1967 Mauritian general election explained

General elections were held in Mauritius on 7 August 1967. Ethnic violence broke out in Port Louis between Muslims, Creoles and Chinese. Anti-riot police used tear gas to restore peace.[1] [2]

The result was a victory for the Independence Party, an alliance of the Labour Party, Independent Forward Bloc and Comité d'Action Musulman, won 43 of the 70 seats,[3] allowing Labour leader and incumbent Prime Minister Seewoosagur Ramgoolam to form a government. Voter turnout was 89%.[4]

Electoral system

The voting system created twenty constituencies on Mauritius, which each elected three members. Two seats were elected by residents of Rodrigues, and eight seats were filled by a system known as "best losers" whereby the electoral commission would appoint eight unsuccessful candidates to ensure that ethnic minorities were fairly represented.[5]

Results

The Independence Party consisted of the Labour Party (26 seats), the Independent Forward Bloc (12 seats) and the Muslim Committee of Action (5 seats).

Notes and References

  1. Web site: Mauritius: 1967 Legislative Assembly election . EISA . 2021-07-11.
  2. Web site: Port Louis – Rioting against Independence at the General Elections of 1967 . Vintage Mauritius . 2021-07-11.
  3. [Dieter Nohlen]
  4. http://www.eisa.org.za/wep/mau1967results.htm Mauritius: 1967 Legislative Assembly election results overview
  5. http://www.eisa.org.za/wep/mau1967background.htm Mauritius: Background to the 1967 Legislative Assembly election