In microeconomics, the expenditure function gives the minimum amount of money an individual needs to spend to achieve some level of utility, given a utility function and the prices of the available goods.
Formally, if there is a utility function
u
e(p,u*):
n | |
bfR | |
+ |
x bfR → bfR
says what amount of money is needed to achieve a utility
u*
p
e(p,u*)=
min | |
x\in\geq(u*) |
p ⋅ x
where
\geq(u*)=\{x\in
n | |
bfR | |
+ |
:u(x)\gequ*\}
is the set of all bundles that give utility at least as good as
u*
Expressed equivalently, the individual minimizes expenditure
x1p1+...+xnpn
u(x1,...,xn)\geu*,
*, | |
x | |
1 |
...
* | |
x | |
n |
u*
e(p1,...,pn;
*)=p | |
u | |
1 |
*+... | |
x | |
1 |
+pn
*. | |
x | |
n |
(Properties of the Expenditure Function) Suppose u is a continuous utility function representing a locally non-satiated preference relation º on Rn +. Then e(p, u) is
1. Homogeneous of degree one in p: for all and
λ>0
e(λp,u)=λe(p,u);
2. Continuous in
p
u;
3. Nondecreasing in
p
u
p\gg0;
4. Concave in
p
5. If the utility function is strictly quasi-concave, there is the Shephard's lemmaProof
(1) As in the above proposition, note that
e(λ
p,u)=min | ||||||||||
|
λp ⋅ x=λ
min | ||||||||||
|
p ⋅ x=λe(p,u)
(2) Continue on the domain
e
N*bfR → | |
bfR | |
++ |
bfR
(3) Let
p\prime>p
x\inh(p\prime,u)
u(h)\gequ
e(p\prime,u)=p\prime ⋅ x\geqp ⋅ x
e(p,u)\leqe(p\prime,u)
For the second statement, suppose to the contrary that for some
u\prime>u
e(p,u\prime)\leqe(p,u)
x\inh(p,u)
u(x)=u\prime>u
(4)Let
t\in(0,1)
x\inh(tp+(1-t)p\prime)
p ⋅ x\geqe(p,u)
p\prime ⋅ x\geqe(p\prime,u)
e(tp+(1-t)p\prime,u)=(tp+(1-t)p\prime) ⋅ x\geq
te(p,u)+(1-t)e(p\prime,u)
(5)
\delta(p0,u0) | |
\deltapi |
0,u | |
=x | |
i(p |
0)
The expenditure function is the inverse of the indirect utility function when the prices are kept constant. I.e, for every price vector
p
I
e(p,v(p,I))\equivI
(1) is a non-negative function, i.e.,
E(P ⋅ u)>O;
(2) For P, it is non-decreasing, i.e.,
E(p1u)>E(p2u),u>Opl>p2>ON
(3)E(Pu) is a concave function. That is,
e(npl+(1-n)p2)u)>λE(p1u)(1-n)E(p2u)y>0
O<λ<1pl\geq
2 | |
O | |
Np |
\geqON
Expenditure function is an important theoretical method to study consumer behavior. Expenditure function is very similar to cost function in production theory. Dual to the utility maximization problem is the cost minimization problem [1] [2]
u(x1,x2)=
.6 | |
x | |
1 |
.4 | |
x | |
2 |
,
x1(p1,p2,I)=
.6I | |
p1 |
{\rmand} x2(p1,p2,I)=
.4I | |
p2 |
,
I
v(p1,p2,I)
v(p1,p2,I)=
*, | |
u(x | |
1 |
*) | |
x | |
2 |
=
*) | |
(x | |
1 |
.6
*) | |
(x | |
2 |
.4=\left(
.6I | |
p1 |
\right).6\left(
.4I | |
p2 |
\right).4=(.6.6 x .4.4)I.6+.4
-.6 | |
p | |
1 |
-.4 | |
p | |
2 |
=K
-.6 | |
p | |
1 |
-.4 | |
p | |
2 |
I,
where
K=(.6.6 x .4.4).
e(p1,p2,u)=e(p1,p2,v(p1,p2,I))=I
e(p1,p2,u)=(1/K)
.6 | |
p | |
1 |
.4 | |
p | |
2 |
u,
Alternatively, the expenditure function can be found by solving the problem of minimizing
(p1x1+p2x2)
u(x1,x2)\gequ*.
*(p | |
x | |
1, |
p2,u*)
*(p | |
x | |
1, |
p2,u*)
e(p1,p2,u*)=p1x
*+ | |
1 |
p2x
* | |
2 |