Derived tensor product explained

In algebra, given a differential graded algebra A over a commutative ring R, the derived tensor product functor is

-

bf{L
A
} - : D(\mathsf_A) \times D(_A \mathsf) \to D(_R \mathsf)where

MA

and

{}AM

are the categories of right A-modules and left A-modules and D refers to the homotopy category (i.e., derived category).[1] By definition, it is the left derived functor of the tensor product functor

-A-:MA x {}AM\to{}RM

.

Derived tensor product in derived ring theory

If R is an ordinary ring and M, N right and left modules over it, then, regarding them as discrete spectra, one can form the smash product of them:

M

L
R

N

whose i-th homotopy is the i-th Tor:

\pii(M

L
R

N)=

R
\operatorname{Tor}
i(M,

N)

.It is called the derived tensor product of M and N. In particular,

\pi0(M

L
R

N)

is the usual tensor product of modules M and N over R.

Geometrically, the derived tensor product corresponds to the intersection product (of derived schemes).

Example: Let R be a simplicial commutative ring, Q(R) → R be a cofibrant replacement, and

1
\Omega
Q(R)
be the module of Kähler differentials. Then

LR=

1
\Omega
Q(R)
L
Q(R)

R

is an R-module called the cotangent complex of R. It is functorial in R: each RS gives rise to

LR\toLS

. Then, for each RS, there is the cofiber sequence of S-modules

LS/R\toLR

L
R

S\toLS.

The cofiber

LS/R

is called the relative cotangent complex.

See also

References

Notes and References

  1. Hinich. Vladimir. 1997-02-11. Homological algebra of homotopy algebras. q-alg/9702015.