Erdős–Szemerédi theorem explained

A

of integers, at least one of

A+A

, the set of pairwise sums or

AA

, the set of pairwise products form a significantly larger set. More precisely, the Erdős–Szemerédi theorem states that there exist positive constants c and

\varepsilon

such that for any non-empty set

A\subsetN

max(|A+A|,|AA|)\geqc|A|1+\varepsilon

.It was proved by Paul Erdős and Endre Szemerédi in 1983.[1] The notation

|A|

denotes the cardinality of the set

A

.

The set of pairwise sums is

A+A=\{a+b:a,b\inA\}

and is called sum set of

A

.

The set of pairwise products is

AA=\{ab:a,b\inA\}

and is called the product set of

A

.

The theorem is a version of the maxim that additive structure and multiplicative structure cannot coexist. It can also be viewed as an assertion that the real line does not contain any set resembling a finite subring or finite subfield; it is the first example of what is now known as the sum-product phenomenon, which is now known to hold in a wide variety of rings and fields, including finite fields.[2]

Sum-Product Conjecture

The sum-product conjecture informally says that one of the sum set or the product set of any set must be nearly as large as possible. It was originally conjectured by Erdős and Szemerédi over the integers, but is thought to hold over the real numbers.

Conjecture: For any set

A\subsetR

one has

max(|A+A|,|AA|)\geq|A|2-o(1).

The asymptotic parameter in the o(1) notation is |A|.

Examples

If

A=\{1,2,3,...,n\}

then

|A+A|=2|A|-1=O(|A|)

using asymptotic notation, with

|A|

the asymptotic parameter. Informally, this says that the sum set of

A

does not grow. On the other hand, the product set of

A

satisfies a bound of the form

|AA|\geq|A|2-\epsilon

for all

\epsilon>0

. This is related to the Erdős multiplication table problem.[3] The best lower bound on

|AA|

for this set is due to Kevin Ford.

This example is an instance of the Few Sums, Many Products[4] version of the sum-product problem of György Elekes and Imre Z. Ruzsa. A consequence of their result is that any set with small additive doubling, for example an arithmetic progression has the lower bound on the product set

|AA|=\Omega(|A|2log-1(|A|))

. Xu and Zhou [5] proved that

|AA|=\Omega(|A|2log1-2log2(|A|))

for any dense subset

A

of an arithmetic progression in integers, which is sharp up to the

o(1)

factor in the exponent.

Conversely, the set

B=\{2,4,8,...,2n\}

satisfies

|BB|=2|B|-1

, but has many sums:

|B+B|=\binom{|B|+1}{2}

. This bound comes from considering the binary representation of a number. The set

B

is an example of a geometric progression.

For a random set of

n

numbers, both the product set and the sum set have cardinality

\binom{n+1}{2}

; that is, with high probability the sum set generates no repeated elements, and the same for the product set.

Sharpness of the conjecture

Erdős and Szemerédi give an example of a sufficiently smooth set of integers

A

with the bound:

max\{|A+A|,|AA|\}\leq|A|2

-clog|A|
loglog|A|
e
.

This shows that the o(1) term in the conjecture is necessary.

Extremal cases

Often studied are the extreme cases of the hypothesis:

|A+A|\ll|A|

, then

|AA|\ge|A|2-o(1)

|AA|\ll|A|

, then

|A+A|\ge|A|2-o(1)

.[6]

History and current results

The following table summarises progress on the sum-product problem over the reals. The exponents 1/4 of György Elekes and 1/3 of József Solymosi are considered milestone results within the citing literature. All improvements after 2009 are of the form

13
+

c

, and represent refinements of the arguments of Konyagin and Shkredov.[7]
A+A
, AA) \geq A^ for

A\subsetR

YearExponentAuthor(s)Comments
1983non-explicit

\delta>0

Erdős and Szemerédi Only for

A\subseteqZ

and of the form

1+\delta

instead of

1+\delta-o(1)

.
1997
1
31

Nathanson[8] Only for

A\subseteqZ

and of the form

1+\delta

instead of

1+\delta-o(1)

.
1998
1{15}
Ford [9] Only for

A\subseteqZ

and of the form

1+\delta

instead of

1+\delta-o(1)

1997
14
Elekes [10] Of the form

1+\delta-o(1)

. Valid also over

C.

2005
3{11}
Solymosi[11] Valid also over

C

2009
13
Solymosi [12]
2015
13
+
1{20598}
=

0.333381...

Konyagin and Shkredov
2016
13
+
5{9813}
=

0.333842...

Konyagin and Shkredov [13]
2016
13
+
1
1509

=0.333996...

Rudnev, Shkredov and Stevens [14]
2019
13
+
5{5277}
=

0.334280...

Shakan [15]
2020
13
+
2{1167}
=

0.335047...

Rudnev and Stevens [16] Current record

Complex numbers

Proof techniques involving only the Szemerédi–Trotter theorem extend automatically to the complex numbers, since the Szemerédi-Trotter theorem holds over

C2

by a theorem of Tóth.[17] Konyagin and Rudnev[18] matched the exponent of 4/3 over the complex numbers. The results with exponents of the form
43
+

c

have not been matched over the complex numbers.

Over finite fields

The sum-product problem is particularly well-studied over finite fields. Motivated by the finite field Kakeya conjecture, Wolff conjectured that for every subset

A\subseteqFp

, where

p

is a (large) prime, that

max\{|A+A|,|AA|\}\geqmin\{p,|A|1+\epsilon\}

for an absolute constant

\epsilon>0

. This conjecture had also been formulated in the 1990s by Wigderson[19] motivated by randomness extractors.

Note that the sum-product problem cannot hold in finite fields unconditionally due to the following example:

Example: Let

F

be a finite field and take

A=F

. Then since

F

is closed under addition and multiplication,

A+A=AA=F

and so

|A+A|=|AA|=|F|

. This pathological example extends to taking

A

to be any sub-field of the field in question.

Qualitatively, the sum-product problem has been solved over finite fields:

Theorem (Bourgain, Katz, Tao (2004) [20]): Let

p

be prime and let

A\subsetFp

with

p\delta<|A|<p1-\delta

for some

0<\delta<1

. Then one has

max(|A+A|,|AA|)\geq

1+\epsilon
c
\delta|A|
for some

\epsilon=\epsilon(\delta)>0

.

Bourgain, Katz and Tao extended this theorem to arbitrary fields. Informally, the following theorem says that if a sufficiently large set does not grow under either addition or multiplication, then it is mostly contained in a dilate of a sub-field.

Theorem (Bourgain, Katz, Tao (2004)): Let

A

be a subset of a finite field

F

so that

|A|>|F|\delta

for some

0<\delta<1

and suppose that

|A+A|,|AA|\leqK|A|

. Then there exists a sub-field

G\subsetF

with

|G|\leq

C\delta
K

|A|

,

x\inF\setminus\{0\}

and a set

X\subsetF

with

|X|\leq

C\delta
K
so that

A\subseteqxG\cupX

.

They suggest that the constant

C\delta

may be independent of

\delta

.

Quantitative results towards the finite field sum-product problem in

F

typically fall into two categories: when

A\subsetF

is small with respect to the characteristic of

F

and when

A\subsetF

is large with respect to the characteristic of

F

. This is because different types of techniques are used in each setting.

Small sets

In this regime, let

F

be a field of characteristic

p

. Note that the field is not always finite. When this is the case, and the characteristic of

F

is zero, then the

p

-constraint is omitted.
A+A
, AA) \geq A^ for

A\subsetF

YearExponent

p

-constraint :
A< p^cAuthor(s)Comments
2004unquantified

c<1

Bourgain, Katz, Tao For finite

F

only.
2007
1{14}

c=7/13

Garaev[21] For finite

F

only. The p-constraint involves a factor of

log(

A)
2008
1{13}

c=1/2

Katz, ShenFor finite

F

only.
2009
1{12}

c=12/23

Bourgain, Garaev[22] For finite

F

only. o(1) removed by Li.[23]
2012
1{11}

c=1/2

Rudnev[24] For finite

F

only.
2016
15

c=5/8

Roche-Newton, Rudnev, Shkredov[25]
2016
19

c=18/35

Rudnev, Shkredov, ShakanThis result is the best of three contemporaneous results.
2021
14

c=1/2

Mohammadi, Stevens [26] Current record. Extends to difference sets and ratio sets.

In fields with non-prime order, the

p

-constraint on

A\subsetF

can be replaced with the assumption that

A

does not have too large an intersection with any subfield. The best work in this direction is due to Li and Roche-Newton[27] attaining an exponent of

\delta=

1{19}
in the notation of the above table.

Large sets

When

F=Fp

for

p

prime, the sum-product problem is considered resolved due to the following result of Garaev:[28]

Theorem (Garaev (2007)): Let

A\subsetFp

. Then

max\{|A+A|,|AA|\}\ggmin\{p1/2|A|1/2,|A|2p-1/2\}

.

This is optimal in the range

|A|\geqp2/3

.

This result was extended to finite fields of non-prime order by Vinh[29] in 2011.

Variants and generalisations

Other combinations of operators

Bourgain and Chang proved unconditional growth for sets

A\subseteqZ

, as long as one considers enough sums or products:

Theorem (Bourgain, Chang (2003) [30] ): Let

b\inN

. Then there exists

k\inN

so that for all

A\subseteqZ

, one has

max\{|kA|,|A(k)|\}=max\{|A+A+...A|,|AA...A|\}\geq|A|b

.

In many works, addition and multiplication are combined in one expression. With the motto addition and multiplication cannot coexist, one expects that any non-trivial combination of addition and multiplication of a set should guarantee growth. Note that in finite settings, or in fields with non-trivial subfields, such a statement requires further constraints.

Sets of interest include (results for

A\subsetR

):

AA+A

- Stevens and Warren[31] show that

|AA+A|\gg

32
3
170
-o(1)
+
|A|

A(A+A)

- Murphy, Roche-Newton and Shkredov[32] show that

|A(A+A)|\gg

32
5{242
+
|A|

-o(1)}

A(A+1)

- Stevens and Warren show that

|A(A+1)|\gg

49-o(1)
38
|A|

AA+AA

- Stevens and Rudnev show that

|AA+AA|\gg

127-o(1)
80
|A|

See also

External links

Notes and References

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  5. 2201.00104. math.NT. Max Wenqiang. Xu. Yunkun. Zhou. On product sets of arithmetic progressions. 2022.
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