In quantum field theory, the Gupta–Bleuler formalism is a way of quantizing the electromagnetic field. The formulation is due to theoretical physicists Suraj N. Gupta and Konrad Bleuler.
Firstly, consider a single photon. A basis of the one-photon vector space (it is explained why it is not a Hilbert space below) is given by the eigenstates
|k,\epsilon\mu\rangle
k
k2=0
k0
\epsilon\mu
\mu
k
\vec{k}
\langle\vec{k}a;\epsilon\mu|\vec{k}b;\epsilon\nu\rangle=(-η\mu\nu)2|\vec{k}a|\delta(\vec{k}a-\vec{k}b)
where the
2|\vec{k}a|
If one includes gauge covariance, one realizes a photon can have three possible polarizations (two transverse and one longitudinal (i.e. parallel to the 4-momentum)). This is given by the restriction
k ⋅ \epsilon=0
To resolve this difficulty, first look at the subspace with three polarizations. The sesquilinear form restricted to it is merely semidefinite, which is better than indefinite.In addition, the subspace with zero norm turns out to be none other than the gauge degrees of freedom. So, define the physical Hilbert space to be the quotient space of the three polarization subspace by its zero norm subspace. This space has a positive definite form, making it a true Hilbert space.
A
\partial\mu\partial\muA=0
with the condition
\langle\chi|\partial\muA\mu|\psi\rangle=0
for physical states
|\chi\rangle
|\psi\rangle
This is not the same thing as
\partial\muA\mu=0
Note that if O is any gauge invariant operator,
\langle\chi|O|\psi\rangle
does not depend upon the choice of the representatives of the equivalence classes, and so, this quantity is well-defined.
This is not true for non-gauge-invariant operators in general because the Lorenz gauge still leaves residual gauge degrees of freedom.
In an interacting theory of quantum electrodynamics, the Lorenz gauge condition still applies, but
A