Ken Austin (cricketer) explained

Ken Austin
Fullname:Quentin Ahern Austin
Birth Date:18 December 1908
Birth Place:Queenstown, Cape Colony
Death Place:Harare, Zimbabwe
Batting:Right-handed
Bowling:Right-arm leg-spin
Club1:Rhodesia
Year1:1927-28 to 1946-47
Columns:1
Column1:First-class
Matches1:5
Runs1:65
Bat Avg1:8.12
100S/50S1:0/0
Top Score1:25
Deliveries1:314
Wickets1:4
Bowl Avg1:49.25
Fivefor1:0
Tenfor1:0
Best Bowling1:4/51
Catches/Stumpings1:3/–
Source:https://www.espncricinfo.com/player/ken-austin-55238 Cricinfo
Date:12 December 2021

Quentin Ahern "Ken" Austin ISO (18 December 1908 – 16 July 2004) was a cricketer who played five matches of first-class cricket for Rhodesia: one in April 1928, and four between March 1946 and March 1947.

Austin was educated at St Aidan's College in Grahamstown, Cape Province, and went to work in a bank. Dissatisfied with his job, he successfully applied for a position in the civil service in Salisbury, Rhodesia, in 1927 aged 18.[1] He made his first-class debut a few months later, but was only moderately successful, making the top score of 25 in Rhodesia’s first innings of 135.[2] Eighteen years later he resumed his first-class career, but he was even less successful, scoring only 40 runs and taking four wickets in four matches.[3]

Austin was appointed Companion of the Imperial Service Order in 1963 for his service as Deputy Secretary in the Ministry of Local Government in Rhodesia.[4] At the time of his death in Harare in 2004 at the age of 95, he was the oldest surviving Rhodesian cricketer.[1]

Notes and References

  1. Web site: Ken Austin . Cricinfo. 12 December 2021.
  2. Web site: Rhodesia v Transvaal 1927-28. Cricinfo. 12 December 2021.
  3. Web site: subscription . Ken Austin. CricketArchive. 12 December 2021.
  4. Imperial Service Order. London Gazette. 8 June 1963. 4818 .