| Official Name: | Kelso Township |
| Settlement Type: | Township |
| Subdivision Type: | Country |
| Subdivision Name: | United States |
| Subdivision Type1: | State |
| Subdivision Name1: | Indiana |
| Subdivision Type2: | County |
| Subdivision Name2: | Dearborn |
| Government Type: | Indiana township |
| Area Total Sq Mi: | 25.65 |
| Area Land Sq Mi: | 25.62 |
| Area Water Sq Mi: | 0.04 |
| Population As Of: | 2020 |
| Population Footnotes: | [1] |
| Population Total: | 2469 |
| Population Density Sq Mi: | 91.4 |
| Elevation Footnotes: | [2] |
| Elevation M: | 281 |
| Elevation Ft: | 922 |
| Coordinates: | 39.2556°N -84.9717°W |
| Blank Name: | FIPS code |
| Blank Info: | 18-39330[3] |
| Blank1 Name: | GNIS feature ID |
| Blank1 Info: | 453523 |
Kelso Township is one of fourteen townships in Dearborn County, Indiana, United States. As of the 2010 census, its population was 2,341 and it contained 919 housing units.[4]
Kelso Township is one of the original townships of Dearborn County that also included what is now Jackson Township. Kelso Township was organized in the November 1826 session of the County Supervisors.[5] Kelso Township was named for John Kelso, an Irish immigrant and pioneer settler.[6]
In 1832 Jackson Township was created from the western portion of Kelso Township.[7]
According to the 2010 census, the township has a total area of, of which (or 99.88%) is land and (or 0.16%) is water.[4]
(This list is based on USGS data and may include former settlements.)