Dual system explained

K

is a triple

(X,Y,b)

consisting of two vector spaces,

X

and

Y

, over

K

and a non-degenerate bilinear map

b:X x Y\toK

.

Mathematical duality is the study of dual systems and is important in functional analysis. It plays crucial roles in quantum mechanics because it has extensive applications to the theory of Hilbert spaces, which are used to represent the states of physical systems in quantum mechanics.

Definition, notation, and conventions

Pairings

A or pair over a field

K

is a triple

(X,Y,b),

which may also be denoted by

b(X,Y),

consisting of two vector spaces

X

and

Y

over

K

and a bilinear map

b:X x Y\toK

called the bilinear map associated with the pairing, or more simply called the pairing's map or its bilinear form. The examples here only describe when

K

is either the real numbers or the complex numbers

\Complex

, but the mathematical theory is general.

For every

x\inX

, define\beginb(x, \,\cdot\,) : \,& Y && \to &&\, \mathbb \\ & y && \mapsto &&\, b(x, y)\endand for every

y\inY,

define\beginb(\,\cdot\,, y) : \,& X && \to &&\, \mathbb \\ & x && \mapsto &&\, b(x, y).\endEvery

b(x,)

is a linear functional on

Y

and every

b(,y)

is a linear functional on

X

. Therefore bothb(X, \,\cdot\,) := \ \qquad \text \qquad b(\,\cdot\,, Y) := \,form vector spaces of linear functionals.

It is common practice to write

\langlex,y\rangle

instead of

b(x,y)

, in which in some cases the pairing may be denoted by

\left\langleX,Y\right\rangle

rather than

(X,Y,\langle,\rangle)

. However, this article will reserve the use of

\langle,\rangle

for the canonical evaluation map (defined below) so as to avoid confusion for readers not familiar with this subject.

Dual pairings

A pairing

(X,Y,b)

is called a, a, or a over

K

if the bilinear form

b

is non-degenerate, which means that it satisfies the following two separation axioms:

Y

separates (distinguishes) points of

X

: if

x\inX

is such that

b(x,)=0

then

x=0

; or equivalently, for all non-zero

x\inX

, the map

b(x,):Y\toK

is not identically

0

(i.e. there exists a

y\inY

such that

b(x,y)0

for each

x\inX

);

X

separates (distinguishes) points of

Y

: if

y\inY

is such that

b(,y)=0

then

y=0

; or equivalently, for all non-zero

y\inY,

the map

b(,y):X\toK

is not identically

0

(i.e. there exists an

x\inX

such that

b(x,y)0

for each

y\inY

).In this case

b

is non-degenerate, and one can say that

b

places

X

and

Y

in duality
(or, redundantly but explicitly, in separated duality), and

b

is called the duality pairing of the triple

(X,Y,b)

.

Total subsets

A subset

S

of

Y

is called if for every

x\inX

, b(x, s) = 0 \quad \text s \in S implies

x=0.

A total subset of

X

is defined analogously (see footnote).[1] Thus

X

separates points of

Y

if and only if

X

is a total subset of

X

, and similarly for

Y

.

Orthogonality

The vectors

x

and

y

are orthogonal, written

x\perpy

, if

b(x,y)=0

. Two subsets

R\subseteqX

and

S\subseteqY

are orthogonal, written

R\perpS

, if

b(R,S)=\{0\}

; that is, if

b(r,s)=0

for all

r\inR

and

s\inS

. The definition of a subset being orthogonal to a vector is defined analogously.

The orthogonal complement or annihilator of a subset

R\subseteqX

isR^ := \ := \Thus

R

is a total subset of

X

if and only if

R\perp

equals

\{0\}

.

Polar sets

See main article: Polar set.

Given a triple

(X,Y,b)

defining a pairing over

K

, the absolute polar set or polar set of a subset

A

of

X

is the set:A^ := \left\.Symmetrically, the absolute polar set or polar set of a subset

B

of

Y

is denoted by

B\circ

and defined byB^ := \left\.

To use bookkeeping that helps keep track of the anti-symmetry of the two sides of the duality, the absolute polar of a subset

B

of

Y

may also be called the absolute prepolar or prepolar of

B

and then may be denoted by

B\circ.

The polar

B\circ

is necessarily a convex set containing

0\inY

where if

B

is balanced then so is

B\circ

and if

B

is a vector subspace of

X

then so too is

B\circ

a vector subspace of

Y.

If

A

is a vector subspace of

X,

then

A\circ=A\perp

and this is also equal to the real polar of

A.

If

A\subseteqX

then the bipolar of

A

, denoted

A\circ\circ

, is the polar of the orthogonal complement of

A

, i.e., the set

{}\circ\left(A\perp\right).

Similarly, if

B\subseteqY

then the bipolar of

B

is

B\circ\circ:=\left({}\circB\right)\circ.

Dual definitions and results

Given a pairing

(X,Y,b),

define a new pairing

(Y,X,d)

where

d(y,x):=b(x,y)

for all

x\inX

and

y\inY

.

There is a consistent theme in duality theory that any definition for a pairing

(X,Y,b)

has a corresponding dual definition for the pairing

(Y,X,d).

Given any definition for a pairing

(X,Y,b),

one obtains a by applying it to the pairing

(Y,X,d).

These conventions also apply to theorems.

For instance, if "

X

distinguishes points of

Y

" (resp, "

S

is a total subset of

Y

") is defined as above, then this convention immediately produces the dual definition of "

Y

distinguishes points of

X

" (resp, "

S

is a total subset of

X

").

This following notation is almost ubiquitous and allows us to avoid assigning a symbol to

d.

If a definition and its notation for a pairing

(X,Y,b)

depends on the order of

X

and

Y

(for example, the definition of the Mackey topology

\tau(X,Y,b)

on

X

) then by switching the order of

X

and

Y,

then it is meant that definition applied to

(Y,X,d)

(continuing the same example, the topology

\tau(Y,X,b)

would actually denote the topology

\tau(Y,X,d)

).

For another example, once the weak topology on

X

is defined, denoted by

\sigma(X,Y,b)

, then this dual definition would automatically be applied to the pairing

(Y,X,d)

so as to obtain the definition of the weak topology on

Y

, and this topology would be denoted by

\sigma(Y,X,b)

rather than

\sigma(Y,X,d)

.

Identification of

(X,Y)

with

(Y,X)

Although it is technically incorrect and an abuse of notation, this article will adhere to the nearly ubiquitous convention of treating a pairing

(X,Y,b)

interchangeably with

(Y,X,d)

and also of denoting

(Y,X,d)

by

(Y,X,b).

Examples

Restriction of a pairing

Suppose that

(X,Y,b)

is a pairing,

M

is a vector subspace of

X,

and

N

is a vector subspace of

Y

. Then the restriction of

(X,Y,b)

to

M x N

is the pairing

\left(M,N,b\vertM\right).

If

(X,Y,b)

is a duality, then it's possible for a restriction to fail to be a duality (e.g. if

Y\{0\}

and

N=\{0\}

).

This article will use the common practice of denoting the restriction

\left(M,N,b\vertM\right)

by

(M,N,b).

Canonical duality on a vector space

Suppose that

X

is a vector space and let

X\#

denote the algebraic dual space of

X

(that is, the space of all linear functionals on

X

). There is a canonical duality

\left(X,X\#,c\right)

where

c\left(x,x\prime\right)=\left\langlex,x\prime\right\rangle=x\prime(x),

which is called the evaluation map or the natural or canonical bilinear functional on

X x X\#.

Note in particular that for any

x\prime\inX\#,

c\left(,x\prime\right)

is just another way of denoting

x\prime

; i.e.

c\left(,x\prime\right)=x\prime()=x\prime.

If

N

is a vector subspace of

X\#

, then the restriction of

\left(X,X\#,c\right)

to

X x N

is called the canonical pairing where if this pairing is a duality then it is instead called the canonical duality. Clearly,

X

always distinguishes points of

N

, so the canonical pairing is a dual system if and only if

N

separates points of

X.

The following notation is now nearly ubiquitous in duality theory.

The evaluation map will be denoted by

\left\langlex,x\prime\right\rangle=x\prime(x)

(rather than by

c

) and

\langleX,N\rangle

will be written rather than

(X,N,c).

Assumption: As is common practice, if

X

is a vector space and

N

is a vector space of linear functionals on

X,

then unless stated otherwise, it will be assumed that they are associated with the canonical pairing

\langleX,N\rangle.

If

N

is a vector subspace of

X\#

then

X

distinguishes points of

N

(or equivalently,

(X,N,c)

is a duality) if and only if

N

distinguishes points of

X,

or equivalently if

N

is total (that is,

n(x)=0

for all

n\inN

implies

x=0

).

Canonical duality on a topological vector space

Suppose

X

is a topological vector space (TVS) with continuous dual space

X\prime.

Then the restriction of the canonical duality

\left(X,X\#,c\right)

to

X

×

X\prime

defines a pairing

\left(X,X\prime,

c\vert
X x X\prime

\right)

for which

X

separates points of

X\prime.

If

X\prime

separates points of

X

(which is true if, for instance,

X

is a Hausdorff locally convex space) then this pairing forms a duality.

Assumption: As is commonly done, whenever

X

is a TVS, then unless indicated otherwise, it will be assumed without comment that it's associated with the canonical pairing

\left\langleX,X\prime\right\rangle.

Polars and duals of TVSs

The following result shows that the continuous linear functionals on a TVS are exactly those linear functionals that are bounded on a neighborhood of the origin.

Inner product spaces and complex conjugate spaces

(H,\langle,\rangle)

is a dual pairing if and only if

H

is vector space over

\R

or

H

has dimension

0.

Here it is assumed that the sesquilinear form

\langle,\rangle

is conjugate homogeneous in its second coordinate and homogeneous in its first coordinate.

Suppose that

(H,\langle,\rangle)

is a complex pre-Hilbert space with scalar multiplication denoted as usual by juxtaposition or by a dot

.

Define the map\,\cdot\, \perp \,\cdot\, : \Complex \times H \to H \quad \text \quad c \perp x := \overline x,where the right-hand side uses the scalar multiplication of

H.

Let

\overline{H}

denote the complex conjugate vector space of

H,

where

\overline{H}

denotes the additive group of

(H,+)

(so vector addition in

\overline{H}

is identical to vector addition in

H

) but with scalar multiplication in

\overline{H}

being the map

\perp

(instead of the scalar multiplication that

H

is endowed with).

The map

b:H x \overline{H}\to\Complex

defined by

b(x,y):=\langlex,y\rangle

is linear in both coordinates[2] and so

\left(H,\overline{H},\langle,\rangle\right)

forms a dual pairing.

Other examples

Weak topology

See main article: Weak topology.

Suppose that

(X,Y,b)

is a pairing of vector spaces over

K.

If

S\subseteqY

then the weak topology on

X

induced by

S

(and

b

) is the weakest TVS topology on

X,

denoted by

\sigma(X,S,b)

or simply

\sigma(X,S),

making all maps

b(,y):X\toK

continuous as

y

ranges over

S.

If

S

is not clear from context then it should be assumed to be all of

Y,

in which case it is called the weak topology on

X

(induced by

Y

). The notation

X\sigma(X,,

X\sigma(X,,

or (if no confusion could arise) simply

X\sigma

is used to denote

X

endowed with the weak topology

\sigma(X,S,b).

Importantly, the weak topology depends on the function

b,

the usual topology on

\Complex,

and

X

's vector space structure but on the algebraic structures of

Y.

Similarly, if

R\subseteqX

then the dual definition of the weak topology on

Y

induced by

R

(and

b

), which is denoted by

\sigma(Y,R,b)

or simply

\sigma(Y,R)

(see footnote for details).[3]

If "

\sigma(X,Y,b)

" is attached to a topological definition (e.g.

\sigma(X,Y,b)

-converges,

\sigma(X,Y,b)

-bounded,

\operatorname{cl}\sigma(X,(S),

etc.) then it means that definition when the first space (i.e.

X

) carries the

\sigma(X,Y,b)

topology. Mention of

b

or even

X

and

Y

may be omitted if no confusion arises. So, for instance, if a sequence

\left(ai\right)

infty
i=1
in

Y

"

\sigma

-converges" or "weakly converges" then this means that it converges in

(Y,\sigma(Y,X,b))

whereas if it were a sequence in

X

, then this would mean that it converges in

(X,\sigma(X,Y,b))

).

The topology

\sigma(X,Y,b)

is locally convex since it is determined by the family of seminorms

py:X\to\R

defined by

py(x):=|b(x,y)|,

as

y

ranges over

Y.

If

x\inX

and

\left(xi\right)i

is a net in

X,

then

\left(xi\right)i

\sigma(X,Y,b)

-converges
to

x

if

\left(xi\right)i

converges to

x

in

(X,\sigma(X,Y,b)).

A net

\left(xi\right)i

\sigma(X,Y,b)

-converges to

x

if and only if for all

y\inY,

b\left(xi,y\right)

converges to

b(x,y).

If

\left(xi\right)

infty
i=1
is a sequence of orthonormal vectors in Hilbert space, then

\left(xi\right)

infty
i=1
converges weakly to 0 but does not norm-converge to 0 (or any other vector).

If

(X,Y,b)

is a pairing and

N

is a proper vector subspace of

Y

such that

(X,N,b)

is a dual pair, then

\sigma(X,N,b)

is strictly coarser than

\sigma(X,Y,b).

Bounded subsets

A subset

S

of

X

is

\sigma(X,Y,b)

-bounded if and only if \sup_ |b(S, y)| < \infty \quad \text y \in Y, where

|b(S,y)|:=\{b(s,y):s\inS\}.

Hausdorffness

If

(X,Y,b)

is a pairing then the following are equivalent:

X

distinguishes points of

Y

;
  1. The map

y\mapstob(,y)

defines an injection from

Y

into the algebraic dual space of

X

;

\sigma(Y,X,b)

is Hausdorff.

Weak representation theorem

The following theorem is of fundamental importance to duality theory because it completely characterizes the continuous dual space of

(X,\sigma(X,Y,b)).

Consequently, the continuous dual space of

(X,\sigma(X,Y,b))

is (X, \sigma(X, Y, b))^ = b(\,\cdot\,, Y) := \left\.

With respect to the canonical pairing, if

X

is a TVS whose continuous dual space

X\prime

separates points on

X

(i.e. such that

\left(X,\sigma\left(X,X\prime\right)\right)

is Hausdorff, which implies that

X

is also necessarily Hausdorff) then the continuous dual space of

\left(X\prime,\sigma\left(X\prime,X\right)\right)

is equal to the set of all "evaluation at a point

x

" maps as

x

ranges over

X

(i.e. the map that send

x\prime\inX\prime

to

x\prime(x)

). This is commonly written as\left(X^, \sigma\left(X^, X\right)\right)^ = X \qquad \text \qquad \left(X^_\right)^ = X.This very important fact is why results for polar topologies on continuous dual spaces, such as the strong dual topology

\beta\left(X\prime,X\right)

on

X\prime

for example, can also often be applied to the original TVS

X

; for instance,

X

being identified with
\prime
\left(X
\sigma

\right)\prime

means that the topology
\prime
\beta\left(\left(X
\sigma

\right)\prime,

\prime
X
\sigma

\right)

on
\prime
\left(X
\sigma

\right)\prime

can instead be thought of as a topology on

X.

Moreover, if

X\prime

is endowed with a topology that is finer than

\sigma\left(X\prime,X\right)

then the continuous dual space of

X\prime

will necessarily contain
\prime
\left(X
\sigma

\right)\prime

as a subset. So for instance, when

X\prime

is endowed with the strong dual topology (and so is denoted by
\prime
X
\beta
) then\left(X^_\right)^ ~\supseteq~ \left(X^_\right)^ ~=~ Xwhich (among other things) allows for

X

to be endowed with the subspace topology induced on it by, say, the strong dual topology
\prime
\beta\left(\left(X
\beta

\right)\prime,

\prime
X
\beta

\right)

(this topology is also called the strong bidual topology and it appears in the theory of reflexive spaces: the Hausdorff locally convex TVS

X

is said to be if
\prime
\left(X
\beta

\right)\prime=X

and it will be called if in addition the strong bidual topology
\prime
\beta\left(\left(X
\beta

\right)\prime,

\prime
X
\beta

\right)

on

X

is equal to

X

's original/starting topology).

Orthogonals, quotients, and subspaces

If

(X,Y,b)

is a pairing then for any subset

S

of

X

:

If

X

is a normed space then under the canonical duality,

S\perp

is norm closed in

X\prime

and

S\perp\perp

is norm closed in

X.

Subspaces

Suppose that

M

is a vector subspace of

X

and let

(M,Y,b)

denote the restriction of

(X,Y,b)

to

M x Y.

The weak topology

\sigma(M,Y,b)

on

M

is identical to the subspace topology that

M

inherits from

(X,\sigma(X,Y,b)).

Also,

\left(M,Y/M\perp,b\vertM\right)

is a paired space (where

Y/M\perp

means

Y/\left(M\perp\right)

) where

b\vertM:M x Y/M\perp\toK

is defined by\left(m, y + M^\right) \mapsto b(m, y).

The topology

\sigma\left(M,Y/M\perp,b\vertM\right)

is equal to the subspace topology that

M

inherits from

(X,\sigma(X,Y,b)).

Furthermore, if

(X,\sigma(X,Y,b))

is a dual system then so is

\left(M,Y/M\perp,b\vertM\right).

Quotients

Suppose that

M

is a vector subspace of

X.

Then

\left(X/M,M\perp,b/M\right)

is a paired space where

b/M:X/M x M\perp\toK

is defined by(x + M, y) \mapsto b(x, y).

The topology

\sigma\left(X/M,M\perp\right)

is identical to the usual quotient topology induced by

(X,\sigma(X,Y,b))

on

X/M.

Polars and the weak topology

If

X

is a locally convex space and if

H

is a subset of the continuous dual space

X\prime,

then

H

is

\sigma\left(X\prime,X\right)

-bounded if and only if

H\subseteqB\circ

for some barrel

B

in

X.

The following results are important for defining polar topologies.

If

(X,Y,b)

is a pairing and

A\subseteqX,

then:
  1. The polar

    A\circ

    of

    A

    is a closed subset of

    (Y,\sigma(Y,X,b)).

  2. The polars of the following sets are identical: (a)

    A

    ; (b) the convex hull of

    A

    ; (c) the balanced hull of

    A

    ; (d) the

    \sigma(X,Y,b)

    -closure of

    A

    ; (e) the

    \sigma(X,Y,b)

    -closure of the convex balanced hull of

    A.

  3. The bipolar theorem: The bipolar of

    A,

    denoted by

    A\circ\circ,

    is equal to the

    \sigma(X,Y,b)

    -closure of the convex balanced hull of

    A.

    • The bipolar theorem in particular "is an indispensable tool in working with dualities."

  4. A

    is

    \sigma(X,Y,b)

    -bounded if and only if

    A\circ

    is absorbing in

    Y.

  5. If in addition

    Y

    distinguishes points of

    X

    then

    A

    is

    \sigma(X,Y,b)

    -bounded if and only if it is

    \sigma(X,Y,b)

    -totally bounded.

If

(X,Y,b)

is a pairing and

\tau

is a locally convex topology on

X

that is consistent with duality, then a subset

B

of

X

is a barrel in

(X,\tau)

if and only if

B

is the polar of some

\sigma(Y,X,b)

-bounded subset of

Y.

Transposes

Transposes of a linear map with respect to pairings

See also: Transpose of a linear map and Transpose.

Let

(X,Y,b)

and

(W,Z,c)

be pairings over

K

and let

F:X\toW

be a linear map.

For all

z\inZ,

let

c(F(),z):X\toK

be the map defined by

x\mapstoc(F(x),z).

It is said that

F

s transpose or adjoint is well-defined if the following conditions are satisfied:

X

distinguishes points of

Y

(or equivalently, the map

y\mapstob(,y)

from

Y

into the algebraic dual

X\#

is injective), and

c(F(),Z)\subseteqb(,Y),

where

c(F(),Z):=\{c(F(),z):z\inZ\}

and

b(,Y):=\{b(,y):y\inY\}

.

In this case, for any

z\inZ

there exists (by condition 2) a unique (by condition 1)

y\inY

such that

c(F(),z)=b(,y)

), where this element of

Y

will be denoted by

{}tF(z).

This defines a linear map ^t F : Z \to Y

called the transpose or adjoint of

F

with respect to

(X,Y,b)

and

(W,Z,c)

(this should not be confused with the Hermitian adjoint). It is easy to see that the two conditions mentioned above (i.e. for "the transpose is well-defined") are also necessary for

{}tF

to be well-defined. For every

z\inZ,

the defining condition for

{}tF(z)

is c(F(\,\cdot\,), z) = b\left(\,\cdot\,, ^t F(z)\right), that is,c(F(x), z) = b\left(x, ^t F(z)\right) for all

x\inX.

By the conventions mentioned at the beginning of this article, this also defines the transpose of linear maps of the form

Z\toY,

[4]

X\toZ,

[5]

W\toY,

[6]

Y\toW,

[7] etc. (see footnote).

Properties of the transpose

Throughout,

(X,Y,b)

and

(W,Z,c)

be pairings over

K

and

F:X\toW

will be a linear map whose transpose

{}tF:Z\toY

is well-defined.

{}tF:Z\toY

is injective (i.e.

\operatorname{ker}{}tF=\{0\}

) if and only if the range of

F

is dense in

\left(W,\sigma\left(W,Z,c\right)\right).

{}tF

being well-defined, the transpose of

{}tF

is also well-defined then

{}ttF=F.

(U,V,a)

is a pairing over

K

and

E:U\toX

is a linear map whose transpose

{}tE:Y\toV

is well-defined. Then the transpose of

F\circE:U\toW,

which is

{}t(F\circE):Z\toV,

is well-defined and

{}t(F\circE)={}tE\circ{}tF.

F:X\toW

is a vector space isomorphism then

{}tF:Z\toY

is bijective, the transpose of

F-1:W\toX,

which is

{}t\left(F-1\right):Y\toZ,

is well-defined, and

{}t\left(F-1\right)=\left({}tF\right)-1

S\subseteqX

and let

S\circ

denotes the absolute polar of

A,

then:

[F(S)]\circ=\left({}tF\right)-1\left(S\circ\right)

;

F(S)\subseteqT

for some

T\subseteqW,

then

{}tF\left(T\circ\right)\subseteqS\circ

;

T\subseteqW

is such that

{}tF\left(T\circ\right)\subseteqS\circ,

then

F(S)\subseteqT\circ\circ

;

T\subseteqW

and

S\subseteqX

are weakly closed disks then

{}tF\left(T\circ\right)\subseteqS\circ

if and only if

F(S)\subseteqT

;

\operatorname{ker}{}tF=[F(X)]\perp.

These results hold when the real polar is used in place of the absolute polar.

If

X

and

Y

are normed spaces under their canonical dualities and if

F:X\toY

is a continuous linear map, then

\|F\|=\left\|{}tF\right\|.

Weak continuity

A linear map

F:X\toW

is weakly continuous (with respect to

(X,Y,b)

and

(W,Z,c)

) if

F:(X,\sigma(X,Y,b))\to(W,(W,Z,c))

is continuous.

The following result shows that the existence of the transpose map is intimately tied to the weak topology.

Weak topology and the canonical duality

Suppose that

X

is a vector space and that

X\#

is its the algebraic dual. Then every

\sigma\left(X,X\#\right)

-bounded subset of

X

is contained in a finite dimensional vector subspace and every vector subspace of

X

is

\sigma\left(X,X\#\right)

-closed.

Weak completeness

If

(X,\sigma(X,Y,b))

is a complete topological vector space say that

X

is

\sigma(X,Y,b)

-complete
or (if no ambiguity can arise) weakly-complete. There exist Banach spaces that are not weakly-complete (despite being complete in their norm topology).

If

X

is a vector space then under the canonical duality,

\left(X\#,\sigma\left(X\#,X\right)\right)

is complete. Conversely, if

Z

is a Hausdorff locally convex TVS with continuous dual space

Z\prime,

then

\left(Z,\sigma\left(Z,Z\prime\right)\right)

is complete if and only if

Z=\left(Z\prime\right)\#

; that is, if and only if the map

Z\to\left(Z\prime\right)\#

defined by sending

z\inZ

to the evaluation map at

z

(i.e.

z\prime\mapstoz\prime(z)

) is a bijection.

In particular, with respect to the canonical duality, if

Y

is a vector subspace of

X\#

such that

Y

separates points of

X,

then

(Y,\sigma(Y,X))

is complete if and only if

Y=X\#.

Said differently, there does exist a proper vector subspace

YX\#

of

X\#

such that

(X,\sigma(X,Y))

is Hausdorff and

Y

is complete in the weak-* topology (i.e. the topology of pointwise convergence). Consequently, when the continuous dual space

X\prime

of a Hausdorff locally convex TVS

X

is endowed with the weak-* topology, then
\prime
X
\sigma
is complete if and only if

X\prime=X\#

(that is, if and only if linear functional on

X

is continuous).

Identification of Y with a subspace of the algebraic dual

If

X

distinguishes points of

Y

and if

Z

denotes the range of the injection

y\mapstob(,y)

then

Z

is a vector subspace of the algebraic dual space of

X

and the pairing

(X,Y,b)

becomes canonically identified with the canonical pairing

\langleX,Z\rangle

(where

\left\langlex,x\prime\right\rangle:=x\prime(x)

is the natural evaluation map). In particular, in this situation it will be assumed without loss of generality that

Y

is a vector subspace of

X

's algebraic dual and

b

is the evaluation map.

Often, whenever

y\mapstob(,y)

is injective (especially when

(X,Y,b)

forms a dual pair) then it is common practice to assume without loss of generality that

Y

is a vector subspace of the algebraic dual space of

X,

that

b

is the natural evaluation map, and also denote

Y

by

X\prime.

In a completely analogous manner, if

Y

distinguishes points of

X

then it is possible for

X

to be identified as a vector subspace of

Y

's algebraic dual space.

Algebraic adjoint

In the special case where the dualities are the canonical dualities

\left\langleX,X\#\right\rangle

and

\left\langleW,W\#\right\rangle,

the transpose of a linear map

F:X\toW

is always well-defined. This transpose is called the algebraic adjoint of

F

and it will be denoted by

F\#

; that is,

F\#={}tF:W\#\toX\#.

In this case, for all

w\prime\inW\#,

F\#\left(w\prime\right)=w\prime\circF

where the defining condition for

F\#\left(w\prime\right)

is:\left\langle x, F^\left(w^\right) \right\rangle = \left\langle F(x), w^ \right\rangle \quad \text >x \in X, or equivalently,

F\#\left(w\prime\right)(x)=w\prime(F(x))forallx\inX.

If

X=Y=Kn

for some integer

n,

l{E}=\left\{e1,\ldots,en\right\}

is a basis for

X

with dual basis

l{E}\prime=\left\{

\prime
e
1

,\ldots,

\prime
e
n

\right\},

F:Kn\toKn

is a linear operator, and the matrix representation of

F

with respect to

l{E}

is

M:=\left(fi,j\right),

then the transpose of

M

is the matrix representation with respect to

l{E}\prime

of

F\#.

Weak continuity and openness

Suppose that

\left\langleX,Y\right\rangle

and

\langleW,Z\rangle

are canonical pairings (so

Y\subseteqX\#

and

Z\subseteqW\#

) that are dual systems and let

F:X\toW

be a linear map. Then

F:X\toW

is weakly continuous if and only if it satisfies any of the following equivalent conditions:

F:(X,\sigma(X,Y))\to(W,\sigma(W,Z))

is continuous.

F\#(Z)\subseteqY

  1. the transpose of F,

{}tF:Z\toY,

with respect to

\left\langleX,Y\right\rangle

and

\langleW,Z\rangle

is well-defined. If

F

is weakly continuous then

{}tF::(Z,\sigma(Z,W))\to(Y,\sigma(Y,X))

will be continuous and furthermore,

{}ttF=F

A map

g:A\toB

between topological spaces is relatively open if

g:A\to\operatorname{Im}g

is an open mapping, where

\operatorname{Im}g

is the range of

g.

Suppose that

\langleX,Y\rangle

and

\langleW,Z\rangle

are dual systems and

F:X\toW

is a weakly continuous linear map. Then the following are equivalent:

F:(X,\sigma(X,Y))\to(W,\sigma(W,Z))

is relatively open.
  1. The range of

{}tF

is

\sigma(Y,X)

-closed in

Y

;

\operatorname{Im}{}tF=(\operatorname{ker}F)\perp

Furthermore,

F:X\toW

is injective (resp. bijective) if and only if

{}tF

is surjective (resp. bijective);

F:X\toW

is surjective if and only if

{}tF::(Z,\sigma(Z,W))\to(Y,\sigma(Y,X))

is relatively open and injective.
Transpose of a map between TVSs

The transpose of map between two TVSs is defined if and only if

F

is weakly continuous.

If

F:X\toY

is a linear map between two Hausdorff locally convex topological vector spaces, then:

F

is continuous then it is weakly continuous and

{}tF

is both Mackey continuous and strongly continuous.

F

is weakly continuous then it is both Mackey continuous and strongly continuous (defined below).

F

is weakly continuous then it is continuous if and only if

{}tF:\prime\toX\prime

maps equicontinuous subsets of

Y\prime

to equicontinuous subsets of

X\prime.

X

and

Y

are normed spaces then

F

is continuous if and only if it is weakly continuous, in which case

\|F\|=\left\|{}tF\right\|.

F

is continuous then

F:X\toY

is relatively open if and only if

F

is weakly relatively open (i.e.

F:\left(X,\sigma\left(X,X\prime\right)\right)\to\left(Y,\sigma\left(Y,Y\prime\right)\right)

is relatively open) and every equicontinuous subsets of

\operatorname{Im}{}tF={}tF\left(Y\prime\right)

is the image of some equicontinuous subsets of

Y\prime.

F

is continuous injection then

F:X\toY

is a TVS-embedding (or equivalently, a topological embedding) if and only if every equicontinuous subsets of

X\prime

is the image of some equicontinuous subsets of

Y\prime.

Metrizability and separability

Let

X

be a locally convex space with continuous dual space

X\prime

and let

K\subseteqX\prime.

  1. If

K

is equicontinuous or

\sigma\left(X\prime,X\right)

-compact, and if

D\subseteqX\prime

is such that

\operatorname{span}D

is dense in

X,

then the subspace topology that

K

inherits from

\left(X\prime,\sigma\left(X\prime,D\right)\right)

is identical to the subspace topology that

K

inherits from

\left(X\prime,\sigma\left(X\prime,X\right)\right).

  1. If

X

is separable and

K

is equicontinuous then

K,

when endowed with the subspace topology induced by

\left(X\prime,\sigma\left(X\prime,X\right)\right),

is metrizable.
  1. If

X

is separable and metrizable, then

\left(X\prime,\sigma\left(X\prime,X\right)\right)

is separable.
  1. If

X

is a normed space then

X

is separable if and only if the closed unit call the continuous dual space of

X

is metrizable when given the subspace topology induced by

\left(X\prime,\sigma\left(X\prime,X\right)\right).

  1. If

X

is a normed space whose continuous dual space is separable (when given the usual norm topology), then

X

is separable.

Polar topologies and topologies compatible with pairing

See main article: Polar topology.

Starting with only the weak topology, the use of polar sets produces a range of locally convex topologies. Such topologies are called polar topologies. The weak topology is the weakest topology of this range.

Throughout,

(X,Y,b)

will be a pairing over

K

and

l{G}

will be a non-empty collection of

\sigma(X,Y,b)

-bounded subsets of

X.

Polar topologies

See main article: Polar topology.

Given a collection

l{G}

of subsets of

X

, the polar topology on

Y

determined by

l{G}

(and

b

) or the

l{G}

-topology
on

Y

is the unique topological vector space (TVS) topology on

Y

for which\left\forms a subbasis of neighborhoods at the origin. When

Y

is endowed with this

l{G}

-topology then it is denoted by Y

l{G}

. Every polar topology is necessarily locally convex. When

l{G}

is a directed set with respect to subset inclusion (i.e. if for all

G,K\inl{G}

there exists some

K\inl{G}

such that

G\cupH\subseteqK

) then this neighborhood subbasis at 0 actually forms a neighborhood basis at 0.

The following table lists some of the more important polar topologies.

If

\Delta(X,Y,b)

denotes a polar topology on

Y

then

Y

endowed with this topology will be denoted by

Y\Delta(Y,,

Y\Delta(Y,

or simply

Y\Delta

(e.g. for

\sigma(Y,X,b)

we'd have

\Delta=\sigma

so that

Y\sigma(Y,,

Y\sigma(Y,

and

Y\sigma

all denote

Y

endowed with

\sigma(X,Y,b)

).

l{G}\subseteql{P}X


("topology of uniform convergence on ...")
Notation Name ("topology of...")Alternative name
finite subsets of

X


(or

\sigma(X,Y,b)

-closed disked hulls of finite subsets of

X

)

\sigma(X,Y,b)


s(X,Y,b)

pointwise/simple convergenceweak/weak* topology

\sigma(X,Y,b)

-compact disks

\tau(X,Y,b)

Mackey topology

\sigma(X,Y,b)

-compact convex subsets

\gamma(X,Y,b)

compact convex convergence

\sigma(X,Y,b)

-compact subsets
(or balanced

\sigma(X,Y,b)

-compact subsets)

c(X,Y,b)

compact convergence

\sigma(X,Y,b)

-bounded subsets

b(X,Y,b)


\beta(X,Y,b)

bounded convergencestrong topology
Strongest polar topology

Definitions involving polar topologies

Continuity

A linear map

F:X\toW

is Mackey continuous (with respect to

(X,Y,b)

and

(W,Z,c)

) if

F:(X,\tau(X,Y,b))\to(W,\tau(W,Z,c))

is continuous.

A linear map

F:X\toW

is strongly continuous (with respect to

(X,Y,b)

and

(W,Z,c)

) if

F:(X,\beta(X,Y,b))\to(W,\beta(W,Z,c))

is continuous.

Bounded subsets

A subset of

X

is weakly bounded (resp. Mackey bounded, strongly bounded) if it is bounded in

(X,\sigma(X,Y,b))

(resp. bounded in

(X,\tau(X,Y,b)),

bounded in

(X,\beta(X,Y,b))

).

Topologies compatible with a pair

If

(X,Y,b)

is a pairing over

K

and

l{T}

is a vector topology on

X

then

l{T}

is a topology of the pairing and that it is compatible (or consistent) with the pairing

(X,Y,b)

if it is locally convex and if the continuous dual space of

\left(X,l{T}\right)=b(,Y).

[8] If

X

distinguishes points of

Y

then by identifying

Y

as a vector subspace of

X

's algebraic dual, the defining condition becomes:

\left(X,l{T}\right)\prime=Y.

Some authors (e.g. [Trèves 2006] and [Schaefer 1999]) require that a topology of a pair also be Hausdorff, which it would have to be if

Y

distinguishes the points of

X

(which these authors assume).

The weak topology

\sigma(X,Y,b)

is compatible with the pairing

(X,Y,b)

(as was shown in the Weak representation theorem) and it is in fact the weakest such topology. There is a strongest topology compatible with this pairing and that is the Mackey topology. If

N

is a normed space that is not reflexive then the usual norm topology on its continuous dual space is compatible with the duality

\left(N\prime,N\right).

Mackey–Arens theorem

See main article: Mackey–Arens theorem, Mackey topology and Mackey space.

The following is one of the most important theorems in duality theory.

It follows that the Mackey topology

\tau(X,Y,b),

which recall is the polar topology generated by all

\sigma(X,Y,b)

-compact disks in

Y,

is the strongest locally convex topology on

X

that is compatible with the pairing

(X,Y,b).

A locally convex space whose given topology is identical to the Mackey topology is called a Mackey space. The following consequence of the above Mackey-Arens theorem is also called the Mackey-Arens theorem.

Mackey's theorem, barrels, and closed convex sets

If

X

is a TVS (over

\Reals

or

\Complex

) then a half-space is a set of the form

\{x\inX:f(x)\leqr\}

for some real

r

and some continuous linear functional

f

on

X.

The above theorem implies that the closed and convex subsets of a locally convex space depend on the continuous dual space. Consequently, the closed and convex subsets are the same in any topology compatible with duality;that is, if

l{T}

and

l{L}

are any locally convex topologies on

X

with the same continuous dual spaces, then a convex subset of

X

is closed in the

l{T}

topology if and only if it is closed in the

l{L}

topology. This implies that the

l{T}

-closure of any convex subset of

X

is equal to its

l{L}

-closure and that for any

l{T}

-closed disk

A

in

X,

A=A\circ\circ.

In particular, if

B

is a subset of

X

then

B

is a barrel in

(X,l{L})

if and only if it is a barrel in

(X,l{L}).

The following theorem shows that barrels (i.e. closed absorbing disks) are exactly the polars of weakly bounded subsets.

If

X

is a topological vector space, then:
  1. A closed absorbing and balanced subset

B

of

X

absorbs each convex compact subset of

X

(i.e. there exists a real

r>0

such that

rB

contains that set).
  1. If

X

is Hausdorff and locally convex then every barrel in

X

absorbs every convex bounded complete subset of

X.

All of this leads to Mackey's theorem, which is one of the central theorems in the theory of dual systems. In short, it states the bounded subsets are the same for any two Hausdorff locally convex topologies that are compatible with the same duality.

Space of finite sequences

Let

X

denote the space of all sequences of scalars

r\bull=\left(ri\right)

infty
i=1
such that

ri=0

for all sufficiently large

i.

Let

Y=X

and define a bilinear map

b:X x X\toK

by b\left(r_, s_\right) := \sum_^ r_i s_i. Then

\sigma(X,X,b)=\tau(X,X,b).

Moreover, a subset

T\subseteqX

is

\sigma(X,X,b)

-bounded (resp.

\beta(X,X,b)

-bounded) if and only if there exists a sequence

m\bull=\left(mi\right)

infty
i=1
of positive real numbers such that

\left|ti\right|\leqmi

for all

t\bull=\left(ti\right)

infty
i=1

\inT

and all indices

i

(resp. and

m\bull\inX

).

It follows that there are weakly bounded (that is,

\sigma(X,X,b)

-bounded) subsets of

X

that are not strongly bounded (that is, not

\beta(X,X,b)

-bounded).

Bibliography

External links

Notes and References

  1. A subset

    S

    of

    X

    is total if for all

    y\inY

    , b(s, y) = 0 \quad \text s \in S implies

    y=0

    .
  2. That

    b

    is linear in its first coordinate is obvious. Suppose

    c

    is a scalar. Then

    b(x,c\perpy)=b\left(x,\overline{c}y\right)=\langlex,\overline{c}y\rangle=c\langlex,y\rangle=cb(x,y),

    which shows that

    b

    is linear in its second coordinate.
  3. The weak topology on

    Y

    is the weakest TVS topology on

    Y

    making all maps

    b(x,):Y\toK

    continuous, as

    x

    ranges over

    R.

    The dual notation of

    (Y,\sigma(Y,R,b)),

    (Y,\sigma(Y,R)),

    or simply

    (Y,\sigma)

    may also be used to denote

    Y

    endowed with the weak topology

    \sigma(Y,R,b).

    If

    R

    is not clear from context then it should be assumed to be all of

    X,

    in which case it is simply called the weak topology on

    Y

    (induced by

    X

    ).
  4. If

    G:Z\toY

    is a linear map then

    G

    's transpose,

    {}tG:X\toW,

    is well-defined if and only if

    Z

    distinguishes points of

    W

    and

    b(X,G())\subseteqc(W,).

    In this case, for each

    x\inX,

    the defining condition for

    {}tG(x)

    is:

    c(x,G())=c\left({}tG(x),\right).

  5. If

    H:X\toZ

    is a linear map then

    H

    's transpose,

    {}tH:W\toY,

    is well-defined if and only if

    X

    distinguishes points of

    Y

    and

    c(W,H())\subseteqb(,Y).

    In this case, for each

    w\inW,

    the defining condition for

    {}tH(w)

    is:

    c(w,H())=b\left(,{}tH(w)\right).

  6. If

    H:W\toY

    is a linear map then

    H

    's transpose,

    {}tH:X\toQ,

    is well-defined if and only if

    W

    distinguishes points of

    Z

    and

    b(X,H())\subseteqc(,Z).

    In this case, for each

    x\inX,

    the defining condition for

    {}tH(x)

    is:

    c(x,H())=b\left(,{}tH(x)\right).

  7. If

    H:Y\toW

    is a linear map then

    H

    's transpose,

    {}tH:Z\toX,

    is well-defined if and only if

    Y

    distinguishes points of

    X

    and

    c(H(),Z)\subseteqb(X,).

    In this case, for each

    z\inZ,

    the defining condition for

    {}tH(z)

    is:

    c(H(),z)=b\left({}tH(z),\right)

  8. Of course, there is an analogous definition for topologies on

    Y

    to be "compatible it a pairing" but this article will only deal with topologies on

    X.