Locally finite operator explained
is called
locally finite if the
space
is the union of a family of finite-dimensional
-
invariant subspaces.
[1] [2] In other words, there exists a family
of linear subspaces of
, such that we have the following:
(\foralli\inI)f[Vi]\subseteqVi
is finite-dimensional.
An equivalent condition only requires
to be the spanned by finite-dimensional
-invariant subspaces.
[3] [4] If
is also a
Hilbert space, sometimes an operator is called locally finite when the sum of the
is only
dense in
.
Examples
- Every linear operator on a finite-dimensional space is trivially locally finite.
- Every diagonalizable (i.e. there exists a basis of
whose elements are all
eigenvectors of
) linear operator is locally finite, because it is the union of subspaces spanned by finitely many eigenvectors of
.
, the space of polynomials with complex coefficients, defined by
, is
not locally finite; any
-invariant subspace is of the form
for some
, and so has infinite dimension.
defined by
is locally finite; for any
, the polynomials of
degree at most
form a
-invariant subspace.
[5] Notes and References
- Central Simple Poisson Algebras. Yucai Su. Xiaoping Xu. math/0011086v1. 2000.
- Book: Time-Varying Systems and Computations. Patrick. DeWilde. Alle-Jan. van der Veen. Springer Science+Business Media, B.V.. 978-1-4757-2817-0. 10.1007/978-1-4757-2817-0. 1998. Dordrecht.
- Operators on Hopf Algebras. David E.. Radford. American Journal of Mathematics. Feb 1977. 99. 1. 139–158. Johns Hopkins University Press. 10.2307/2374012 . 2374012.
- On the Riccati Equations of the H∞ Control Problem for Discrete Time-Varying Systems. Jacquelien. Scherpen. Michel . Verhaegen. 3rd European Control Conference (Rome, Italy). September 1995. 10.1.1.867.5629 .
- https://math.stackexchange.com/users/431940/joppy Joppy