Gyroelongated pentagonal cupola explained

Type:Johnson
J23 - J24 - J25
Faces:3x5+10 triangles
5 squares
1 pentagon
1 decagon
Edges:55
Vertices:25
Symmetry:C5v
Vertex Config:5(3.4.5.4)
2.5(33.10)
10(34.4)
Dual:-
Properties:convex
Net:Johnson solid 24 net.png

In geometry, the gyroelongated pentagonal cupola is one of the Johnson solids (J24). As the name suggests, it can be constructed by gyroelongating a pentagonal cupola (J5) by attaching a decagonal antiprism to its base. It can also be seen as a gyroelongated pentagonal bicupola (J46) with one pentagonal cupola removed.

Area and Volume

With edge length a, the surface area is

A=1
4

\left(20+25\sqrt{3}+\left(10+\sqrt{5}\right)\sqrt{5+2\sqrt{5}}\right)a2 ≈ 25.240003791...a2,

and the volume is

V=\left(5+
6
2
3

\sqrt{5}+

5
6

\sqrt{2\sqrt{650+290\sqrt{5}}-2\sqrt{5}-2}\right)a3 ≈ 9.073333194...a3.

Dual polyhedron

The dual of the gyroelongated pentagonal cupola has 25 faces: 10 kites, 5 rhombi, and 10 pentagons.