The Ekman spiral is an arrangement of ocean currents: the directions of horizontal current appear to twist as the depth changes.[1] The oceanic wind driven Ekman spiral is the result of a force balance created by a shear stress force, Coriolis force and the water drag. This force balance gives a resulting current of the water different from the winds. In the ocean, there are two places where the Ekman spiral can be observed. At the surface of the ocean, the shear stress force corresponds with the wind stress force. At the bottom of the ocean, the shear stress force is created by friction with the ocean floor. This phenomenon was first observed at the surface by the Norwegian oceanographer Fridtjof Nansen during his Fram expedition. He noticed that icebergs did not drift in the same direction as the wind. His student, the Swedish oceanographer Vagn Walfrid Ekman, was the first person to physically explain this process.[2]
In order to derive the properties of an Ekman spiral a look is taken at a uniform, horizontal geostrophic interior flow in a homogeneous fluid. This flow will be denoted by
\vec{u}=(\bar{u},\bar{v})
\partialw | |
\partialz |
=0
w=0
\begin{align} -fv&=-
1 | |
\rho0 |
\partialp | |
\partialx |
+\nuE
\partial2u | |
\partialz2 |
,\\[5pt] fu&=-
1 | |
\rho0 |
\partialp | |
\partialy |
+\nuE
\partial2v | |
\partialz2 |
,\\[5pt] 0&=-
1 | |
\rho0 |
\partialp | |
\partialz |
, \end{align}
Where
f
\rho0
\nuE
u=\bar{u}
v=\bar{v}
\begin{align} -f\bar{v}&=-
1 | |
\rho0 |
\partialp | |
\partialx |
=constant\\[5pt] f\bar{u}&=-
1 | |
\rho0 |
\partialp | |
\partialy |
=constant \end{align}
Using the last of the three equations at the top of this section, yields that the pressure is independent of depth.
\begin{align} -f(v-\bar{v})&=\nuE
\partial2u | |
\partialz2 |
\\[5pt] f(u-\bar{u})&=\nuE
\partial2v | |
\partialz2 |
\end{align}
u=\bar{u}+Aeλ
v=\bar{v}+Beλ
2λ | |
\nu | |
E |
4+f2=0
λ
λ=\pm(1\pmi)\sqrt{
f | |
2\nuE |
Because of the no-slip condition at the bottom and the constant interior flow for
z\ggd
A
B
\vec{u}(z)
\begin{align} u&=\bar{u}\left[1-e-z/d\cos\left(
z | |
d |
\right)\right]-\bar{v}e-z/d\sin\left(
z | |
d |
\right),\\[5pt] v&=\bar{u}e-z/d\sin\left(
z | |
d |
\right)+\bar{v}\left[1-e-z/d\cos\left(
z | |
d |
\right)\right], \end{align}
Here,
d=\sqrt{ | 2\nuE |
f |
z
d
d
z → {0}
f>0
f<0
z
z | |
d |
\pi
e-\pi
z | |
d |
z\ggd
\vec{u}=(\bar{u},\bar{v})
\vec{\tau}=(\taux,\tauy)
\vec{u}=(u,v)
\begin{align} -f(v-\bar{v})&=\nuE
\partial2u | |
\partialz2 |
\\[5pt] f(u-\bar{u})&=\nuE
\partial2v | |
\partialz2 |
\\ \end{align}
The boundary conditions for this case are as follows:
(z=0)
\rho0\nu
|
=\taux
\rho0\nu
|
=\tauy
(z → {-infty})
u=\bar{u}
v=\bar{v}
With these conditions, the solution can be determined:
\begin{align} u&=\bar{u}+
\sqrt{2 | |
Some differences with respect to the bottom Ekman spiral emerge. The deviation from the interior flow is exclusively dependent on the wind stress and not on the interior flow. Whereas in the case of the bottom Ekman spiral, the deviation is determined by the interior flow. The wind-driven component of the flow is inversely proportional with respect to the Ekman-layer thickness
d
The equations and assumptions above are not representative for the actual observations of the Ekman spiral. The differences between the theory and the observations are that the angle is between 5–20 degrees instead of the 45 degrees as expected[4] and that the Ekman layer depth and thus the Ekman spiral is less deep than expected. There are three main factors which contribute to the reason why this is, stratification,[5] turbulence and horizontal gradients. Other less important factors which play a role in this are the Stokes drift,[6] waves and the Stokes-Coriolis force.[7]