Folkman graph | |
Vertices: | 20 |
Edges: | 40 |
Girth: | 4 |
Diameter: | 4 |
Radius: | 3 |
Automorphisms: | 5! ยท 25 = 3840 |
Chromatic Number: | 2 |
Chromatic Index: | 4 |
Book Thickness: | 3 |
Queue Number: | 2 |
Genus: | 3 |
Properties: |
In the mathematical field of graph theory, the Folkman graph is a 4-regular graph with 20 vertices and 40 edges. It is a regular bipartite graph with symmetries taking every edge to every other edge, but the two sides of its bipartition are not symmetric with each other, making it the smallest possible semi-symmetric graph. It is named after Jon Folkman, who constructed it for this property in 1967.
The Folkman graph can be constructed either using modular arithmetic or as the subdivided double of the five-vertex complete graph. Beyond the investigation of its symmetry, it has also been investigated as a counterexample for certain questions of graph embedding.
Semi-symmetric graphs are defined as regular graphs (that is, graphs in which all vertices touch equally many edges) in which each two edges are symmetric to each other, but some two vertices are not symmetric. Jon Folkman was inspired to define and research these graphs in a 1967 paper, after seeing an unpublished manuscript by E. Dauber and Frank Harary which gave examples of graphs meeting the symmetry condition but not the regularity condition. Folkman's original construction of this graph was a special case of a more general construction of semi-symmetric graphs using modular arithmetic, based on a prime number
p
r
r2=-1
p
2pr
p=5
r=2
Another construction for the Folkman graph begins with the complete graph on five vertices,
K5
K5
K5
K5
Because each edge of the result comes from a doubled half of an edge of
K5
K5
K5
The automorphism group of the Folkman graph (its group of symmetries) combines the
5!
K5
25
5! ⋅ 25=3840
Like all semi-symmetric graphs, the Folkman graph is bipartite. Its automorphism group includes symmetries taking any vertex to any other vertex that is on the same side of the bipartition, but none that take a vertex to the other side of the bipartition. Although one can argue directly that the Folkman graph is not vertex-transitive, this can also be explained group-theoretically: its symmetries act primitively on the vertices constructed as subdivision points of
K5
K5
The characteristic polynomial of the Folkman graph is
(x-4)x10(x+4)(x2-6)4
The Folkman graph has a Hamiltonian cycle, and more strongly a Hamiltonian decomposition into two Hamiltonian cycles. Like every bipartite graph, its chromatic number is two, and its chromatic index (the minimum number of colors needed to color its edges so that no two edges of the same color meet at a vertex) equals its maximum degree, which in this case is four. For instance, such a coloring can be obtained by using two colors in alternation for each cycle of a Hamiltonian decomposition.
Its radius is 3 and its diameter is 4. If
v
K5
v
K5
The Folkman graph has genus 3: it can be embedded on a triple torus, but not on any simpler oriented surface. It has book thickness 3, but requires five pages for a "dispersable" book embedding in which each page is a matching, disproving a conjecture of Frank Bernhart and Paul Kainen that dispersable book embeddings of regular graphs need only a number of pages equal to their degree.