Mazeppa (1909 film) explained

Mazeppa
Native Name:	ru|Мазепа
Director:	Vasili Goncharov
Producer:	Aleksandr Khanzhonkov
Cinematography:	Vladimir Siversen
Country:	Russian Empire
Language:	Russian

Mazeppa (ru|Мазепа) is a 1909 Russian drama film directed by Vasili Goncharov.^{[1] [2] [3] [4]}

Plot

The film tells about the Hetman named Mazepa, who is in love with Kochubey's daughter, Maria, and asks her father for consent to marry her, but his father refuses him. This does not stop them and they run away...^[5]

Cast

• Vasili Stepanov as Kochubey
• Andrey Gromov as Mazepa
• Raisa Reyzen as Maria
• Antonina Pozharskaya as Maria's mother^[6]

Notes and References

1. http://www.stoletie.ru/kultura/uznaj_po_krajnej_mere_zvuki_429.htm «Узнай, по крайней мере, звуки…»
2. http://www.proficinema.ru/news/detail.php?ID=124839 ПУШКИН И КИНО
3. https://worldnewsage.com/ru/kultura/v_moskve_umer_akter_nikolay_penkov1261547445 В Москве умер актер Николай Пеньков
4. https://www.perm.kp.ru/daily/24415/588342/ Ушел из жизни Николай Пеньков
5. https://www.kinopoisk.ru/film/41605/ Мазепа
6. https://www.imdb.com/title/tt0347516/fullcredits/?ref_=tt_ov_st_sm Мазепа (1909) Full Cast & Crew