Lie bialgebroid explained
In differential geometry, a field in mathematics, a Lie bialgebroid consists of two compatible Lie algebroids defined on dual vector bundles. Lie bialgebroids are the vector bundle version of Lie bialgebras.
Definition
Preliminary notions
A Lie algebroid consists of a bilinear skew-symmetric operation
on the sections
of a
vector bundle
over a smooth manifold
, together with a vector bundle morphism
subject to the Leibniz rule
[\phi,f ⋅ \psi]=\rho(\phi)[f] ⋅ \psi+f ⋅ [\phi,\psi],
and Jacobi identity
[\phi,[\psi1,\psi2]]=[[\phi,\psi1],\psi2]+[\psi1,[\phi,\psi2]]
where
are sections of
and
is a smooth function on
.
The Lie bracket
can be extended to multivector fields
graded symmetric via the Leibniz rule[\Phi\wedge\Psi,\Chi]A=\Phi\wedge[\Psi,\Chi]A+(-1)|\Psi|(|\Chi|-1)[\Phi,\Chi]A\wedge\Psi
for homogeneous multivector fields
.
The Lie algebroid differential is an
-linear operator
on the
-forms \OmegaA(M)=\Gamma(\wedgeA*)
of degree 1 subject to the Leibniz ruledA(\alpha\wedge\beta)=(dA\alpha)\wedge\beta+(-1)|\alpha|\alpha\wedgedA\beta
for
-forms
and
. It is uniquely characterized by the conditions
(dAf)(\phi)=\rho(\phi)[f]
and
(dA\alpha)[\phi,\psi]=\rho(\phi)[\alpha(\psi)]-\rho(\psi)[\alpha(\phi)]-\alpha[\phi,\psi]
for functions
on
,
-1-forms
and
sections of
.
The definition
A Lie bialgebroid consists of two Lie algebroids
and
on the dual vector bundles
and
, subject to the compatibilityd*[\phi,\psi]A=[d*\phi,\psi]A+[\phi,d*\psi]A
for all sections
of
. Here
denotes the Lie algebroid differential of
which also operates on the multivector fields
.
Symmetry of the definition
It can be shown that the definition is symmetric in
and
, i.e.
is a Lie bialgebroid if and only if
is.Examples
- A Lie bialgebra consists of two Lie algebras
})
and
on dual vector spaces
and
such that the Chevalley–Eilenberg differential
is a derivation of the
-bracket.- A Poisson manifold
gives naturally rise to a Lie bialgebroid on
(with the commutator bracket of tangent vector fields) and
(with the Lie bracket induced by the Poisson structure). The
-differential is
and the compatibility follows then from the Jacobi identity of the Schouten bracket.Infinitesimal version of a Poisson groupoid
It is well known that the infinitesimal version of a Lie groupoid is a Lie algebroid (as a special case, the infinitesimal version of a Lie group is a Lie algebra). Therefore, one can ask which structures need to be differentiated in order to obtain a Lie bialgebroid.
Definition of Poisson groupoid
A Poisson groupoid is a Lie groupoid
together with a Poisson structure
on
such that the graph
of the multiplication map is coisotropic. An example of a Poisson-Lie groupoid is a Poisson-Lie group (where
is a point). Another example is a symplectic groupoid (where the Poisson structure is non-degenerate on
).Differentiation of the structure
Remember the construction of a Lie algebroid from a Lie groupoid. We take the
-tangent fibers (or equivalently the
-tangent fibers) and consider their vector bundle pulled back to the base manifold
. A section of this vector bundle can be identified with a
-invariant
-vector field on
which form a Lie algebra with respect to the commutator bracket on
.We thus take the Lie algebroid
of the Poisson groupoid. It can be shown that the Poisson structure induces a fiber-linear Poisson structure on
. Analogous to the construction of the cotangent Lie algebroid of a Poisson manifold there is a Lie algebroid structure on
induced by this Poisson structure. Analogous to the Poisson manifold case one can show that
and
form a Lie bialgebroid.Double of a Lie bialgebroid and superlanguage of Lie bialgebroids
For Lie bialgebras
there is the notion of Manin triples, i.e.
can be endowed with the structure of a Lie algebra such that
and
are subalgebras and
contains the representation of
on
, vice versa. The sum structure is just[X+\alpha,Y+\beta]=[X,Y]g+ad\alphaY-ad\betaX
+[\alpha,\beta]*
.
Courant algebroids
It turns out that the naive generalization to Lie algebroids does not give a Lie algebroid any more. Instead one has to modify either the Jacobi identity or violate the skew-symmetry and is thus lead to Courant algebroids.[1]
Superlanguage
The appropriate superlanguage of a Lie algebroid
is
, the supermanifold whose space of (super)functions are the
-forms. On this space the Lie algebroid can be encoded via its Lie algebroid differential, which is just an odd vector field.As a first guess the super-realization of a Lie bialgebroid
should be
. But unfortunately
is not a differential, basically because
is not a Lie algebroid. Instead using the larger N-graded manifold
to which we can lift
and
as odd Hamiltonian vector fields, then their sum squares to
iff
is a Lie bialgebroid.References
- C. Albert and P. Dazord: Théorie des groupoïdes symplectiques: Chapitre II, Groupoïdes symplectiques. (in Publications du Département de Mathématiques de l’Université Claude Bernard, Lyon I, nouvelle série, pp. 27–99, 1990)
- Y. Kosmann-Schwarzbach: The Lie bialgebroid of a Poisson–Nijenhuis manifold. (Lett. Math. Phys., 38:421–428, 1996)
- K. Mackenzie, P. Xu: Integration of Lie bialgebroids (1997),
- K. Mackenzie, P. Xu: Lie bialgebroids and Poisson groupoids (Duke J. Math, 1994)
- A. Weinstein: Symplectic groupoids and Poisson manifolds (AMS Bull, 1987),
Notes and References
- Z.-J. Liu, A. Weinstein and P. Xu: Manin triples for Lie bialgebroids, Journ. of diff. geom. vol. 45, pp. 547–574 (1997)