Fatou's theorem explained

Fatou's theorem should not be confused with Fatou's lemma.

In mathematics, specifically in complex analysis, Fatou's theorem, named after Pierre Fatou, is a statement concerning holomorphic functions on the unit disk and their pointwise extension to the boundary of the disk.

Motivation and statement of theorem

If we have a holomorphic function

f

defined on the open unit disk

D=\{z:|z|<1\}

, it is reasonable to ask under what conditions we can extend this function to the boundary of the unit disk. To do this, we can look at what the function looks like on each circle inside the disk centered at 0, each with some radius

r

. This defines a new function:

\begin{cases}

1
f
r:S

\to\Complex\fr(ei\theta)=f(rei\theta)\end{cases}

where

S1:=\{ei\theta:\theta\in[0,2\pi]\}=\{z\in\Complex:|z|=1\},

is the unit circle. Then it would be expected that the values of the extension of

f

onto the circle should be the limit of these functions, and so the question reduces to determining when

fr

converges, and in what sense, as

r\to1

, and how well defined is this limit. In particular, if the

Lp

norms
of these

fr

are well behaved, we have an answer:

Theorem. Let

f:D\to\Complex

be a holomorphic function such that

\sup0<r<1\|fr\|

Lp(S1)

<infty,

where

fr

are defined as above. Then

fr

converges to some function

f1\inLp(S1)

pointwise almost everywhere and in

Lp

norm. That is,

\begin{align} \left

i\theta
|f
r(e

)-f1(ei\theta)\right|&\to0&&foralmostevery\theta\in[0,2\pi]\\ \|fr-f1\|

Lp(S1)

&\to0 \end{align}

Now, notice that this pointwise limit is a radial limit. That is, the limit being taken is along a straight line from the center of the disk to the boundary of the circle, and the statement above hence says that

f(rei\theta)\to

i\theta
f
1(e

)    foralmostevery\theta.

The natural question is, with this boundary function defined, will we converge pointwise to this function by taking a limit in any other way? That is, suppose instead of following a straight line to the boundary, we follow an arbitrary curve

\gamma:[0,1)\toD

converging to some point

ei\theta

on the boundary. Will

f

converge to

f1(ei\theta)

? (Note that the above theorem is just the special case of

\gamma(t)=tei\theta

). It turns out that the curve

\gamma

needs to be non-tangential, meaning that the curve does not approach its target on the boundary in a way that makes it tangent to the boundary of the circle. In other words, the range of

\gamma

must be contained in a wedge emanating from the limit point. We summarize as follows:

Definition. Let

\gamma:[0,1)\toD

be a continuous path such that

\lim\nolimitst\to\gamma(t)=ei\theta\inS1

. Define

\begin{align} \Gamma\alpha&=\{z:\argz\in[\pi-\alpha,\pi+\alpha]\}\\ \Gamma\alpha(\theta)&=D\capei\theta(\Gamma\alpha+1) \end{align}

That is,

\Gamma\alpha(\theta)

is the wedge inside the disk with angle

2\alpha

whose axis passes between

ei\theta

and zero. We say that

\gamma

converges non-tangentially to

ei\theta

, or that it is a non-tangential limit, if there exists

0<\alpha<\tfrac{\pi}{2}

such that

\gamma

is contained in

\Gamma\alpha(\theta)

and

\lim\nolimitst\to\gamma(t)=ei\theta

.

Fatou's Theorem. Let

f\inHp(D).

Then for almost all

\theta\in[0,2\pi],

\limt\to

i\theta
f(\gamma(t))=f
1(e

)

for every non-tangential limit

\gamma

converging to

ei\theta,

where

f1

is defined as above.

Discussion

See also

References