Hobart Township, Lake County, Indiana Explained

Official Name:Hobart Township
Settlement Type:Township
Subdivision Type:Country
Subdivision Name:United States
Subdivision Type1:State
Subdivision Name1:Indiana
Subdivision Type2:County
Subdivision Name2:Lake
Government Type:Indiana township
Area Total Sq Mi:25.98
Area Land Sq Mi:25.47
Area Water Sq Mi:0.51
Population As Of:2020
Population Footnotes:[1]
Population Total:40652
Population Density Sq Mi:1547.4
Elevation Footnotes:[2]
Elevation M:191
Elevation Ft:627
Coordinates:41.5467°N -87.2647°W
Blank Name:FIPS code
Blank Info:18-34132[3]
Blank1 Name:GNIS feature ID
Blank1 Info:453414

Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.[4]

Geography

According to the 2010 census, the township has a total area of, of which (or 98.04%) is land and (or 1.96%) is water.[4]

References

  1. Web site: May 2023 . Census Bureau profile: Hobart Township, Lake County, Indiana . . March 15, 2024.
  2. Web site: US Board on Geographic Names. 2008-01-31. United States Geological Survey. 2007-10-25.
  3. Web site: U.S. Census website. United States Census Bureau. 2008-01-31.
  4. Web site: Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1 . https://archive.today/20200212203256/http://factfinder.census.gov/bkmk/table/1.0/en/DEC/10_SF1/GCTPH1.CY10/0500000US18089 . dead . 2020-02-12 . United States Census . 2013-05-10.

External links