. J..
  2. Book: T. J. Ouellette, C. T. Ratcliffe, D. W. A. Sharp, A. M. Steven. Molybdenum(V) Fluoride (Molybdenum pentalfluoride). Molybdenum(V) Fluoride (Molybdenum Pentafluoride). Inorganic Syntheses. 13. 1972. 146–150. 10.1002/9780470132449.ch28. 9780470132449.
  3. Stene. Riane E.. Scheibe. Benjamin. Pietzonka. Clemens. Karttunen. Antti J.. Petry. Winfried. Kraus. Florian. MoF5 revisited. A comprehensive study of MoF5. Journal of Fluorine Chemistry. 211. 2018. 171–179. 0022-1139. 10.1016/j.jfluchem.2018.05.002. 103463040 .

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