Harlan Township, Fayette County, Iowa Explained

Official Name:Harlan Township
Settlement Type:Township
Subdivision Type:Country
Subdivision Type1:State
Subdivision Type2:County
Subdivision Name2:Fayette
Area Total Km2:95.28
Area Land Km2:95.22
Area Water Km2:0.07
Unit Pref:Imperial
Area Total Sq Mi:36.79
Area Land Sq Mi:36.76
Area Water Sq Mi:0.03
Area Water Percent:0.07
Population As Of:2010
Population Total:871
Population Density Km2:auto
Elevation M:349
Elevation Ft:1145
Coordinates:42.7808°N -91.9125°W
Timezone:CST
Utc Offset:-6
Timezone Dst:CDT
Utc Offset Dst:-5
Postal Code Type:ZIP codes
Postal Code:50655, 50662, 50681, 52142, 52164
Blank Name:GNIS feature ID
Blank Info:0468005

Harlan Township is one of twenty townships in Fayette County, Iowa. As of the 2010 census, its population was 871.[1]

Geography

According to the United States Census Bureau, Harlan Township covers an area of 36.79 square miles (95.28 square kilometers); of this, 36.76 square miles (95.22 square kilometers, 99.94 percent) is land and 0.03 square miles (0.07 square kilometers, 0.07 percent) is water.

Cities, towns, villages

Adjacent townships

Cemeteries

The township contains these two cemeteries: Hope and Long Grove.

Major highways

Landmarks

School districts

Political districts

References

External links

Notes and References

  1. Web site: Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Harlan township, Fayette County, Iowa. United States Census Bureau. March 5, 2012.