Kleiman's theorem explained

In algebraic geometry, Kleiman's theorem, introduced by, concerns dimension and smoothness of scheme-theoretic intersection after some perturbation of factors in the intersection.

Precisely, it states: given a connected algebraic group G acting transitively on an algebraic variety X over an algebraically closed field k and

Vi\toX,i=1,2

morphisms of varieties, G contains a nonempty open subset such that for each g in the set,
  1. either

gV1 x XV2

is empty or has pure dimension

\dimV1+\dimV2-\dimX

, where

gV1

is

V1\toX\overset{g}\toX

,
  1. (Kleiman–Bertini theorem) If

Vi

are smooth varieties and if the characteristic of the base field k is zero, then

gV1 x XV2

is smooth.

Statement 1 establishes a version of Chow's moving lemma: after some perturbation of cycles on X, their intersection has expected dimension.

Sketch of proof

We write

fi

for

Vi\toX

. Let

h:G x V1\toX

be the composition that is

(1G,f1):G x V1\toG x X

followed by the group action

\sigma:G x X\toX

.

Let

\Gamma=(G x V1) x XV2

be the fiber product of

h

and

f2:V2\toX

; its set of closed points is

\Gamma=\{(g,v,w)|g\inG,v\inV1,w\inV2,gf1(v)=f2(w)\}

.We want to compute the dimension of

\Gamma

. Let

p:\Gamma\toV1 x V2

be the projection. It is surjective since

G

acts transitively on X. Each fiber of p is a coset of stabilizers on X and so

\dim\Gamma=\dimV1+\dimV2+\dimG-\dimX

.Consider the projection

q:\Gamma\toG

; the fiber of q over g is

gV1 x XV2

and has the expected dimension unless empty. This completes the proof of Statement 1.

For Statement 2, since G acts transitively on X and the smooth locus of X is nonempty (by characteristic zero), X itself is smooth. Since G is smooth, each geometric fiber of p is smooth and thus

p0:\Gamma0:=(G x V1,) x XV2,\toV1, x V2,

is a smooth morphism. It follows that a general fiber of

q0:\Gamma0\toG

is smooth by generic smoothness.

\square