Frullani integral explained

In mathematics, Frullani integrals are a specific type of improper integral named after the Italian mathematician Giuliano Frullani. The integrals are of the form

\int

infty
{
0
f(ax)-f(bx)
x
}\,xwhere

f

is a function defined for all non-negative real numbers that has a limit at

infty

, which we denote by

f(infty)

.

The following formula for their general solution holds if

f

is continuous on

(0,infty)

, has finite limit at

infty

, and

a,b>0

:

\int

infty
{
0
f(ax)-f(bx)
x
}\,x=\Big(f(\infty)-f(0)\Big)\ln .

Proof for continuously differentiable functions

A simple proof of the formula (under stronger assumptions than those stated above, namely

f\inl{C}1(0,infty)

) can be arrived at by using the Fundamental theorem of calculus to express the integrand as an integral of

f'(xt)=

\partial\left(
\partialt
f(xt)
x

\right)

:

\begin{align}

f(ax)-f(bx)
x

&=\left[

f(xt)
x
t=a
\right]
t=b

\\ &=

a
\int
b

f'(xt)dt\\ \end{align}

and then use Tonelli’s theorem to interchange the two integrals:

\begin{align}

infty
\int
0
f(ax)-f(bx)
x

dx&=

infty
\int
0
a
\int
b

f'(xt)dtdx\\ &=

a
\int
b
infty
\int
0

f'(xt)dxdt\\ &=

a
\int\left[
b
f(xt)
t
x\toinfty
\right]
x=0

dt\\ &=

a
\int
b
f(infty)-f(0)
t

dt\\ &=(f(infty)-f(0))(ln(a)-ln(b))\\ &=(f(infty)-f(0))ln(

a
b

)\\ \end{align}

Note that the integral in the second line above has been taken over the interval

[b,a]

, not

[a,b]

.

Applications

ln(x)

by letting

f(x)=e-x

and

a=1

:

{\int

infty
{
0
e-x-e-bx
x
}\,x=\Big(\lim_\frac-e^0\Big)\ln \Big(}\Big) = \ln(b)

The formula can also be generalized in several different ways.[1]

References

Notes and References

  1. Bravo . Sergio . Gonzalez . Ivan . Kohl . Karen . Moll . Victor Hugo . Victor Hugo Moll . Integrals of Frullani type and the method of brackets . Open Mathematics . 21 January 2017 . 15 . 1 . 10.1515/math-2017-0001 . 17 June 2020. free .