Football at the 1960 Summer Olympics – final explained
The 1960 Summer Olympics football tournament gold medal match was the final match of the 1960 Summer Olympics football tournament, the 13th edition of Olympic competition for men's national football teams. The match was played at Stadio Flaminio in Rome, Italy, on 10 September 1960, and was contested by Yugoslavia and Denmark.[1]
The tournament comprised hosts Italy and 15 other teams who emerged victorious from the qualification phase, The 16 teams competed in a group stage in the first round, from which 16 teams qualified for the knockout stage.[2] En route to the final, Yugoslavia finished first in Group 1 with two wins and one draw, first winning against United Arab Republic 6–1 and Turkey 4–0, then drawing against Bulgaria 3–3. They then beat hosts Italy in the semi-finals by lots after a 1–1 draw. Denmark finished first in Group 3 with three wins, defeating Argentina 3–2, Poland 2–1 and Tunisia 3–1), and defeating Hungary 2–0 in the semi-finals. The final took place in front of 23,042 spectators and was refereed by Concetto Lo Bello.
Yugoslavia took the lead in the first minute through Milan Galić in the first minute before Željko Matuš further increased their lead in the 11th minute. A third goal was scored for Yugoslavia through Bora Kostić in the 69th minute, only then Denmark scored a consolation goal in the 90th minute by Flemming Nielsen, until Yugoslavia won the match and became gold medalists for 1960.[3]
Route to the final
Yugoslavia
Denmark
Match
Details
See also
Notes and References
- Web site: Olympic Games 1960 » Final. worldfootball.net. 5 August 2024.
- Web site: XVII. Olympiad Rome 1960 Football Tournament. Reyes. Macario. RSSSF. 20 June 2019.
- News: Ethiopian Winner In Marathon. Reading Eagle. 11 September 1960. 25.