Free module explained

In mathematics, a free module is a module that has a basis, that is, a generating set consisting of linearly independent elements. Every vector space is a free module,[1] but, if the ring of the coefficients is not a division ring (not a field in the commutative case), then there exist non-free modules.

Given any set and ring, there is a free -module with basis, which is called the free module on or module of formal -linear combinations of the elements of .

A free abelian group is precisely a free module over the ring of integers.

Definition

R

and an

R

-module

M

, the set

E\subseteqM

is a basis for

M

if:

E

is a generating set for

M

; that is to say, every element of

M

is a finite sum of elements of

E

multiplied by coefficients in

R

; and

E

is linearly independent if for every

\{e1,...,en\}\subsetE

of distinct elements,

r1e1+r2e2++rnen=0M

implies that

r1=r2==rn=0R

(where

0M

is the zero element of

M

and

0R

is the zero element of

R

).

A free module is a module with a basis.[2]

An immediate consequence of the second half of the definition is that the coefficients in the first half are unique for each element of M.

If

R

has invariant basis number, then by definition any two bases have the same cardinality. For example, nonzero commutative rings have invariant basis number. The cardinality of any (and therefore every) basis is called the rank of the free module

M

. If this cardinality is finite, the free module is said to be free of finite rank, or free of rank if the rank is known to be .

Examples

Let R be a ring.

Z

), a submodule of a free module is free.

R[X]

in indeterminate X is a free module with a possible basis 1, X, X2, ....

A[t]

be a polynomial ring over a commutative ring A, f a monic polynomial of degree d there,

B=A[t]/(f)

and

\xi

the image of t in B. Then B contains A as a subring and is free as an A-module with a basis

1,\xi,...,\xid-1

.

Rn=R x x R

, the cartesian product of n copies of R as a left R-module, is free. If R has invariant basis number, then its rank is n.

Formal linear combinations

Given a set and ring, there is a free -module that has as a basis: namely, the direct sum of copies of R indexed by E

R(E)=opluseR

.Explicitly, it is the submodule of the Cartesian product \prod_E R (R is viewed as say a left module) that consists of the elements that have only finitely many nonzero components. One can embed E into as a subset by identifying an element e with that of whose e-th component is 1 (the unity of R) and all the other components are zero. Then each element of can be written uniquely as

\sumecee,

where only finitely many

ce

are nonzero. It is called a formal linear combination of elements of .

A similar argument shows that every free left (resp. right) R-module is isomorphic to a direct sum of copies of R as left (resp. right) module.

Another construction

The free module may also be constructed in the following equivalent way.

Given a ring R and a set E, first as a set we let

R(E)=\{f:E\toR\midf(x)=0forallbutfinitelymanyx\inE\}.

We equip it with a structure of a left module such that the addition is defined by: for x in E,

(f+g)(x)=f(x)+g(x)

and the scalar multiplication by: for r in R and x in E,

(rf)(x)=rf(x)

Now, as an R-valued function on E, each f in

R(E)

can be written uniquely as

f=\sumece\deltae

where

ce

are in R and only finitely many of them are nonzero and

\deltae

is given as

\deltae(x)=\begin{cases}1Rifx=e\ 0Rifxe\end{cases}

(this is a variant of the Kronecker delta). The above means that the subset

\{\deltae\mide\inE\}

of

R(E)

is a basis of

R(E)

. The mapping

e\mapsto\deltae

is a bijection between and this basis. Through this bijection,

R(E)

is a free module with the basis E.

Universal property

The inclusion mapping

\iota:E\toR(E)

defined above is universal in the following sense. Given an arbitrary function

f:E\toN

from a set to a left -module, there exists a unique module homomorphism

\overline{f}:R(E)\toN

such that

f=\overline{f}\circ\iota

; namely,

\overline{f}

is defined by the formula:

\overline{f}\left(\sumeree\right)=\sumeref(e)

and

\overline{f}

is said to be obtained by extending

f

by linearity.
The uniqueness means that each R-linear map

R(E)\toN

is uniquely determined by its restriction to E.

As usual for universal properties, this defines up to a canonical isomorphism. Also the formation of

\iota:E\toR(E)

for each set E determines a functor

R(-):bf{Set}\toR-Mod,E\mapstoR(E)

,from the category of sets to the category of left -modules. It is called the free functor and satisfies a natural relation: for each set E and a left module N,

\operatorname{Hom}bf{Set

}(E, U(N)) \simeq \operatorname_R(R^, N), \, f \mapsto \overlinewhere

U:R-Mod\tobf{Set}

is the forgetful functor, meaning

R(-)

is a left adjoint of the forgetful functor.

Generalizations

Many statements true for free modules extend to certain larger classes of modules. Projective modules are direct summands of free modules. Flat modules are defined by the property that tensoring with them preserves exact sequences. Torsion-free modules form an even broader class. For a finitely generated module over a PID (such as Z), the properties free, projective, flat, and torsion-free are equivalent.

See local ring, perfect ring and Dedekind ring.

See also

Notes

  1. Book: Keown . [{{Google books|plainurl=y|id=hC9iTw8DO7gC|page=24|text=Every vector space is free}} An Introduction to Group Representation Theory]. 1975. 24.
  2. Book: Hazewinkel . [{{Google books|plainurl=y|id=s9F71NJxwzoC|page=110|text=A free module is a module with a basis}} Encyclopaedia of Mathematics, Volume 4]. 1989. 110.
  3. Proof: Suppose

    I

    is free with a basis

    \{xj|j\}

    . For

    j\nek

    ,

    xjxk

    must have the unique linear combination in terms of

    xj

    and

    xk

    , which is not true. Thus, since

    I\ne0

    , there is only one basis element which must be a nonzerodivisor. The converse is clear.

    \square

References