| Meduza Island | |
| Map: | Antarctica#Antarctic Peninsula |
| Map Relief: | yes |
| Location: | Antarctica |
| Coordinates: | -65.0256°N -64.0847°W |
| Archipelago: | Wilhelm Archipelago |
| Area Ha: | 11.9 |
| Length M: | 670 |
| Width M: | 434 |
| Population: | uninhabited |
| Country: | None |
| Treaty System: | Antarctic Treaty System |
Meduza Island (Bulgarian: остров Медуза|ostrov Meduza, in Bulgarian pronounced as /ˈɔstrof mɛˈduzɐ/) is the partly ice-covered island extending 670 m in southwest–northeast direction and 434 m in north–south direction in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 11.9 ha.[1]
The feature is so named because of its shape supposedly resembling a jellyfish ('meduza' in Bulgarian), and in association with other descriptive names of islands in the area.[1]
Meduza Island is located at -65.0256°N -64.0847°W, which is 3.18 km southwest of Kosatka Island, 509 m west-northwest of Greblo Island, 2.33 km northwest of Rollet Island, 1.26 km east-northeast of Yastreb Island and 1.4 km southeast of Tyulen Island. British mapping in 2001.
