Dini test explained

In mathematics, the Dini and Dini–Lipschitz tests are highly precise tests that can be used to prove that the Fourier series of a function converges at a given point. These tests are named after Ulisse Dini and Rudolf Lipschitz.

Definition

Let be a function on [0,2{{pi}}], let be some point and let be a positive number. We define the local modulus of continuity at the point by

\left.\right.\omegaf(\delta;t)=max|\varepsilon||f(t)-f(t+\varepsilon)|

Notice that we consider here to be a periodic function, e.g. if and is negative then we define .

The global modulus of continuity (or simply the modulus of continuity) is defined by

\omegaf(\delta)=maxt\omegaf(\delta;t)

With these definitions we may state the main results:

Theorem (Dini's test): Assume a function satisfies at a point that

\pi
\int
0
1
\delta

\omegaf(\delta;t)d\delta<infty.

Then the Fourier series of converges at to .

For example, the theorem holds with but does not hold with .

Theorem (the Dini–Lipschitz test): Assume a function satisfies

\omega
f(\delta)=o\left(log1
\delta

\right)-1.

Then the Fourier series of converges uniformly to .

In particular, any function that obeys a Hölder condition satisfies the Dini–Lipschitz test.

Precision

Both tests are the best of their kind. For the Dini-Lipschitz test, it is possible to construct a function with its modulus of continuity satisfying the test with instead of , i.e.

\omega
f(\delta)=O\left(log1
\delta

\right)-1.

and the Fourier series of diverges. For the Dini test, the statement of precision is slightly longer: it says that for any function Ω such that

\pi
\int
0
1
\delta

\Omega(\delta)d\delta=infty

there exists a function such that

\omegaf(\delta;0)<\Omega(\delta)

and the Fourier series of diverges at 0.

See also