Kirkman's schoolgirl problem explained

Kirkman's schoolgirl problem is a problem in combinatorics proposed by Thomas Penyngton Kirkman in 1850 as Query VI in The Lady's and Gentleman's Diary (pg.48). The problem states:

Fifteen young ladies in a school walk out three abreast for seven days in succession: it is required to arrange them daily so that no two shall walk twice abreast.

Solutions

A solution to this problem is an example of a Kirkman triple system, which is a Steiner triple system having a parallelism, that is, a partition of the blocks of the triple system into parallel classes which are themselves partitions of the points into disjoint blocks. Such Steiner systems that have a parallelism are also called resolvable.

There are exactly seven non-isomorphic solutions to the schoolgirl problem, as originally listed by Frank Nelson Cole in Kirkman Parades in 1922. The seven solutions are summarized in the table below, denoting the 15 girls with the letters A to O.

Solution classAutomorphism groupDay 1Day 2Day 3Day 4Day 5Day 6Day 7
Solution Ialign='center'Order 168, generated by
(A K G E I L B)(C H M J N O D)
and
(A M L K O C D)(B H N G I E J).
Related to PG(3,2).
align='center'ABC
DEF
GHI
JKL
MNO
align='center'ADG
BEH
CJM
FKN
ILO
align='center'AEO
BIJ
CDN
FHL
GKM
align='center'AIM
BDL
CEK
FGO
HJN
align='center'AFJ
BKO
CGL
DHM
EIN
align='center'AHK
BGN
CFI
DJO
ELM
align='center'ALN
BFM
CHO
DIK
EGJ
Solution IIalign='center'Order 168, generated by
(A B I M F C J)(D N H K O L E)
and
(A J M I B F C)(D H G N K E O).
Related to PG(3,2).
align='center'ABC
DEF
GHI
JKL
MNO
align='center'ADG
BEH
CJM
FKN
ILO
align='center'AEO
BIJ
CDN
FHL
GKM
align='center'AFJ
BGN
CHO
DIK
ELM
align='center'AHK
BFM
CGL
DJO
EIN
align='center'AIM
BDL
CEK
FGO
HJN
align='center'ALN
BKO
CFI
DHM
EGJ
Solution IIIalign='center'Order 24, generated by
(A H E)(B O K)(C F I)(D J L)(G N M)
and
(A J B M)(D L E O)(F I)(G K H N)
align='center'ABC
DEF
GHI
JKL
MNO
align='center'ADG
BEH
CJM
FKN
ILO
align='center'AEO
BIM
CDK
FGL
HJN
align='center'AFM
BGN
CHL
DJO
EIK
align='center'AHK
BFJ
CGO
DIN
ELM
align='center'AIJ
BDL
CEN
FHO
GKM
align='center'ALN
BKO
CFI
DHM
EGJ
Solution IValign='center'Order 24, generated by
(A J M)(C F I)(D E K)(H O L)
and
(A L B O)(C I)(D K E N)(G J H M)
align='center'ABC
DEF
GHI
JKL
MNO
align='center'ADG
BEH
CJM
FKN
ILO
align='center'AEO
BIM
CDK
FGL
HJN
align='center'AFM
BKO
CHL
DIN
EGJ
align='center'AHK
BGN
CFI
DJO
ELM
align='center'AIJ
BDL
CEN
FHO
GKM
align='center'ALN
BFJ
CGO
DHM
EIK
Solution Valign='center'Tetrahedral group of order 12,
generated by
(A L)(B G)(E O)(F J)(H K)(I M)
and
(A B C)(D L G)(F J I)(E K H)
align='center'ABC
DEF
GHI
JKL
MNO
align='center'ADG
BEJ
CHM
FKN
ILO
align='center'AEM
BDL
CIK
FGO
HJN
align='center'AFH
BKM
CGL
DJO
EIN
align='center'AIJ
BGN
CEO
DHK
FLM
align='center'AKO
BFI
CDN
EHL
GJM
align='center'ALN
BHO
CFJ
DIM
EGK
Solution VIalign='center'Tetrahedral group of order 12,
generated by
(A L)(B G)(E O)(H K)(F J)(I M)
and
(A B C)(D L G)(E K H)(F J I)
align='center'ABC
DEF
GHI
JKL
MNO
align='center'ADG
BEJ
CHM
FKN
ILO
align='center'AEM
BDL
CIK
FGO
HJN
align='center'AFH
BKM
CGL
DJO
EIN
align='center'AIJ
BHO
CDN
EGK
FLM
align='center'AKO
BGN
CFJ
DIM
EHL
align='center'ALN
BFI
CEO
DHK
GJM
Solution VIIalign='center'Order 21, generated by
(A B L C G D N)(E H K I O J F)
and
(B G L)(C D N)(E F K)(H I O)
align='center'ABC
DEF
GHI
JKL
MNO
align='center'ADG
BEJ
CHM
FKN
ILO
align='center'AEI
BDN
CJO
FHL
GKM
align='center'AFO
BIK
CGN
DHJ
ELM
align='center'AHK
BFM
CDL
EGO
IJN
align='center'AJM
BGL
CFI
DKO
EHN
align='center'ALN
BHO
CEK
FGJ
DIM

From the number of automorphisms for each solution and the definition of an automorphism group, the total number of solutions including isomorphic solutions is therefore:

15! x \left(

1
168

+

1
168

+

1
24

+

1
24

+

1
12

+

1
12

+

1
21

\right)

=15! x

13
42

=404,756,352,000

=210 x 35 x 53 x 7 x 11 x 132

.

History

The problem has a long and storied history. This section is based on historical work done at different times by Robin Wilson[1] and by Louise Duffield Cummings. The history is as follows:

455=13 x 35

. In words, is it possible for the girls to march every day for 13 weeks, such that every two girls march together exactly once each week and every three girls march together exactly once in the term of 13 weeks? This problem was much harder, and a computational solution would finally be provided in 1974 by RHF Denniston (see below).

Sylvester's problem

James Joseph Sylvester in 1850 asked if 13 disjoint Kirkman systems of 35 triples each could be constructed to use all = 455 triples on 15 girls. No solution was found until 1974 when RHF Denniston at the University of Leicester constructed it with a computer. Denniston's insight was to create a single-week Kirkman solution in such a way that it could be permuted according to a specific permutation of cycle length 13 to create disjoint solutions for subsequent weeks; he chose a permutation with a single 13-cycle and two fixed points like (1 2 3 4 5 6 7 8 9 10 11 12 13)(14)(15). Under this permutation, a triple like 123 would map to 234, 345, ... (11, 12, 13), (12, 13, 1) and (13, 1, 2) before repeating. Denniston thus classified the 455 triples into 35 rows of 13 triples each, each row being the orbit of a given triple under the permutation. In order to construct a Sylvester solution, no single-week Kirkman solution could use two triples from the same row, otherwise they would eventually collide when the permutation was applied to one of them. Solving Sylvester's problem is equivalent to finding one triple from each of the 35 rows such that the 35 triples together make a Kirkman solution. He then asked an Elliott 4130 computer to do exactly that search, which took him 7 hours to find this first-week solution, labeling the 15 girls with the letters A to O:

Day 1 ABJ CEM FKL HIN DGO
Day 2 ACH DEI FGM JLN BKO
Day 3 ADL BHM GIK CFN EJO
Day 4 AEG BIL CJK DMN FHO
Day 5 AFI BCD GHJ EKN LMO
Day 6 AKM DFJ EHL BGN CIO
Day 7 BEF CGL DHK IJM ANO

He stopped the search at that point, not looking to establish uniqueness.

The American minimalist composer Tom Johnson composed a piece of music called Kirkman's Ladies based on Denniston's solution.[4] [5]

As of 2021, it is not known whether there are other non-isomorphic solutions to Sylvester's problem, or how many solutions there are.

9 schoolgirls and extensions

The equivalent of the Kirkman problem for 9 schoolgirls results in S(2,3,9), an affine plane isomorphic to the following triples on each day:

Day 1: 123 456 789
Day 2: 147 258 369
Day 3: 159 267 348
Day 4: 168 249 357

The corresponding Sylvester problem asks for 7 different S(2,3,9) systems of 12 triples each, together covering all = 84 triples. This solution was known to Bays (1917) which was found again from a different direction by Earl Kramer and Dale Mesner in a 1974 paper titled Intersections Among Steiner Systems (J Combinatorial Theory, Vol 16 pp 273-285). There can indeed be 7 disjoint S(2,3,9) systems, and all such sets of 7 fall into two non-isomorphic categories of sizes 8640 and 6720, with 42 and 54 automorphisms respectively.

Solution 1:
             Day 1          Day 2          Day 3          Day 4
Week 1    ABC.DEF.GHI    ADG.BEH.CFI    AEI.BFG.CDH    AFH.BDI.CEG
Week 2    ABD.CEH.FGI    ACF.BGH.DEI    AEG.BCI.DFH    AHI.BEF.CDG
Week 3    ABE.CDI.FGH    ACG.BDF.EHI    ADH.BGI.CEF    AFI.BCH.DEG
Week 4    ABF.CEI.DGH    ACD.BHI.EFG    AEH.BCG.DFI    AGI.BDE.CFH
Week 5    ABG.CDE.FHI    ACH.BEI.DFG    ADI.BCF.EGH    AEF.BDH.CGI
Week 6    ABH.CDF.EGI    ACI.BDG.EFH    ADE.BFI.CGH    AFG.BCE.DHI
Week 7    ABI.CFG.DEH    ACE.BFH.DGI    ADF.BEG.CHI    AGH.BCD.EFI
Solution 1 has 42 automorphisms, generated by the permutations (A I D C F H)(B G) and (C F D H E I)(B G). Applying the 9! = 362880 permutations of ABCDEFGHI, there are 362880/42 = 8640 different solutions all isomorphic to Solution 1.
Solution 2:
             Day 1          Day 2          Day 3          Day 4
Week 1    ABC.DEF.GHI    ADG.BEH.CFI    AEI.BFG.CDH    AFH.BDI.CEG
Week 2    ABD.CEH.FGI    ACF.BGH.DEI    AEG.BCI.DFH    AHI.BEF.CDG
Week 3    ABE.CGH.DFI    ACI.BFH.DEG    ADH.BGI.CEF    AFG.BCD.EHI
Week 4    ABF.CGI.DEH    ACE.BDG.FHI    ADI.BCH.EFG    AGH.BEI.CDF
Week 5    ABG.CDI.EFH    ACH.BDF.EGI    ADE.BHI.CFG    AFI.BCE.DGH
Week 6    ABH.CEI.DFG    ACD.BFI.EGH    AEF.BCG.DHI    AGI.BDE.CFH
Week 7    ABI.CDE.FGH    ACG.BDH.EFI    ADF.BEG.CHI    AEH.BCF.DGI
Solution 2 has 54 automorphisms, generated by the permutations (A B D)(C H E)(F G I) and (A I F D E H)(B G). Applying the 9! = 362880 permutations of ABCDEFGHI, there are 362880/54 = 6720 different solutions all isomorphic to Solution 2.

Thus there are 8640 + 6720 = 15360 solutions in total, falling into two non-isomorphic categories.

In addition to S(2,3,9), Kramer and Mesner examined other systems that could be derived from S(5,6,12) and found that there could be up to 2 disjoint S(5,6,12) systems, up to 2 disjoint S(4,5,11) systems, and up to 5 disjoint S(3,4,10) systems. All such sets of 2 or 5 are respectively isomorphic to each other.

Larger systems and continuing research

In the 21st century, analogues of Sylvester's problem have been visited by other authors under terms like "Disjoint Steiner systems" or "Disjoint Kirkman systems" or "LKTS" (Large Sets of Kirkman Triple Systems), for n > 15.[6] Similar sets of disjoint Steiner systems have also been investigated for the S(5,8,24) Steiner system in addition to triple systems.[7]

Galois geometry

In 1910 the problem was addressed using Galois geometry by George Conwell.[8]

The Galois field GF(2) with two elements is used with four homogeneous coordinates to form PG(3,2) which has 15 points, 3 points to a line, 7 points and 7 lines in a plane. A plane can be considered a complete quadrilateral together with the line through its diagonal points. Each point is on 7 lines, and there are 35 lines in all.

The lines of PG(3,2) are identified by their Plücker coordinates in PG(5,2) with 63 points, 35 of which represent lines of PG(3,2). These 35 points form the surface S known as the Klein quadric. For each of the 28 points off S there are 6 lines through it which do not intersect S.[8]

As there are seven days in a week, the heptad is an important part of the solution:A heptad is determined by any two of its points. Each of the 28 points off S lies in two heptads. There are 8 heptads. The projective linear group PGL(3,2) is isomorphic the alternating group on the 8 heptads.[8]

The schoolgirl problem consists in finding seven lines in the 5-space which do not intersect and such that any two lines always have a heptad in common.[8]

Spreads and packing

In PG(3,2), a partition of the points into lines is called a spread, and a partition of the lines into spreads is called a or . There are 56 spreads and 240 packings. When Hirschfeld considered the problem in his Finite Projective Spaces of Three Dimensions (1985), he noted that some solutions correspond to packings of PG(3,2), essentially as described by Conwell above, and he presented two of them.

Generalization

The problem can be generalized to

n

girls, where

n

must be an odd multiple of 3 (that is

n\equiv3\pmod{6}

), walking in triplets for \frac(n-1) days, with the requirement, again, that no pair of girls walk in the same row twice. The solution to this generalisation is a Steiner triple system, an S(2, 3, 6t + 3) with parallelism (that is, one in which each of the 6t + 3 elements occurs exactly once in each block of 3-element sets), known as a Kirkman triple system. It is this generalization of the problem that Kirkman discussed first, while the famous special case

n=15

was only proposed later. A complete solution to the general case was published by D. K. Ray-Chaudhuri and R. M. Wilson in 1968, though it had already been solved by Lu Jiaxi (Chinese: s=陆家羲) in 1965, but had not been published at that time.

Many variations of the basic problem can be considered. Alan Hartman solves a problem of this type with the requirement that no trio walks in a row of four more than once using Steiner quadruple systems.

More recently a similar problem known as the Social Golfer Problem has gained interest that deals with 32 golfers who want to get to play with different people each day in groups of 4, over the course of 10 days.

As this is a regrouping strategy where all groups are orthogonal, this process within the problem of organising a large group into smaller groups where no two people share the same group twice can be referred to as orthogonal regrouping. [9]

The Resolvable Coverings problem considers the general

n

girls,

g

groups case where each pair of girls must be in the same group at some point, but we want to use as few days as possible. This can, for example, be used to schedule a rotating table plan, in which each pair of guests must at some point be at the same table.[10]

The Oberwolfach problem, of decomposing a complete graph into edge-disjoint copies of a given 2-regular graph, also generalizes Kirkman's schoolgirl problem. Kirkman's problem is the special case of the Oberwolfach problem in which the 2-regular graph consists of five disjoint triangles.

See also

External links

Notes and References

  1. The Early History of Block Designs by Robin Wilson, Dept of Pure Mathematics, The Open University, UK
  2. 10.1073/pnas.3.3.197 . The Complete Enumeration of Triad Systems in 15 Elements . 1917 . Cole . F. N. . Cummings . Louise D. . White . H. S. . Proceedings of the National Academy of Sciences . 3 . 3 . 197–199 . 16576216 . 1091209 . 1917PNAS....3..197C . free .
  3. 10.1016/0012-365X(74)90004-1 . Sylvester's problem of the 15 schoolgirls . 1974 . Denniston . R.H.F. . Discrete Mathematics . 9 . 3 . 229–233 . free .
  4. https://m.youtube.com/watch?v=XHbMMAxPgRA Kirkman's Ladies audio
  5. Book: https://link.springer.com/chapter/10.1007/978-3-0348-0554-4_4 . 10.1007/978-3-0348-0554-4_4 . Kirkman's Ladies, A Combinatorial Design . Looking at Numbers . 2014 . Johnson . Tom . Jedrzejewski . Franck . 37–55 . 978-3-0348-0553-7 .
  6. A new result on Sylvester's problem . 10.1016/j.disc.2014.04.022 . 2014 . Zhou . Junling . Chang . Yanxun . Discrete Mathematics . 331 . 15–19 .
  7. Araya, Makoto & Harada, Masaaki. (2010). Mutually Disjoint Steiner Systems S(5, 8, 24) and 5-(24, 12, 48) Designs. Electr. J. Comb.. 17.
  8. Conwell . George M. . 1910 . The 3-space PG(3,2) and its Group . . 11 . 2. 60–76 . 10.2307/1967582 . 1967582 .
  9. Book: https://link.springer.com/chapter/10.1007/978-3-030-69625-2_5 . 10.1007/978-3-030-69625-2_5 . Max-Diversity Orthogonal Regrouping of MBA Students Using a GRASP/VND Heuristic . Variable Neighborhood Search . Lecture Notes in Computer Science . 2021 . Banchero . Matías . Robledo . Franco . Romero . Pablo . Sartor . Pablo . Servetti . Camilo . 12559 . 58–70 . 978-3-030-69624-5 . 232314621 .
  10. 10.1002/jcd.10024 . Equitable resolvable coverings . 2003 . Van Dam . Edwin R. . Haemers . Willem H. . Peek . Maurice B. M. . Journal of Combinatorial Designs . 11 . 2 . 113–123 . 120596961 . free .
  11. Web site: The Mind-Bending Math Behind Spot It!, the Beloved Family Card Game. McRobbie. Linda Rodriguez. Smithsonian Magazine. en. 2020-03-01.