Elongated triangular cupola explained

Type:Johnson
Faces:4 triangles
9 squares
1 hexagon
Edges:27
Vertices:15
Dual:-
Properties:convex
Net:Johnson solid 18 net.png

In geometry, the elongated triangular cupola is a polyhedron constructed from a hexagonal prism by attaching a triangular cupola. It is an example of a Johnson solid.

Construction

The elongated triangular cupola is constructed from a hexagonal prism by attaching a triangular cupola onto one of its bases, a process known as the elongation. This cupola covers the hexagonal face so that the resulting polyhedron has four equilateral triangles, nine squares, and one regular hexagon. A convex polyhedron in which all of the faces are regular polygons is the Johnson solid. The elongated triangular cupola is one of them, enumerated as the eighteenth Johnson solid

J18

.

Properties

The surface area of an elongated triangular cupola

A

is the sum of all polygonal face's area. The volume of an elongated triangular cupola can be ascertained by dissecting it into a cupola and a hexagonal prism, after which summing their volume. Given the edge length

a

, its surface and volume can be formulated as:\begin A &= \fraca^2 &\approx 13.330a^2, \\ V &= \fraca^3 &\approx 3.777a^3.\end

C3v

of order 6. Its dihedral angle can be calculated by adding the angle of a triangular cupola and a hexagonal prism:

Dual polyhedron

The dual of the elongated triangular cupola has 15 faces: 6 isosceles triangles, 3 rhombi, and 6 quadrilaterals.

Related polyhedra and honeycombs

The elongated triangular cupola can form a tessellation of space with tetrahedra and square pyramids.[1]

Notes and References

  1. Web site: J18 honeycomb.