Dichloro(1,5-cyclooctadiene)palladium explained

Dichloro(1,5-cyclooctadiene)palladium is the organopalladium compound with the formula PdCl2(C8H12) where C8H12 is cycloocta-1,5-diene (cod) or abbreviated PdCl2(cod). It is a yellow solid that is soluble in chloroform.[1] According to X-ray crystallography, the Pd center is square planar.[2] This complex can be synthesized by reaction of tetrachloropalladate in hydrochloric acid with cycloocta-1,5-diene.[3]

See also

References

  1. Encyclopedia: Dichloro(1,5-cyclooctadiene)palladium(II). Shomir Ghosh. Xiang Wang. Anil Guram . Encyclopedia of Reagents for Organic Synthesis . 2009. 10.1002/047084289X.rd113.pub2. 978-0471936237 .
  2. Acta Crystallogr. C. 1993. 49. 1766–1767. The Pbca polymorph of dichloro(η4-1,5-cyclooctadiene)palladium(II). R. Kumar. A. W. Maverick. F. R. Fronczek. J. R. Doyle. N. C. Baenziger. M. A. M. Howells. 10 . 10.1107/S0108270193003889. free. 1993AcCrC..49.1766K .
  3. Book: 1972. 13. 47–55. Cyclic Diolefin Complexes of Platinum and Palladium. Drew, D.. Doyle, J. R.. Shaver, A. G. . Inorganic Syntheses . 10.1002/9780470132449.ch11. 978-0-470-13172-5 .

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