In quantum mechanics, the results of the quantum particle in a box can be used to look at the equilibrium situation for a quantum ideal gas in a box which is a box containing a large number of molecules which do not interact with each other except for instantaneous thermalizing collisions. This simple model can be used to describe the classical ideal gas as well as the various quantum ideal gases such as the ideal massive Fermi gas, the ideal massive Bose gas as well as black body radiation (photon gas) which may be treated as a massless Bose gas, in which thermalization is usually assumed to be facilitated by the interaction of the photons with an equilibrated mass.
Using the results from either Maxwell–Boltzmann statistics, Bose–Einstein statistics or Fermi–Dirac statistics, and considering the limit of a very large box, the Thomas–Fermi approximation (named after Enrico Fermi and Llewellyn Thomas) is used to express the degeneracy of the energy states as a differential, and summations over states as integrals. This enables thermodynamic properties of the gas to be calculated with the use of the partition function or the grand partition function. These results will be applied to both massive and massless particles. More complete calculations will be left to separate articles, but some simple examples will be given in this article.
For both massive and massless particles in a box, the states of a particle areenumerated by a set of quantum numbers . The magnitude of the momentum is given by
p= | h |
2L |
2} | |
\sqrt{n | |
z |
nx,ny,nz=1,2,3,\ldots
| ||||
n=\sqrt{n | ||||
z |
Suppose each set of quantum numbers specify f states where f is the number of internal degrees of freedom of the particle that can be altered by collision. For example, a spin particle would have, one for each spin state. For large values of n, the number of states with magnitude of momentum less than or equal to p from the above equation is approximately
g=\left(
f | |
8 |
\right)
4 | |
3 |
\pin3=
4\pif | \left( | |
3 |
Lp | |
h |
\right)3
dg=
\pi | |
2 |
~fn2dn=
4\pifV | |
h3 |
~p2dp
Without using any approximation, the number of particles with energy εi is given by
Ni=
gi | |
\Phi(\varepsiloni) |
gi
Using the Thomas−Fermi approximation, the number of particles dNE with energy between E and is:
dNE=
dgE | |
\Phi(E) |
dgE
Using the results derived from the previous sections of this article, some distributions for the gas in a box can now be determined. For a system of particles, the distribution
PA
A
PAdA
A
A
A+dA
PA~dA=
dNA | |
N |
=
dgA | |
N\PhiA |
dNA
A
A
A+dA
dgA
A
A
A+dA
-1 | |
\Phi | |
A |
A
N
It follows that:
\intAPA~dA=1
For a momentum distribution
Pp
p
p+dp
Pp~dp=
Vf | ~ | |
N |
4\pi | ||||||
|
~p2dp
PE
E
E+dE
PE~dE=
P | ||||
|
~dE
For a particle in a box (and for a free particle as well), the relationship between energy
E
p
E= | p2 |
2m |
E=pc
m
c
dg_E & = \quad \ \left(\frac\right)\frac~\beta^E^~dE \\ P_E~dE & = \frac\left(\frac\right)\frac~\frac~dE \\\end where is the thermal wavelength of the gas. This is an important quantity, since when is on the order of the inter-particle distance
(V/N)1/3
dg_E & = \quad \ \left(\frac\right)\frac~\beta^3E^2~dE \\ P_E~dE & = \frac\left(\frac\right)\frac~\frac~dE \\\end where is now the thermal wavelength for massless particles.
The following sections give an example of results for some specific cases.
For this case:
\Phi(E)=e\beta(E-\mu)
Integrating the energy distribution function and solving for N gives
N=\left(
Vf | |
Λ3 |
\right)e\beta\mu
Substituting into the original energy distribution function gives
PE~dE=2\sqrt{
\beta3E | |
\pi |
For this case:
\Phi(E)= | e\beta |
z |
-1
z=e\beta\mu.
Integrating the energy distribution function and solving for N gives the particle number
N=\left(
Vf | |
Λ3 |
\right)rm{Li}3/2(z)
N=\left(
Vf | ||||||
|
\right)\zeta(3/2),
\zeta(z)
N= | g0z | +\left( |
1-z |
Vf | |
Λ3 |
\right)\operatorname{Li}3/2(z)
For the case of massless particles, the massless energy distribution function must be used. It is convenient to convert this function to a frequency distribution function:
P\nu~d\nu=
h3 | \left( | |
N |
Vf | \right) | |
Λ3 |
1 | ~ | |
2 |
\beta3\nu2 | ||||||
|
~d\nu
U\nu~d\nu=\left(
Nh\nu | |
V |
\right)P\nu~d\nu=
4\pifh\nu3 | ~ | |
c3 |
1 | ||||||
|
~d\nu.
Other thermodynamic parameters may be derived analogously to the case for massive particles. For example, integrating the frequency distribution function and solving for N gives the number of particles:
N= | 16\piV |
c3h3\beta3 |
\mu/k\rmT | |
Li | |
3\left(e |
\right).
The most common massless Bose gas is a photon gas in a black body. Taking the "box" to be a black body cavity, the photons are continually being absorbed and re-emitted by the walls. When this is the case, the number of photons is not conserved. In the derivation of Bose–Einstein statistics, when the restraint on the number of particles is removed, this is effectively the same as setting the chemical potential (μ) to zero. Furthermore, since photons have two spin states, the value of f is 2. The spectral energy density is then
U\nu~d\nu=
8\pih\nu3 | ~ | |
c3 |
1 | ||||||
|
~d\nu
In certain situations, the reactions involving photons will result in the conservation of the number of photons (e.g. light-emitting diodes, "white" cavities). In these cases, the photon distribution function will involve a non-zero chemical potential. (Hermann 2005)
Another massless Bose gas is given by the Debye model for heat capacity. This model considers a gas of phonons in a box and differs from the development for photons in that the speed of the phonons is less than light speed, and there is a maximum allowed wavelength for each axis of the box. This means that the integration over phase space cannot be carried out to infinity, and instead of results being expressed in polylogarithms, they are expressed in the related Debye functions.
For this case:
\Phi(E)=e\beta(E-\mu)+1.
Integrating the energy distribution function gives
N=\left( | Vf |
Λ3 |
\right)\left[-rm{Li}3/2(-z)\right]