May 1985 lunar eclipse explained

Type:total
Date:4 May 1985
Axis:0.3593°
Gamma:0.35197
Magnitude:1.23687
Saros Ser:121
Saros No:54 of 84
Totality:67 minutes, 41.5 seconds
Partiality:198 minutes, 57.6 seconds
Penumbral:310 minutes, 20.4 seconds
P1:17:21:14.4
U1:18:16:54.8
U2:19:22:33.0
Greatest:19:56:24.1
U3:20:30:14.5
U4:21:35:52.4
P4:22:31:34.8
Previous:November 1984
Next:October 1985

A total lunar eclipse took place on Saturday, May 4, 1985, the first of two total lunar eclipses in 1985, the second being on October 28, 1985.[1]

This lunar eclipse is the first of a tetrad, four total lunar eclipses in series. The last series was in 1967 and 1968, starting with an April 1967 lunar eclipse, while the next was in 2003 and 2004, starting with a May 2003 lunar eclipse.

Visibility

It is seen rising over the whole of Africa, Middle East, Europe and Asia. The eclipse was sighted over the Philippines at night. The second also followed on October 28, 1985.

Related eclipses

Eclipses of 1985

Metonic series

This eclipse is the second of four Metonic cycle lunar eclipses on the same date, May 4–5, each separated by 19 years:

Saros series

It is a member of Saros cycle 121.

Half-Saros cycle

A lunar eclipse will be preceded and followed by solar eclipses by 9 years and 5.5 days (a half saros).[2] This lunar eclipse is related to two annular solar eclipses of Solar Saros 128.

See also

Notes and References

  1. http://www.hermit.org/Eclipse/gen_stats.cgi?mode=query&page=full&qtype=type&body=L&saros=121 Hermit Eclipse: Saros cycle 121
  2. Mathematical Astronomy Morsels, Jean Meeus, p.110, Chapter 18, The half-saros