In mathematics, the n-th hyperharmonic number of order r, denoted by
(r) | |
H | |
n |
(0) | |
H | |
n |
=
1 | |
n |
,
and
(r) | |
H | |
n |
=
n | |
\sum | |
k=1 |
(r-1) | |
H | |
k |
(r>0).
In particular,
Hn=H
(1) | |
n |
The hyperharmonic numbers were discussed by J. H. Conway and R. K. Guy in their 1995 book The Book of Numbers.
By definition, the hyperharmonic numbers satisfy the recurrence relation
(r) | |
H | |
n |
=
(r) | |
H | |
n-1 |
+
(r-1) | |
H | |
n |
.
In place of the recurrences, there is a more effective formula to calculate these numbers:
(r) | |
H | |
n |
=\binom{n+r-1}{r-1}(Hn+r-1-Hr-1).
The hyperharmonic numbers have a strong relation to combinatorics of permutations. The generalization of the identity
Hn=
1 | |
n! |
\left[{n+1\atop2}\right].
reads as
(r) | |
H | |
n |
=
1 | |
n! |
\left[{n+r\atopr+1}\right]r,
where
\left[{n\atopr}\right]r
The above expression with binomial coefficients easily gives that for all fixed order r>=2 we have.[2]
(r) | ||
H | \sim | |
n |
1 | |
(r-1)! |
\left(nr-1ln(n)\right),
An immediate consequence is that
| ||||||||||
\sum | ||||||||||
n=1 |
<+infty
when m>r.
The generating function of the hyperharmonic numbers is
infty | |
\sum | |
n=0 |
(r) | |
H | |
n |
| ||||
z |
.
The exponential generating function is much more harder to deduce. One has that for all r=1,2,...
infty | |
\sum | |
n=0 |
(r) | |
H | |
n |
tn | |
n! |
r-1 | |
=e | |
n=1 |
(r-n) | |
H | |
n |
tn | + | |
n! |
(r-1)! | |
(r!)2 |
r | |
t | |
2 |
F2\left(1,1;r+1,r+1;-t\right)\right),
The next relation connects the hyperharmonic numbers to the Hurwitz zeta function:
| ||||||||||
\sum | ||||||||||
n=1 |
infty | |
=\sum | |
n=1 |
(r-1) | |
H | |
n |
\zeta(m,n) (r\ge1,m\ger+1).
It is known, that the harmonic numbers are never integers except the case n=1. The same question can be posed with respect to the hyperharmonic numbers: are there integer hyperharmonic numbers? István Mező proved[4] that if r=2 or r=3, these numbers are never integers except the trivial case when n=1. He conjectured that this is always the case, namely, the hyperharmonic numbers of order r are never integers except when n=1. This conjecture was justified for a class of parameters by R. Amrane and H. Belbachir.[5] Especially, these authors proved that
(4) | |
H | |
n |
(r) | |
H | |
n |
Another result is the following.[7] Let
S(x)
(n,x)\in[0,x] x [0,x]
S(x)=x2+O(xlog3x).
[0,x] x [0,x]
x2+O(x2)
The problem was finally settled by D. C. Sertbaş who found that there are infinitely many hyperharmonic integers, albeit they are quite huge. The smallest hyperharmonic number which is an integer found so far is[8]
(64(22659-1)+32) | |
H | |
33 |
.