Lie bialgebroid explained

In differential geometry, a field in mathematics, a Lie bialgebroid consists of two compatible Lie algebroids defined on dual vector bundles. Lie bialgebroids are the vector bundle version of Lie bialgebras.

Definition

Preliminary notions

A Lie algebroid consists of a bilinear skew-symmetric operation

[,]

on the sections

\Gamma(A)

of a vector bundle

A\toM

over a smooth manifold

M

, together with a vector bundle morphism

\rho:A\toTM

subject to the Leibniz rule

[\phi,f\psi]=\rho(\phi)[f]\psi+f[\phi,\psi],

and Jacobi identity

[\phi,[\psi1,\psi2]]=[[\phi,\psi1],\psi2]+[\psi1,[\phi,\psi2]]

where

\phi,\psik

are sections of

A

and

f

is a smooth function on

M

.

The Lie bracket

[,]A

can be extended to multivector fields

\Gamma(\wedgeA)

graded symmetric via the Leibniz rule

[\Phi\wedge\Psi,\Chi]A=\Phi\wedge[\Psi,\Chi]A+(-1)|\Psi|(|\Chi|-1)[\Phi,\Chi]A\wedge\Psi

for homogeneous multivector fields

\phi,\psi,X

.

The Lie algebroid differential is an

R

-linear operator

dA

on the

A

-forms

\OmegaA(M)=\Gamma(\wedgeA*)

of degree 1 subject to the Leibniz rule

dA(\alpha\wedge\beta)=(dA\alpha)\wedge\beta+(-1)|\alpha|\alpha\wedgedA\beta

for

A

-forms

\alpha

and

\beta

. It is uniquely characterized by the conditions

(dAf)(\phi)=\rho(\phi)[f]

and

(dA\alpha)[\phi,\psi]=\rho(\phi)[\alpha(\psi)]-\rho(\psi)[\alpha(\phi)]-\alpha[\phi,\psi]

for functions

f

on

M

,

A

-1-forms

\alpha\in\Gamma(A*)

and

\phi,\psi

sections of

A

.

The definition

A Lie bialgebroid consists of two Lie algebroids

(A,\rhoA,[,]A)

and
*,\rho
(A
*,[,]

*)

on the dual vector bundles

A\toM

and

A*\toM

, subject to the compatibility

d*[\phi,\psi]A=[d*\phi,\psi]A+[\phi,d*\psi]A

for all sections

\phi,\psi

of

A

. Here

d*

denotes the Lie algebroid differential of

A*

which also operates on the multivector fields

\Gamma(\wedgeA)

.

Symmetry of the definition

It can be shown that the definition is symmetric in

A

and

A*

, i.e.

(A,A*)

is a Lie bialgebroid if and only if

(A*,A)

is.

Examples

  1. A Lie bialgebra consists of two Lie algebras

(ak{g},[ ⋅, ⋅ ]ak{g

}) and
*,[,]
(ak{g}
*)
on dual vector spaces

ak{g}

and

ak{g}*

such that the Chevalley–Eilenberg differential

\delta*

is a derivation of the

ak{g}

-bracket.
  1. A Poisson manifold

(M,\pi)

gives naturally rise to a Lie bialgebroid on

TM

(with the commutator bracket of tangent vector fields) and

T*M

(with the Lie bracket induced by the Poisson structure). The

T*M

-differential is

d*=[\pi,]

and the compatibility follows then from the Jacobi identity of the Schouten bracket.

Infinitesimal version of a Poisson groupoid

It is well known that the infinitesimal version of a Lie groupoid is a Lie algebroid (as a special case, the infinitesimal version of a Lie group is a Lie algebra). Therefore, one can ask which structures need to be differentiated in order to obtain a Lie bialgebroid.

Definition of Poisson groupoid

A Poisson groupoid is a Lie groupoid

G\rightrightarrowsM

together with a Poisson structure

\pi

on

G

such that the graph

m\subsetG x G x (G,-\pi)

of the multiplication map is coisotropic. An example of a Poisson-Lie groupoid is a Poisson-Lie group (where

M

is a point). Another example is a symplectic groupoid (where the Poisson structure is non-degenerate on

TG

).

Differentiation of the structure

Remember the construction of a Lie algebroid from a Lie groupoid. We take the

t

-tangent fibers (or equivalently the

s

-tangent fibers) and consider their vector bundle pulled back to the base manifold

M

. A section of this vector bundle can be identified with a

G

-invariant

t

-vector field on

G

which form a Lie algebra with respect to the commutator bracket on

TG

.

We thus take the Lie algebroid

A\toM

of the Poisson groupoid. It can be shown that the Poisson structure induces a fiber-linear Poisson structure on

A

. Analogous to the construction of the cotangent Lie algebroid of a Poisson manifold there is a Lie algebroid structure on

A*

induced by this Poisson structure. Analogous to the Poisson manifold case one can show that

A

and

A*

form a Lie bialgebroid.

Double of a Lie bialgebroid and superlanguage of Lie bialgebroids

For Lie bialgebras

(ak{g},ak{g}*)

there is the notion of Manin triples, i.e.

c=ak{g}+ak{g}*

can be endowed with the structure of a Lie algebra such that

ak{g}

and

ak{g}*

are subalgebras and

c

contains the representation of

ak{g}

on

ak{g}*

, vice versa. The sum structure is just

[X+\alpha,Y+\beta]=[X,Y]g+ad\alphaY-ad\betaX +[\alpha,\beta]*

*
+ad
X\beta
*
-ad
Y\alpha

.

Courant algebroids

It turns out that the naive generalization to Lie algebroids does not give a Lie algebroid any more. Instead one has to modify either the Jacobi identity or violate the skew-symmetry and is thus lead to Courant algebroids.[1]

Superlanguage

The appropriate superlanguage of a Lie algebroid

A

is

\PiA

, the supermanifold whose space of (super)functions are the

A

-forms. On this space the Lie algebroid can be encoded via its Lie algebroid differential, which is just an odd vector field.

As a first guess the super-realization of a Lie bialgebroid

(A,A*)

should be

\PiA+\PiA*

. But unfortunately

dA+d*|\PiA+\PiA*

is not a differential, basically because

A+A*

is not a Lie algebroid. Instead using the larger N-graded manifold

T*[2]A[1]=T*[2]A*[1]

to which we can lift

dA

and

d*

as odd Hamiltonian vector fields, then their sum squares to

0

iff

(A,A*)

is a Lie bialgebroid.

References

Notes and References

  1. Z.-J. Liu, A. Weinstein and P. Xu: Manin triples for Lie bialgebroids, Journ. of diff. geom. vol. 45, pp. 547–574 (1997)