Mutation (Jordan algebra) explained

In mathematics, a mutation, also called a homotope, of a unital Jordan algebra is a new Jordan algebra defined by a given element of the Jordan algebra. The mutation has a unit if and only if the given element is invertible, in which case the mutation is called a proper mutation or an isotope. Mutations were first introduced by Max Koecher in his Jordan algebraic approach to Hermitian symmetric spaces and bounded symmetric domains of tube type. Their functorial properties allow an explicit construction of the corresponding Hermitian symmetric space of compact type as a compactification of a finite-dimensional complex semisimple Jordan algebra. The automorphism group of the compactification becomes a complex subgroup, the complexification of its maximal compact subgroup. Both groups act transitively on the compactification. The theory has been extended to cover all Hermitian symmetric spaces using the theory of Jordan pairs or Jordan triple systems. Koecher obtained the results in the more general case directly from the Jordan algebra case using the fact that only Jordan pairs associated with period two automorphisms of Jordan algebras are required.

Definitions

See also: Quadratic Jordan algebra. Let A be a unital Jordan algebra over a field k of characteristic ≠ 2.^[1] For a in A define the Jordan multiplication operator on A by

\displaystyle{L(a)b = ab}

and the quadratic representation Q(a) by

Q(a) =2 L(a) ^{2} - L(a ^{2).}

It satisfies

Q( 1 ) = I.

the fundamental identity

\displaystyle{Q(Q(a)b) = Q(a)Q(b)Q(a)}

the commutation or homotopy identity

\displaystyle{Q(a)R(b,a) = R(a,b)Q(a) = 2 Q(Q(a)b,a),}

where

R(a,b)c =2 Q(a,c)b, Q(x,y) = (1)/(2) (Q(x + y) - Q(x) - Q(y)).

In particular if a or b is invertible then

\displaystyle{R(a,b) =2 Q(a)Q(a ^{-1} ,b) =2 Q(a,b ^{-1} )Q(b).}

It follows that A with the operations Q and R and the identity element defines a quadratic Jordan algebra, where a quadratic Jordan algebra consists of a vector space A with a distinguished element 1 and a quadratic map of A into endomorphisms of A, a ↦ Q(a), satisfying the conditions:

• • ("fundamental identity")
• ("commutation or homotopy identity"), where

The Jordan triple product is defined by

\{a,b,c\} = (ab)c + (cb)a - (ac)b,

so that

Q(a)b = \{a,b,a\}, Q(a,c)b = \{a,b,c\}, R(a,b)c = \{a,b,c\}.

There are also the formulas

Q(a,b) = L(a)L(b) + L(b)L(a) - L(ab), R(a,b) = [L(a),L(b)] + L(ab).

For y in A the mutation A^y is defined to the vector space A with multiplication

a\circ b = \{a,y,b\}. If Q(y) is invertible, the mutual is called a proper mutation or isotope.

Quadratic Jordan algebras

See main article: Quadratic Jordan algebra. Let A be a quadratic Jordan algebra over a field k of characteristic ≠ 2. Following, a linear Jordan algebra structure can be associated with A such that, if L(a) is Jordan multiplication, then the quadratic structure is given by Q(a) = 2L(a)² − L(a²).

Firstly the axiom Q(a)R(b,a) = R(a,b)Q(a) can be strengthened to

\displaystyle{Q(a)R(b,a) = R(a,b)Q(a) =2 Q(Q(a)b,a).}

Indeed, applied to c, the first two terms give

\displaystyle{ 2 Q(a)Q(b,c)a =2 Q(Q(a)c,a)b.}

Switching b and c then gives

\displaystyle{Q(a)R(b,a)c =2 Q(Q(a)b,a)c.}

Now let

\displaystyle{L(a) = (1)/(2) R(a, 1 ).} Replacing b by a and a by 1 in the identity above gives\displaystyle{R(a, 1 ) = R( 1 ,a) =2 Q(a, 1 ).}

In particular

\displaystyle{L(a) = Q(a, 1 ),L( 1 ) = Q( 1 , 1 ) = I.}

The Jordan product is given by

\displaystyle{a\circ b = L(a)b = (1)/(2) R(a, 1 )b = Q(a,b) 1 ,}

so that

\displaystyle{a\circ b = b \circ a.}

The formula above shows that 1 is an identity. Defining a² by a∘a = Q(a)1, the only remaining condition to be verified is the Jordan identity

\displaystyle{[L(a),L(a ^{2)]=0.}}

In the fundamental identity

\displaystyle{Q(Q(a)b) = Q(a)Q(b)Q(a),}

Replace a by a + t1, set b = 1 and compare the coefficients of t² on both sides:

\displaystyle{Q(a) =2 Q(a, 1 ) ^{2} - Q(a ^{2,1)=} 2 L(a) ^{2} - L(a ^{2).}}

Setting b = 1 in the second axiom gives

\displaystyle{Q(a)L(a) = L(a)Q(a),}

and therefore L(a) must commute with L(a²).

Inverses

Let A be a unital Jordan algebra over a field k of characteristic ≠ 2. An element a in a unital Jordan algebra A is said to be invertible if there is an element b such that ab = 1 and a²b = a.^[2]

Properties.^[3]

If and, then . The Jordan identity can be polarized by replacing by and taking the coefficient of . This gives\displaystyle{[L(x ^{2),L(y)]+2[L(xy),L(x)]=0.}}

Taking or and or shows that commutes with and commutes with . Hence . Applying gives . Hence . Conversely if and, then the second relation gives . So both and are invertible. The first gives so that and are each other's inverses. Since commutes with it commutes with its inverse . Similarly commutes with . So and .

Indeed, if is invertible then the above implies is invertible with inverse . Any inverse b satisfies, so . Conversely if is invertible let . Then. The fundamental identity then implies that and are each other's inverses so that .

This follows from the formula .

Suppose that . Then by the fundamental identity is invertible, so is invertible.

This is an immediate consequence of the fundamental identity and the fact that is invertible if and only and are invertible.

In the commutation identity, set with . Then and . Since commutes with, .

If and commute, then implies . Conversely suppose that is invertible with inverse . Then . Morevoer commutes with and hence its inverse . So it commutes with .

The algebra is commutative and associative, so if is an inverse there and . Conversely leaves invariant. So if it is bijective on it is bijective there. Thus lies in .

Elementary properties of proper mutations

In fact ^[4] multiplication in the algebra A^y is given by\displaystyle{a\circ b = \{a,y,b\},}

so by definition is commutative. It follows that

\displaystyle{a\circ b = L _{y(a)b,}}

with

\displaystyle{L _{y(a)=[L(a),L(y)]} + L(ay).}

If e satisfies, then taking a = 1 gives

\displaystyle{ye =1 .}

Taking a = e gives

\displaystyle{e(ya) = y(ea)}

so that L(y) and L(e) commute. Hence y is invertible and e = y⁻¹.

Now for y invertible set

\displaystyle{Q _{y(a)=Q(a)Q(y),} R _{y(a,b)=R(a,Q(y)b).}}

Then

\displaystyle{Q _{y(e)=Q} ^{-1} ^{y(y} ) = Q(y ^{-1} )Q(y) = I.}

Moreover,

\displaystyle{Q _{y(a)Q} _{y(b)Q} _{y(a)=Q(a)Q(y)Q(b)Q(y)Q(a)Q(y)=Q(a)} Q(Q(y)b) Q(a)Q(y) = Q(Q(a)Q(y)b)Q(y) = Q _{y(Q} _{y(a)b).}}

Finally

\displaystyle{Q(y)R(c,Q(y)d)Q(y) ^{-1} = R(Q(y)c,d),}

since

\displaystyle{Q(y)R(c,Q(y)d)x =2 Q(y)Q(c,x)Q(y)d =2 Q(Q(y)c,Q(y)x)d = R(Q(y)c,d)Q(y)x.}

Hence

\displaystyle{Q _{y(a)R} ^{-1} ^{y(b,a) = Q(a)Q(y)R(b,Q(y)a) = Q(y} ) Q(Q(y)a)R(b,Q(y)a) = Q(y) ^{-1} R(Q(y)a,b)Q(Q(y)a) = R _{y(a,b)} Q _{y(a).}}

Thus is a unital quadratic Jordan algebra. It therefore corresponds to a linear Jordan algebra with the associated Jordan multiplication operator M(a) given by

\displaystyle{M(a)b = (1)/(2) R _{y(a,e)b=} (1)/(2) R(a,Q(y)e)b = (1)/(2) R(a,y)b = \{a,y,b\} = L _{y(a)b.}}

This shows that the operators satisfy the Jordan identity so that the proper mutation or isotope is a unital Jordan algebra. The correspondence with quadratic Jordan algebras shows that its quadratic representation is given by .

Nonunital mutations

The definition of mutation also applies to non-invertible elements y. If A is finite-dimensional over R or C, invertible elements a in A are dense, since invertibility is equivalent to the condition that det Q(a) ≠ 0. So by continuity the Jordan identity for proper mutations implies the Jordan identity for arbitrary mutations. In general the Jordan identity can be deduced from Macdonald's theorem for Jordan algebras because it involves only two elements of the Jordan algebra. Alternatively, the Jordan identity can be deduced by realizing the mutation inside a unital quadratic algebra.^[5]

For a in A define a quadratic structure on A₁ = A ⊕ k by

\displaystyle{Q _{1(a ⊕} \alpha 1 )(b ⊕ \beta 1 ) = \alpha ^{2\beta} 1 ⊕ [\alpha ^{2} a + \alpha ^{2} b + 2 \alpha\beta a + \alpha \{a,y, b\} + \beta Q(a)y + Q(a)Q(y)b].}

It can then be verified that is a unital quadratic Jordan algebra. The unital Jordan algebra to which it corresponds has A^y as an ideal, so that in particular A^y satisfies the Jordan identity. The identities for a unital quadratic Jordan algebra follow from the following compatibility properties of the quadratic map and the squaring map

• • • • • • .

Hua's identity

Let A be a unital Jordan algebra. If a, b and a – b are invertible, then Hua's identity holds:

In particular if x and 1 – x are invertible, then so too is 1 – x⁻¹ with\displaystyle{( 1- x) ^{-1} + ( 1- x ^{-1} ) ^{-1} = 1 .}

To prove the identity for x, set . Then . Thus commutes with and . Since, it also commutes with and . Since, also commutes with and .

It follows that . Moreover, since . So commutes with and hence . Thus has inverse .

Now let be the mutation of A defined by a. The identity element of is . Moreover, an invertible element c in A is also invertible in with inverse .

Let in . It is invertible in A, as is . So by the special case of Hua's identity for x in

\displaystyle{a ^{-1} = Q(a) ^{-1} (a ^{-1} - Q(a) ^{-1} b) ^{-1} + Q(a) ^{-1} (a ^{-1} - b ^{-1} ) ^{-1} = (a - b) ^{-1} + (a - Q(a)b ^{-1} ) ^{-1} .}

Bergman operator

If A is a unital Jordan algebra, the Bergman operator is defined for a, b in A by

\displaystyle{B(a,b) = I - R(a,b) + Q(a)Q(b).}

If a is invertible then

\displaystyle{B(a,b) = Q(a)Q(a ^{-1} - b);}

while if b is invertible then

\displaystyle{B(a,b) = Q(a - b ^{-1} )Q(b).}

In fact if a is invertible

and similarly if b is invertible.

More generally the Bergman operator satisfies a version of the commutation or homotopy identity:

and a version of the fundamental identity:

There is also a third more technical identity:

Quasi-invertibility

Let A be a finite-dimensional unital Jordan algebra over a field k of characteristic ≠ 2.^[6] For a pair with and invertible define

In this case the Bergman operator defines an invertible operator on A and

In fact\displaystyle{B(a,b) ^{-1} (a - Q(a)b) = Q(a ^{b)Q(a} ^{-1} )(a - Q(a)b) = Q(a ^{b)(a} ^{b)} ^{-1} = a ^{b.}}

Moreover, by definition is invertible if and only if is invertible. In that case

Indeed,\displaystyle{a ^{b+c} = ((a ^{-1} - b) - c) ^{-1} = ((a ^{b)} ^{-1} - c) ^{-1} = (a ^{b)} ^{c.}}

The assumption that be invertible can be dropped since can be defined only supposing that the Bergman operator is invertible. The pair is then said to be quasi-invertible. In that case is defined by the formula

\displaystyle{a ^{b} = B(a,b) ^{-1} (a - Q(a)b).}

If is invertible, then for some . The fundamental identity implies that . So by finite-dimensionality is invertible. Thus is invertible if and only if is invertible and in this case

In fact

so the formula follows by applying to both sides. As before is quasi-invertible if and only if is quasi-invertible; and in that case

\displaystyle{a ^{b+c} = (a ^{b)} ^{c.}}

If k = R or C, this would follow by continuity from the special case where and were invertible. In general the proof requires four identities for the Bergman operator:

In fact applying to the identity yields\displaystyle{B(a,b)Q(a ^{b)B(b,a)=B(a,b)Q(a)=Q(a)B(b,a).}}

The first identity follows by cancelling and . The second identity follows by similar cancellation in

.

The third identity follows by applying the second identity to an element d and then switching the roles of c and d. The fourth follows because

.

In fact is quasi-invertible if and only if is quasi-invertible in the mutation . Since this mutation might not necessarily unital this means that when an identity is adjoint becomes invertible in . This condition can be expressed as follows without mentioning the mutation or homotope:

In fact if is quasi-invertible, then satisfies the first identity by definition. The second follows because . Conversely the conditions state that in the conditions imply that is the inverse of . On the other hand, for in . Hence is invertible.

Equivalence relation

Let A be a finite-dimensional unital Jordan algebra over a field k of characteristic ≠ 2.Two pairs with invertible are said to be equivalent if is invertible and .

This is an equivalence relation, since if is invertible so that a pair is equivalent to itself. It is symmetric since from the definition . It is transitive. For suppose that is a third pair with invertible and . From the above

\displaystyle{a ^{-1} _{1} - b _{1} + b _{3=} (a ^{-1} _{1} - b _{1} + b _{2)} - b _{2} + b _{3=a} ^{-1} ^{2} - b _{2+b} _{3}}

is invertible and

\displaystyle{a _{3=a} ^{b _{2-b} _{3}} ^{2} = (a ^{b _{1-b} _{2}} _{1} ) ^{b _{2-b} _{3}} = a ^{b _{1-b} _{3}} _{1} .}

As for quasi-invertibility, this definition can be extended to the case where and are not assumed to be invertible.

Two pairs are said to be equivalent if is quasi-invertible and . When k = R or C, the fact that this more general definition also gives an equivalence relation can deduced from the invertible case by continuity. For general k, it can also be verified directly:

• The relation is reflexive since is quasi-invertible and .
• The relation is symmetric, since .
• The relation is transitive. For suppose that is a third pair with quasi-invertible and . In this case

\displaystyle{B(a _{1,b} _{1-b} _{3)=B(a} _{1,b} _{1-b} _{2)B(a} _{2,b} _{2-b} _{3),}}

so that is quasi-invertible with

\displaystyle{a _{3=a} ^{b _{2-b} _{3}} ^{2} = (a ^{b _{1-b} _{2}} _{1} ) ^{b _{2-b} _{3}} = a ^{b _{1-b} _{3}} _{1} .}

The equivalence class of is denoted by .

Structure groups

Let be a finite-dimensional complex semisimple unital Jordan algebra. If is an operator on, let be its transpose with respect to the trace form. Thus,, and . The structure group of A consists of g in such that

\displaystyle{Q(ga) = gQ(a)g ^{t.}}

They form a group . The automorphism group Aut A of A consists of invertible complex linear operators g such that L(ga) = gL(a)g⁻¹ and g1 = 1. Since an automorphism g preserves the trace form, g⁻¹ = g^t.

• The structure group is closed under taking transposes g ↦ g^t and adjoints g ↦ g*.
• The structure group contains the automorphism group. The automorphism group can be identified with the stabilizer of 1 in the structure group.
• If a is invertible, Q(a) lies in the structure group.
• If g is in the structure group and a is invertible, ga is also invertible with (ga)⁻¹ = (g^t)⁻¹a⁻¹.
• The structure group Γ(A) acts transitively on the set of invertible elements in A.
• Every g in Γ(A) has the form g = h Q(a) with h an automorphism and a invertible.

The complex Jordan algebra A is the complexification of a real Euclidean Jordan algebra E, for which the trace form defines an inner product. There is an associated involution on which gives rise to a complex inner product on . The unitary structure group Γ_u(A) is the subgroup of Γ(A) consisting of unitary operators, so that . The identity component of is denoted by . It is a connected closed subgroup of .

• The stabilizer of 1 in Γ_u(A) is Aut E.
• Every g in Γ_u(A) has the form g = h Q(u) with h in Aut E and u invertible in A with u* = u⁻¹.
• Γ(A) is the complexification of Γ_u(A).
• The set S of invertible elements u in A such that u* = u⁻¹ can be characterized equivalently either as those u for which L(u) is a normal operator with uu* = 1 or as those u of the form exp ia for some a in E. In particular S is connected.
• The identity component of Γ_u(A) acts transitively on S
• Given a Jordan frame (e_i) and v in A, there is an operator u in the identity component of Γ_u(A) such that uv = Σ α_i e_i with α_i ≥ 0. If v is invertible, then α_i > 0.

The structure group Γ(A) acts naturally on X. For g in Γ(A), set

\displaystyle{g(a,b) = (ga,(g ^{t)} ^{-1} b).}

Then is quasi-invertible if and only if is quasi-invertible and

\displaystyle{g(x ^{y)=(gx)} ^{(g ^{t)} ^{-1} y} .}

In fact the covariance relations for g with Q and the inverse imply that

\displaystyle{gB(x,y)g ^{-1} = B(gx,(g ^{t)} ^{-1} y)}

if x is invertible and so everywhere by density. In turn this implies the relation for the quasi-inverse. If a is invertible then Q(a) lies in Γ(A) and if (a,b) is quasi-invertible B(a,b) lies in Γ(A). So both types of operators act on X.

The defining relations for the structure group show that it is a closed subgroup of

ak{g} _{0} of . Since, the corresponding complex Lie algebra contains the operators . The commutators span the complex Lie algebra of derivations of . The operators span ak{g} _{0} andsatisfy and.

Geometric properties of quotient space

Let A be a finite-dimensional complex unital Jordan algebra which is semisimple, i.e. the trace form Tr L(ab) is non-degenerate. Let be the quotient of by the equivalence relation. Let be the subset of X of classes . The map, is injective. A subset of is defined to be open if and only if is open for all .

The transition maps of the atlas with charts are given by\displaystyle{\varphi _{cb} = \varphi _{c\circ\varphi} ^{-1} ^{b} :\varphi _{b(X} _{b\cap} X _{c) →} \varphi _{c(X} _{b\cap} X _{c).}}

and are injective and holomorphic since

\displaystyle{\varphi _{cb} (a) = a ^{b-c} }

with derivative

\displaystyle{\varphi ^{\prime(a) = B(a,b - c)} _{cb} ^{-1} .}

This defines the structure of a complex manifold on X because on .

Indeed, all the polynomial functions are non-trivial since . Therefore, there is a such that for all i, which is precisely the criterion for to lie in .

uses the Bergman operators to construct an explicit biholomorphism between X and a closed smooth algebraic subvariety of complex projective space. This implies in particular that is compact. There is a more direct proof of compactness using symmetry groups.

Given a Jordan frame (e_i) in E, for every a in A there is a k in U = Γ_u(A) such that with (and if a is invertible).In fact, if (a,b) is in X then it is equivalent to k(c,d) with c and d in the unital Jordan subalgebra, which is the complexification of .Let be the complex manifold constructed for . Because is a direct sum of copies of C, Z is just a product of Riemann spheres, one for each . In particular it is compact. There is a natural map of Z into X which is continuous. Let Y be the image of Z. It is compact and therefore coincides with the closure of Y₀ = A_e ⊂ A = X₀. The set U⋅Y is the continuous image of the compact set U × Y. It is therefore compact. On the other hand, U⋅Y₀ = X₀, so it contains a dense subset of X and must therefore coincide with X. So X is compact.

The above argument shows that every (a,b) in X is equivalent to k(c,d) with c and d in and k in. The mapping of Z into X is in fact an embedding. This is a consequence of being quasi-invertible in if and only if it is quasi-invertible in . Indeed, if is injective on A, its restriction to is also injective. Conversely, the two equations for the quasi-inverse in imply that it is also a quasi-inverse in .

Möbius transformations

Let be a finite-dimensional complex semisimple unital Jordan algebra. The group SL(2,C) acts by Möbius transformation on the Riemann sphere C ∪, the one-point compactification of C. If g in SL(2,C) is given by the matrix

\displaystyle{g = \begin{pmatrix}\alpha & \beta \ \gamma & \delta\end{pmatrix},}

then

\displaystyle{g(z) = (\alpha z + \beta)(\gamma z + \delta) ^{-1} .}

There is a generalization of this action of SL(2,C) to A and its compactification X. In order to define this action, note that SL(2,C) is generated by the three subgroups of lower and upper unitriangular matrices and the diagonal matrices. It is also generated by the lower (or upper) unitriangular matrices, the diagonal matrices and the matrix

\displaystyle{J = \begin{pmatrix} 0 & 1 \ -1 & 0 \end{pmatrix}.}

The matrix J corresponds to the Möbius transformation and can be written

\displaystyle{J = \begin{pmatrix} 1 & 0 \ -1 & 1 \end{pmatrix}\begin{pmatrix} 1 & 1 \ 0 & 1 \end{pmatrix} \begin{pmatrix} 1 & 0 \ -1 & 1 \end{pmatrix}.}

The Möbius transformations fixing ∞ are just the upper triangular matrices. If g does not fix ∞, it sends ∞ to a finite point a. But then g can be composed with an upper unitriangular to send a to 0 and then with J to send 0 to infinity.

For an element of, the action of in SL(2,C) is defined by the same formula

\displaystyle{g(a) = (\alpha a + \beta 1 )(\gamma a + \delta 1 ) ^{-1} .}

This defines an element of provided that is invertible in . The action is thus defined everywhere on if g is upper triangular. On the other hand, the action on X is simple to define for lower triangular matrices.^[7]

• For diagonal matrices g with diagonal entries and, is a well-defined holomorphic action on which passes to the quotient X. On it agrees with the Möbius action.
• For lower unitriangular matrices, with off-diagonal parameter γ, define . Again this is holomorphic on and passes to the quotient X. When and,

\displaystyle{g(a: 0 ) = (a: - \gamma) = (a ^{-\gamma} : 0 ) = (a(\gamma a +1 ) ^{-1} : 0 )}

if is invertible, so this is an extension of the Möbius action.

• For upper unitriangular matrices, with off-diagonal parameter β, the action on is defined by . showed that this defined a complex one-parameter flow on . The corresponding holomorphic complex vector field extended to, so that the action on the compact complex manifold could be defined by the associated complex flow. A simpler method is to note that the operator can be implemented directly using its intertwining relations with the unitary structure group.

In fact on the invertible elements in A, the operator satisfies . To define a biholomorphism j on X such that, it is enough to define these for in some suitable orbit of Γ(A) or Γ_u(A). On the other hand, as indicated above, given a Jordan frame (e_i) in E, for every a in A there is a k in U = Γ_u(A) such that with .

The computation of in the associative commutative algebra is straightforward since it is a direct product. For and, the Bergman operator on has determinant . In particular for some λ ≠ 0. So that is equivalent to . Let . On, for a dense set of, the pair is equivalent to with b invertible. Then is equivalent to . Since is holomorphic it follows that j has a unique continuous extension to X such that for in, the extension is holomorphic and for,

The holomorphic transformations corresponding to upper unitriangular matrices can be defined using the fact that they are the conjugates by J of lower unitriangular matrices, for which the action is already known. A direct algebraic construction is given in .

This action of is compatible with inclusions. More generally if is a Jordan frame, there is an action of on A_e which extends to A. If and, then and give the action of the product of the lower and upper unitriangular matrices. If is invertible, the corresponding product of diagonal matrices act as . In particular the diagonal matrices give an action of and .

Holomorphic symmetry group

Let be a finite-dimensional complex semisimple unital Jordan algebra. There is a transitive holomorphic action of a complex matrix group on the compact complex manifold . described analogously to in terms of generators and relations. acts on the corresponding finite-dimensional Lie algebra of holomorphic vector fields restricted to, so that is realized as a closed matrix group. It is the complexification of a compact Lie group without center, so a semisimple algebraic group. The identity component of the compact group acts transitively on, so that can be identified as a Hermitian symmetric space of compact type.^[8]

The group G is generated by three types of holomorphic transformation on :

• Operators W corresponding to elements W in given by . These were already described above. On, they are given by .
• Operators S_c defined by . These are the analogue of lower unitriangular matrices and form a subgroup isomorphic to the additive group of, with the given parametrization. Again these act holomorphically on and the action passes to the quotient X. On the action is given by if is quasi-invertible.
• The transformation corresponding to in . It was constructed above as part of the action of on . On invertible elements in it is given by .

The operators normalize the group of operators . Similarly the operator normalizes the structure group, . The operators also form a group of holomorphic transformations isomorphic to the additive group of . They generalize the upper unitriangular subgroup of . This group is normalized by the operators W of the structure group. The operator acts on as . If is a scalar the operators and coincide with the operators corresponding to lower and upper unitriangular matrices in . Accordingly, there is a relation and is a subgroup of G. defines the operators in terms of the flow associated to a holomorphic vector field on, while give a direct algebraic description.

Indeed, .

Let and be the complex Abelian groups formed by the symmetries and respectively. Let .

The two expressions for are equivalent as follows by conjugating by .

For invertible, Hua's identity can be rewritten

\displaystyle{Q(a) = T _{a} \circ j \circ T _{a ^{-1}} \circ j \circ T _{a} \circ j.}

Moreover, and.

The convariance relations show that the elements of fall into sets,,, . ...The first expression for follows once it is established that no new elements appear in the fourth or subsequent sets. For this it suffices to show that

.

For then if there are three or more occurrences of, the number can be recursively reduced to two. Given in, pick so that and are invertible. Then

\displaystyle{j T _{a} j T _{b} j = j T _{c} T _{λ} j T _{λ ^{-1}} T _{d} \circ j = λ ^{2} j T _{c} j T _{-λ} j T _{d} j = λ ^{2} T _{- c ^{-1}} j Q(c ^{-1} )T _{- c ^{-1} -λ- d ^{-1}} j Q(d ^{-1} )jT _{- d ^{-1}} ,}

which lies in .

It suffices to check that if, then . If so, so .

Exchange relations

For invertible, Hua's identity can be rewritten\displaystyle{Q(a) = T _{a} \circ j \circ T _{a ^{-1}} \circ j \circ T _{a} \circ j.}

Since, the operators belong to the group generated by .

For quasi-invertible pairs, there are the "exchange relations"

This identity shows that is in the group generated by . Taking inverses, it is equivalent to the identity .

To prove the exchange relations, it suffices to check that it valid when applied to points the dense set of points in for which is quasi-invertible. It then reduces to the identity:

In fact, if is quasi-invertible, then is quasi-invertible if and only if is quasi-invertible. This follows because is quasi-invertible if and only if is. Moreover, the above formula holds in this case.

For the proof, two more identities are required:

\displaystyle{B(c + b,a) = B(c,a ^{b)B(b,a)}} \displaystyle{R(a,b) = R(a ^{b,b-Q(b)a)=R(a-Q(a)b,b} ^{a)}}

The first follows from a previous identity by applying the transpose. For the second, because of the transpose, it suffices to prove the first equality. Setting in the identity yields

so the identity follows by cancelling .

To prove the formula, the relations and show that it is enough to prove that

Indeed, . On the other hand, and . So .

Now set . Then the exchange relations imply that lies in if and only if is quasi-invertible; and that lies in if and only if is in .

In fact if lies in, then is equivalent to, so it a quasi-invertible pair; the converse follows from the exchange relations. Clearly . The converse follows from and the criterion for to lie in .

Lie algebra of holomorphic vector fields

See also: Kantor–Koecher–Tits construction. The compact complex manifold is modelled on the space . The derivatives of the transition maps describe the tangent bundle through holomorphic transition functions . These are given by, so the structure group of the corresponding principal fiber bundle reduces to, the structure group of .^[9] The corresponding holomorphic vector bundle with fibre is the tangent bundle of the complex manifold . Its holomorphic sections are just holomorphic vector fields on X. They can be determined directly using the fact that they must be invariant under the natural adjoint action of the known holomorphic symmetries of X. They form a finite-dimensional complex semisimple Lie algebra. The restriction of these vector fields to X₀ can be described explicitly. A direct consequence of this description is that the Lie algebra is three-graded and that the group of holomorphic symmetries of X, described by generators and relations in and, is a complex linear semisimple algebraic group that coincides with the group of biholomorphisms of X.

The Lie algebras of the three subgroups of holomorphic automorphisms of give rise to linear spaces of holomorphic vector fields on and hence .

• The structure group has Lie algebra

ak{g} _{0} spanned by the operators . These define a complex Lie algebra of linear vector fields on .

• The translation operators act on as . The corresponding one-parameter subgroups are given by and correspond to the constant vector fields . These give an Abelian Lie algebra

ak{g} _{-1} of vector fields on .

• The operators defined on by . The corresponding one-parameter groups define quadratic vector fields on . These give an Abelian Lie algebra

ak{g} _{1} of vector fields on .

Let

\displaystyle{ ak{g}= ak{g} _{-1} ⊕ ak{g} _{0 ⊕ ak{g}} _{1.}}

Then, defining

ak{g} _{i} = ( 0 ) for, ak{g} forms a complex Lie algebra with\displaystyle{[ ak{g} _{p,ak{g}} _{q]\subseteq} ak{g} _{p+q} }.

This gives the structure of a 3-graded Lie algebra. For elements in

ak{g} , the Lie bracket is given by\displaystyle{[(a _{1,T} _{1,b} _{1),(a} _{2,T} _{2,b} _{2)]=(T} _{1a} _{2-T} _{2a} _{1,[T} _{1,T} _{2]+R(a} _{1,b} _{2)-R(a} _{2,b} _{1),T} ^{tb} ^{1- T} ^{tb} ^{2 )}}

The group of Möbius transformations of X normalizes the Lie algebra

ak{g} . The transformation corresponding to the Weyl group element induces the involutive automorphism given by\displaystyle{\sigma(a,T,b) = (b, - T ^{t,a).}}

More generally the action of a Möbius transformation

\displaystyle{g = \begin{pmatrix}\alpha & \beta \ \gamma & \delta\end{pmatrix}}

can be described explicitly. In terms of generators diagonal matrices act as

\displaystyle{\begin{pmatrix}\alpha & 0 \ 0 & \alpha ^{-1} \end{pmatrix}(a,T,b) = (\alpha ^{2} a,T,\alpha ^{-2} b),}

upper unitriangular matrices act as

\displaystyle{\begin{pmatrix} 1 & \beta \ 0 & 1 \end{pmatrix}(a,T,b) = (a + \beta T( 1 ) - \beta ^{2} b,T - \beta L(a),b),}

and lower unitriangular matrices act as

\displaystyle{\begin{pmatrix} 1 & 0 \ \gamma & 1 \end{pmatrix}(a,T,b) = (a,T - \gamma L(b),b - \gamma T ^{t(1)} - \gamma ^{2} a).}

This can be written uniformly in matrix notation as

\displaystyle{\begin{pmatrix}g(T) & g(a) \ g(b) & g(T) ^{t\end{pmatrix}=} g \begin{pmatrix}T & a \ b & T ^{t\end{pmatrix}} g ^{-1} .}

In particular the grading corresponds to the action of the diagonal subgroup of, even with |α| = 1, so a copy of T.

The Killing form is given by

\displaystyle{ {B }((a_1,T_1,b_1),(a_2,T_2,b_2))= (a_1,b_2) + (b_1,a_2) + \beta(T_1,T_2),}

where is the symmetric bilinear form defined by

\displaystyle{\beta(R(a,b),R(c,d)) = (R(a,b)c,d) = (R(c,d)a,b),}

with the bilinear form corresponding to the trace form: .

More generally the generators of the group act by automorphisms on

ak{g} as\displaystyle{W(a,T,b) = (Wa,WTW ^{-1} ,(W ^{t)} ^{-1} b),} \displaystyle{J(a,T,b) = ( - b, - T ^{t,-a),}} \displaystyle{T _{x(a,T,b)=(a+Tx} - Q(x)b, T - R(x,b),b),} \displaystyle{S ^{ty - Q(y)a).}} _{y(a,T,b) = (a,T - R(a,y),b - T}

The nondegeneracy of the Killing form is immediate from the explicit formula. By Cartan's criterion, ak{g} is semisimple. In the next section the group is realized as the complexification of a connected compact Lie group with trivial center, so semisimple. This gives a direct means to verify semisimplicity. The group H also acts transitively on X.

To prove that ak{g} exhausts the holomorphic vector fields on, note the group T acts on holomorphic vector fields. The restriction of such a vector field to gives a holomorphic map of A into A. The power series expansion around 0 is a convergent sum of homogeneous parts of degree . The action of scales the part of degree by . By taking Fourier coefficients with respect to T, the part of degree m is also a holomorphic vector field. Since conjugation by gives the inverse on, it follows that the only possible degrees are 0, 1 and 2. Degree 0 is accounted for by the constant fields. Since conjugation by interchanges degree 0 and degree 2, it follows that ak{g} _{\pm} account for all these holomorphic vector fields. Any further holomorphic vector field would have to appear in degree 1 and so would have the form for some in . Conjugation by J would give another such map N. Moreover, . But then\displaystyle{e ^{tM} ( 0 , 0 ,b) = Je ^{tN} J( 0 , 0 ,b) = Je ^{tN} (b, 0 , 0 ) = ( 0 , 0 ,e ^{tN} b).}

Set and . Then

\displaystyle{Q(U _{ta)b} = U _{tQ(a)V} _{-t} b.}

It follows that lies in for all and hence that lies in

ak{g} _{0} . So ak{g} is exactly the space of holomorphic vector fields on X.

Compact real form

Suppose acts trivially on ak{g} . Then must leave the subalgebra invariant. Hence so must . This forces, so that . But then must leave the subalgebra invariant, so that and . If acts trivially, .

The group can thus be identified with its image in GL

ak{g} .

Let be the complexification of a Euclidean Jordan algebra . For, set . The trace form on defines a complex inner product on and hence an adjoint operation. The unitary structure group consists of those in that are in, i.e. satisfy . It is a closed subgroup of U(A). Its Lie algebra consists of the skew-adjoint elements in

ak{g} _{0} . Define a conjugate linear involution on ak{g} by\displaystyle{\theta(a,T,b) = (b ^{*,-T} ^{*,} a ^{*).}}

This is a period 2 conjugate-linear automorphism of the Lie algebra. It induces an automorphism of, which on the generators is given by

\displaystyle{\theta(S _{a)=T} ^{a ^{*}} , \theta(j) = j, \theta(T _{b)=S} ^{b ^{*}} , \theta(W) = (W ^{*)} ^{-1} .}

Let be the fixed point subgroup of in . Let

ak{h} be the fixed point subalgebra of in ak{g} . Define a sesquilinear form on ak{g} by . This defines a complex inner product on ak{g} which restricts to a real inner product on ak{h} . Both are preserved by . Let be the identity component of . It lies in . Let be the diagonal torus associated with a Jordan frame in E. The action of is compatible with which sends a unimodular matrix \begin{pmatrix} \alpha & \beta\ \gamma & \delta\end{pmatrix} to \begin{pmatrix} \overline{\delta} & - \overline{\gamma}\ - \overline{\beta} & \overline{\alpha}\end{pmatrix} . In particular this gives a homomorphism of into .

Now every matrix in can be written as a product

\displaystyle{M = \begin{pmatrix} \zeta _{1} & 0 \ 0 & \zeta ^{-1} _{1} \end{pmatrix} \begin{pmatrix} \cos \varphi & \sin \varphi\ - \sin \varphi & \cos \varphi\end{pmatrix} \begin{pmatrix} \zeta _{2} & 0 \ 0 & \zeta ^{-1} _{2} \end{pmatrix}.}

The factor in the middle gives another maximal torus in obtained by conjugating by . If with |α_i| = 1, then gives the action of the diagonal torus and corresponds to an element of . The element lies in and its image is a Möbius transformation lying in . Thus is another torus in and coincides with the image of .

Since for the compact complex manifold corresponding to, if follows that, where is the image of . On the other hand,, so that. On the other hand, the stabilizer of in is, since the fixed point subgroup of under is . Hence . In particular H is compact and connected since both K and S are. Because it is a closed subgroup of U ak{g} , it is a Lie group. It contains K and hence its Lie algebra contains the operators with . It contains the image of and hence the elements with in . Since and, it follows that the Lie algebra ak{h} _{1} of contains for all in . Thus it contains ak{h} .

They are equal because all skew-adjoint derivations of

ak{h} are inner. In fact, since normalizes ak{h} and the action by conjugation is faithful, the map of ak{h} _{1} into the Lie algebra ak{d} of derivations of ak{h} is faithful. In particular ak{h} has trivial center. To show that ak{h} equals ak{h} _{1} , it suffices to show that ak{d} coincides with ak{h} . Derivations on ak{h} are skew-adjoint for the inner product given by minus the Killing form. Take the invariant inner product on ak{d} given by . Since ak{h} is invariant under ak{d} so is its orthogonal complement. They are both ideals in ak{d} , so the Lie bracket between them must vanish. But then any derivation in the orthogonal complement would have 0 Lie bracket with ak{h} , so must be zero. Hence ak{h} is the Lie algebra of . (This also follows from a dimension count since .)

The formulas above for the action of and show that the image of is closed in GL ak{g} . Since acts transitively on and the stabilizer of in is, it follows that . The compactness of and closedness of implies that is closed in GL ak{g} .

is a closed subgroup of GL ak{g} so a real Lie group. Since it contains with or, its Lie algebra contains ak{g} . Since ak{g} is the complexification of ak{h} , like ak{h} all its derivations are inner and it has trivial center. Since the Lie algebra of normalizes ak{g} and o is the only element centralizing ak{g} , as in the compact case the Lie algebra of must be ak{g} . (This can also be seen by a dimension count since .) Since it is a complex subspace, is a complex Lie group. It is connected because it is the continuous image of the connected set .Since ak{g} is the complexification of ak{h} , is the complexification of .

Noncompact real form

For in the spectral norm ||a|| is defined to be if with and in . It is independent of choices and defines a norm on . Let be the set of with ||a|| < 1 and let be the identity component of the closed subgroup of G carrying onto itself. It is generated by, the Möbius transformations in and the image of corresponding to a Jordan frame. Let τ be the conjugate-linear period 2 automorphism of

ak{g} defined by\displaystyle{\tau(a,T,b) = ( - a ^{*,-T} ^{*,-b} ^{*).}}

Let

ak{h} ^{*} be the fixed point algebra of τ. It is the Lie algebra of . It induces a period 2 automorphism of with fixed point subgroup . The group acts transitively on . The stabilizer of0 is .^[10]

The noncompact real semisimple Lie group acts on X with an open orbit . As with the action of on the Riemann sphere, it has only finitely many orbits. This orbit structure can be explicitly described when the Jordan algebra is simple. Let be the subset of consisting of elements with exactly of the α_i less than one and exactly of them greater than one. Thus . These sets are the intersections of the orbits of with . The orbits with are open. There is a unique compact orbit . It is the Shilov boundary S of D consisting of elements with in, the underlying Euclidean Jordan algebra. is in the closure of if and only if and .In particular is in the closure of every orbit.^[11]

Jordan algebras with involution

The preceding theory describes irreducible Hermitian symmetric spaces of tube type in terms of unital Jordan algebras. In general Hermitian symmetric spaces are described by a systematic extension of the above theory to Jordan pairs. In the development of, however, irreducible Hermitian symmetric spaces not of tube type are described in terms of period two automorphisms of simple Euclidean Jordan algebras. In fact any period 2 automorphism defines a Jordan pair: the general results of on Jordan pairs can be specialized to that setting.

Let τ be a period two automorphism of a simple Euclidean Jordan algebra E with complexification A. There are corresponding decompositions E = E₊ ⊕ E₋ and A = A₊ ⊕ A₋ into ±1 eigenspaces of τ. Let . τ is assumed to satisfy the additional condition that the trace form on defines an inner product. For in, define to be the restriction of to V. For a pair in, define and to be the restriction of and to . Then is simple if and only if the only subspaces invariant under all the operators and are and .

The conditions for quasi-invertibility in show that is invertible if and only if is invertible. The quasi-inverse is the same whether computed in or . A space of equivalence classes can be defined on pairs . It is a closed subspace of, so compact. It also has the structure of a complex manifold, modelled on . The structure group can be defined in terms of and it has as a subgroup the unitary structure group with identity component . The group is the identity component of the fixed point subgroup of τ in . Let be the group of biholomorphisms of generated by in, the identity component of, and the Abelian groups consisting of the and consisting of the with and in . It acts transitively on with stabilizer and. The Lie algebra

ak{g} _{\tau} of holomorphic vector fields on is a 3-graded Lie algebra,\displaystyle{ ak{g} _{\tau} = ak{g} _{\tau,+1} ⊕ ak{g} _{\tau,0} ⊕ ak{g} _{\tau,-1} .}

Restricted to the components are generated as before by the constant functions into, by the operators and by the operators . The Lie brackets are given by exactly the same formula as before.

The spectral decomposition in and is accomplished using tripotents, i.e. elements such that . In this case is an idempotent in . There is a Pierce decomposition into eigenspaces of . The operators and commute, so leaves the eigenspaces above invariant. In fact acts as 0 on, as 1/4 on and 1 on . This induces a Pierce decomposition . The subspace becomes a Euclidean Jordan algebra with unit under the mutation Jordan product .

Two tripotents and are said to be orthogonal if all the operators when a and b are powers of and and if the corresponding idempotents and are orthogonal. In this case and generate a commutative associative algebra and, since . Let be in . Let be the finite-dimensional real subspace spanned by odd powers of . The commuting self-adjoint operators with odd powers of act on, so can be simultaneously diagonalized by an orthonormal basis . Since is a positive multiple of, rescaling if necessary, can be chosen to be a tripotent. They form an orthogonal family by construction. Since is in, it can be written with real. These are called the eigenvalues of (with respect to τ). Any other tripotent in has the form with, so the are up to sign the minimal tripotents in .

A maximal family of orthogonal tripotents in is called a Jordan frame. The tripotents are necessarily minimal. All Jordan frames have the same number of elements, called the rank of . Any two frames are related by an element in the subgroup of the structure group of preserving the trace form. For a given Jordan frame, any element in can be written in the form with and an operator in . The spectral norm of is defined by ||a|| = sup α_i and is independent of choices. Its square equals the operator norm of . Thus becomes a complex normed space with open unit ball .

Note that for in, the operator is self-adjoint so that the norm |||| = ||||ⁿ. Since, it follows that |||| = ||||ⁿ. In particular the spectral norm of in is the square root of the spectral norm of . It follows that the spectral norm of is the same whether calculated in or . Since preserves both norms, the spectral norm on is obtained by restricting the spectral norm on .

For a Jordan frame, let . There is an action of on which extends to V. If and, then and give the action of the product of the lower and upper unitriangular matrices. If with, then the corresponding product of diagonal matrices act as, where . In particular the diagonal matrices give an action of and .

As in the case without an automorphism τ, there is an automorphism θ of . The same arguments show that the fixed point subgroup is generated by and the image of . It is a compact connected Lie group. It acts transitively on ; the stabilizer of is . Thus, a Hermitian symmetric space of compact type.

Let be the identity component of the closed subgroup of carrying onto itself. It is generated by and the image of corresponding to a Jordan frame. Let ρ be the conjugate-linear period 2 automorphism of

ak{g} _{\tau} defined by\displaystyle{\rho(a,T,b) = ( - a ^{*,-T} ^{*,-b} ^{*).}}

Let

ak{h} ^{*} _{\tau} be the fixed point algebra of ρ. It is the Lie algebra of . It induces a period 2 automorphism of with fixed point subgroup . The group acts transitively on . The stabilizer of0 is .^[12] is the Hermitian symmetric space of noncompact type dual to .

The Hermitian symmetric space of non-compact type have an unbounded realization, analogous the upper half-plane in C. Möbius transformations in corresponding to the Cayley transform and its inverse give biholomorphisms of the Riemann sphere exchanging the unit disk and the upper halfplane. When the Hermitian symmetric space is of tube type the same Möbius transformations map the disk in onto the tube domain were is the open self-dual convex cone of squares in the Euclidean Jordan algebra .

For Hermitian symmetric space not of tube type there is no action of on X, so no analogous Cayley transform. A partial Cayley transform can be defined in that case for any given maximal tripotent in . It takes the disk in onto a Siegel domain of the second kind.

In this case is a Euclidean Jordan algebra and there is symmetric -valued bilinear form on such that the corresponding quadratic form takes values in its positive cone . The Siegel domain consists of pairs such that lies in .The quadratic form on and the squaring operation on are given by . The positive cone corresponds to with invertible.

Examples

For simple Euclidean Jordan algebras with complexication, the Hermitian symmetric spaces of compact type can be described explicitly as follows, using Cartan's classification.

Type I_n. A is the Jordan algebra of n × n complex matrices with the operator Jordan product . It is the complexification of, the Euclidean Jordan algebra of self-adjoint n × n complex matrices. In this case acting on with

g = \begin{pmatrix}a & b \ c & d\end{pmatrix} acting as . Indeed, this can be verified directly for diagonal, upper and lower unitriangular matrices which correspond to the operators, and . The subset corresponds to the matrices with invertible. In fact consider the space of linear maps from to . It is described by a pair (|) with in . This is a module for acting on the target space. There is also an action of induced by the action on the source space. The space of injective maps is invariant and acts freely on it. The quotient is the Grassmannian consisting of n-dimensional subspaces of . Define a map of into by sending to the injective map (|). This map induces an isomorphism of onto .

In fact let be an n-dimensional subspace of . If it is in general position, i.e. it and its orthogonal complement have trivial intersection with and, it is the graph of an invertible operator .So the image corresponds to (|) with and .

At the other extreme, and its orthogonal complement can be written as orthogonal sums,, where and are the intersections with and and with . Then and . Moreover, and . The subspace corresponds to the pair (|), where is the orthogonal projection of onto . So and .

The general case is a direct sum of these two cases. can be written as an orthogonal sum where and are the intersections with and and is their orthogonal complement in . Similarly the orthogonal complement of can be written . Thus and, where are orthogonal complements. The direct sum is of the second kind and its orthogonal complement of the first.

Maps in the structure group correspond to in, with . The corresponding map on sends (|) to(|). Similarly the map corresponding to sends (|) to(|), the map corresponding to sends (|) to(|) and the map corresponding to sends(|) to (|). It follows that the map corresponding to sends (|) to(|).On the other hand, if is invertible,(|) is equivalent to(|), whence the formula for the fractional linear transformation.

Type III_n. A is the Jordan algebra of n × n symmetric complex matrices with the operator Jordan product . It is the complexification of, the Euclidean Jordan algebra of n × n symmetric real matrices. On, define a nondegenerate alternating bilinear form by . In matrix notation if

J = \begin{pmatrix} 0 & I \ - I & 0 \end{pmatrix} ,\displaystyle{\omega(z _{1,z} ^{t.}} ^{2 ) = zJz}

Let denote the complex symplectic group, the subgroup of preserving ω. It consists of such that and is closed under . If

g = \begin{pmatrix}a & b \ c & d\end{pmatrix} belongs to then\displaystyle{g ^{-1} = \begin{pmatrix}d ^{t} & - c ^{t} \ - b ^{t} & a ^{t\end{pmatrix}.}}

It has center . In this case acting on as . Indeed, this can be verified directly for diagonal, upper and lower unitriangular matrices which correspond to the operators, and . The subset corresponds to the matrices with invertible. In fact consider the space of linear maps from to . It is described by a pair (|) with in . This is a module for acting on the target space. There is also an action of induced by the action on the source space. The space of injective maps with isotropic image, i.e. ω vanishes on the image, is invariant. Moreover, acts freely on it. The quotient is the symplectic Grassmannian consisting of n-dimensional Lagrangian subspaces of . Define a map of into by sending to the injective map (|). This map induces an isomorphism of onto .

In fact let be an n-dimensional Lagrangian subspace of . Let be a Lagrangian subspace complementing . If they are in general position, i.e. they have trivial intersection with and, than is the graph of an invertible operator with . So the image corresponds to (|) with and .

At the other extreme, and can be written as direct sums,, where and are the intersections with and and with . Then and . Moreover, and . The subspace corresponds to the pair (|), where is the projection of onto . Note that the pair is in duality with respect to ω and the identification between them induces the canonical symmetric bilinear form on . In particular V₁ is identified with U₂ and V₂ with U₁. Moreover, they are V₁ and U₁ are orthogonal with respect to the symmetric bilinear form on (. Hence the idempotent satisfies . So and lie in and is the image of (|).

The general case is a direct sum of these two cases. can be written as a direct sum where and are the intersections with and and is a complement in . Similarly can be written . Thus and, where are complements. The direct sum is of the second kind. It has a complement of the first kind.

Maps in the structure group correspond to in, with . The corresponding map on sends (|) to(|). Similarly the map corresponding to sends (|) to(|), the map corresponding to sends (|) to(|) and the map corresponding to sends(|) to (|). It follows that the map corresponding to sends (|) to(|).On the other hand, if is invertible,(|) is equivalent to(|), whence the formula for the fractional linear transformation.

Type II_2n. A is the Jordan algebra of 2n × 2n skew-symmetric complex matrices and Jordan product where the unit is given by

J = \begin{pmatrix} 0 & I \ - I & 0 \end{pmatrix} . It is the complexification of, the Euclidean Jordan algebra of self-adjoint n × n matrices with entries in the quaternions. This is discussed in and .

Type IV_n. A is the Jordan algebra with Jordan product . It is the complexication of the rank 2 Euclidean Jordan algebra defined by the same formulas but with real coefficients. This is discussed in .

Type VI. The complexified Albert algebra. This is discussed in, and .

The Hermitian symmetric spaces of compact type for simple Euclidean Jordan algebras with period two automorphism can be described explicitly as follows, using Cartan's classification.

Type I_p,q. Let F be the space of q by p matrices over R with p ≠ q. This corresponds to the automorphism of E = H_{p + q}(R) given by conjugating by the diagonal matrix with p diagonal entries equal to 1 and q to −1. Without loss of generality can be taken greater than . The structure is given bythe triple product . The space X can be identified with the Grassmannian of -dimensional subspace of . This has a natural embedding in by adding 0's in the last coordinates. Since any -dimensional subspace of can be represented in the form [{{math|1=''I'' − ''y''^''t''''x''}}|{{math|''x''}}], the same is true for subspaces lying in . The last rows of must vanish and the mapping does not change if the last rows of are set equal to zero. So a similar representation holds for mappings, but now with q by p matrices. Exactly as when, it follows that there is an action of by fractional linear transformations.^[13]

Type II_n F is the space of real skew-symmetric m by m matrices. After removing a factor of, this corresponds to the period 2 automorphism given by complex conjugation on E = H_n(C).

Type V. F is the direct sum of two copies of the Cayley numbers, regarded as 1 by 2 matrices. This corresponds to the canonical period 2 automorphism defined by any minimal idempotent in E = H₃(O).

See also

• Mutation (algebra)
• Symmetric cone

Notes and References

1. See:
2. See:
3. See:
4. See:
5. See:
6. In the main application in, A is finite dimensional. In that case invertibility of operators on A is equivalent to injectivity or surjectivity. The general case is treated in and .
7. See:
8. See:
9. See:
10. See:
11. See:
12. See:
13. See: