Markov–Kakutani fixed-point theorem explained

In mathematics, the Markov–Kakutani fixed-point theorem, named after Andrey Markov and Shizuo Kakutani, states that a commuting family of continuous affine self-mappings of a compact convex subset in a locally convex topological vector space has a common fixed point. This theorem is a key tool in one of the quickest proofs of amenability of abelian groups.

Statement

Let

X

be a locally convex topological vector space, with a compact convex subset

K

. Let

S

be a family of continuous mappings of

K

to itself which commute and are affine, meaning that

T(λx+(1-λ)y)=λT(x)+(1-λ)T(y)

for all

λ

in

(0,1)

and

T

in

S

. Then the mappings in

S

share a fixed point.

Proof for a single affine self-mapping

Let

T

be a continuous affine self-mapping of

K

.

For

x

in

K

define a net

\{x(N)\}N\inN

in

K

by

x(N)={1\over

N
N+1}\sum
n=0

Tn(x).

Since

K

is compact, there is a convergent subnet in

K

:

x(Ni)y.

To prove that

y

is a fixed point, it suffices to show that

f(Ty)=f(y)

for every

f

in the dual of

X

. (The dual separates points by the Hahn-Banach theorem; this is where the assumption of local convexity is used.)

Since

K

is compact,

|f|

is bounded on

K

by a positive constant

M

. On the other hand

|f(Tx(N))-f(x(N))|={1\overN+1}|f(TN+1x)-f(x)|\le{2M\overN+1}.

Taking

N=Ni

and passing to the limit as

i

goes to infinity, it follows that

f(Ty)=f(y).

Hence

Ty=y.

Proof of theorem

The set of fixed points of a single affine mapping

T

is a non-empty compact convex set

KT

by the result for a single mapping. The other mappings in the family

S

commute with

T

so leave

KT

invariant. Applying the result for a single mapping successively, it follows that any finite subset of

S

has a non-empty fixed point set given as the intersection of the compact convex sets

KT

as

T

ranges over the subset. From the compactness of

K

it follows that the set

KS=\{y\inK\midTy=y,T\inS\}=capT\inKT

is non-empty (and compact and convex).